Complete the data table by performing the following calculations on a separate sheet: Row 2: Determine the molar mass of each compound (check the periodic table…) Row 3: Determine the amount of mol you scooped for each sample grams (row 1) x 1 mol = mol of compound Molar mass (row 2) Row 4: Determine the number of particles (molecules or formula units) for each compound # of moles (row 3) x 6.02 x 1023 particles = # of particles 1 mol Row 5: Determine the number of atoms in each formula (add all
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Nevertheless‚ the similarity of odor to different compounds can be a source of error. For instance‚ the way humans detect odors is due to the presence of seven different receptors in the olfactory area. When smelling different compounds‚ some odor chemicals bind with olfactory receptors easily‚ and other odors need more time to bind with receptors. Therefore‚ after smelling different compounds one after the other‚ the receptors can be altered and associate the previous
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Interpret‚ predict‚ and write formulas for ionic and molecular compounds 3. Which of the following statements are correct? 1.|Metals generally lose electrons to become cations.| 2.|Nonmetals generally gain electrons to become anions.| 3.|Group 2A metals form ions with a 2+ charge.| a.|1 only| b.|2 only| c.|3 only| d.|1‚2‚ and 3| ANS: D OBJ: Goal #3.1: Interpret‚ predict‚ and write formulas for ionic and molecular compounds 5. What charge is most commonly observed for an oxide
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Emission Spectra & Flame Tests Intro The emission spectrum is used in modern chemistry to help further studies of wavelengths and the spectrum. When a metal in a compound reacts in a flame and produces a color‚ it helps to show the strongest color in the emission spectrum. The purpose of performing these operations on the flame was to see how different metals would react. Using a spectroscope‚ it is possible to observe the line emission spectrum produced by sunlight‚ artificial light‚ and
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CODE: CHM 121 ‚ UNIT: 2.0 . INTRODUCTORY AND IMPORTANCE OF ORGANIC CHEMISTRY Organic chemistry is the study of the compounds of carbon. Carbon compounds are far more numerous than those of other elements because carbon are able to bond together to form a wide range of chains and rings. The subject is named organic chemistry because living organisms are composed of carbon compounds. Organic chemistry could be regarded as the chemistry of life. Organic Chemistry is of great medical‚ economic
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1023 molecules) of any chemical compounds. Molar masses of common chemical compounds that you might find in the chemistry laboratory can range between 18 grams/mole for compounds like water to hundreds of grams per mole for more complex chemical compounds.The lightest possible chemical that one can have under normal conditions is hydrogen gas‚ or H2. There is no limit to how heavy a chemical compound can be - it is not uncommon for macromolecules (large organic or bioorganic compounds such as DNA) to weigh
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1)Calculate the amount of your compound interest investment after 10 years. Remember that you are starting with $7‚500. $10‚642.83 work: A=7500(1+3.5%/365)^365x10 = 7500(1+0.00009589)^365x10 = 7500(1.00009589)^3650 = 7500(1.419041609) = 10‚642.83 2)Calculate the amount of your simple interest investment after 10 years. Remember to use the same rate and compounding as in #1. $2‚625 work: 7500x.035x10 = 7500x.35=2625 3)Create a graph that shows the growth of your compound interest and simple interest
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single reference compound. The composition of the unknown mixture and two single unknowns were determined by spotting the reference compounds and the unknown compounds on two TLC plates. Placed them in a developing chamber that contained 0.5% acetic acid in ethyl acetate solvent and observed the TLC plates under UV light after the TLC plates were taken out of the developing chamber. The known reference compounds portrayed spots and calculated Rf values that the unknown compounds matched to. This
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the lesson‚ students are expected to: Write the IUPAC name of certain alcohol compounds; SUBJECT MATTER Topic: Nomenclature of Carboxylic Acid References: General‚ Organic and Biochemistry by Denniston‚ Topping and Caret. Page 283-289. Fundamentals of General‚ Organic and Biochemistry by John R. Holum. Page 418-425. Materials: Ball and stick model of compounds Overhead projector Textbooks Pictures of certain compounds Skills: Describing‚ Naming‚ TEACHING ACTIVITY Teacher’s Activity Student’s
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______________________________________________ Hydrocarbons are organic compounds containing only hydrogen and carbons and further divided in major types. Hydrocarbons react differently in reagents. The basis of determining an unknown hydrocarbon is due to the differences in reactions of hydrocarbons. An unknown compound is determined using tests. The unknown gives a positive result in nitration test and gives no brown precipitate in oxidation test. The unknown is an aromatic and non-alkylated compound. _______________________________________________
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