word as used in your textbook? A. B. C. D. E. air tap water sea water water toothpaste 2. Select the best statement. A. B. C. D. E. Physical changes may be reversed by changing the temperature. Physical changes alter the composition of the substances involved. Physical properties are not valid characteristics for identifying a substance. Physical properties are mostly extensive in nature. Physical changes are usually accompanied by chemical changes. 3. Select the best
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Determining the composition of pennies with redox reactions Introduction: The understanding of oxidation and reduction must be clear to carry out this lab. With the understanding of these concepts we can calculate or hypothesize for the properties of each element or compound. Oxidation involves the gain of electrons of hydrogen or the loss of oxygen or decrease in oxidation state. If zinc completely reacts with HCL‚ then the theoretical yield of copper should be equivalent to the actual yield
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Determination of % Composition of Pennies Using Redox and Double Displacement (Precipitation) Reactions Introduction: Oxidation involves the gain of electrons of hydrogen or the loss of oxygen or decrease in oxidation state. If zinc completely reacts with HCL‚ then the theoretical yield of copper should be equivalent to the actual yield. Purpose: In this lab‚ we will determine the percent composition of a modern (post-1982) penny by using a strong acid to react and dissolve the zinc
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Observations | Reaction Type | Complete and Balance | 1. When heated in oxygen‚ magnesium gives off a bright white flame. | combination reaction | 2Mg + O2-----> 2MgO | 2. Bubbling and fizzing occurs; the zinc appears to “dissolve” and what appears to be “steam” comes off out of container. | single-displacement reaction | Zn + 2 HCl (aq) --> ZnCl2(aq) + H2(g) | 3. Black smoke occurs | decomposition reactions | 2 (H2O2)(aq) MnO2 2 (H2O) + (O2) | 4. reddish-brown deposit
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chemical reactions using physical and chemical properties and balanced chemical equations. There are four different types of chemical reactions decomposition reactions‚ single displacement reactions‚ synthesis reactions‚ and double displacement reactions. A decomposition reaction happens when a compound breaks into two or more elements or compounds. Generally‚ for decomposition reactions heat‚ energy‚ light or electricity is needed to separate the compound. In a single displacement reaction‚ a single
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chloride and they form a solid precipitate. Then we poured it a funnel with a filter paper to get the solid precipitate. Purpose ● The purposed of the lab is to lets us student know if we know how calculate the percent yield of a double displacement reaction while using the grams that we get from our lab. Objectives ● We need to know the solid precipitate that had been formed in the
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A double displacement reaction is a type of chemical reaction in which two compounds react in order to create two new chemicals. The two cations and anions switch places with each other which forms two new compounds. As an example AB+CC can switch to AD+CB. Both sides of these equations must balance out in order to be neutral. So any pairs of compounds (such as A+B) must have a total balanced charge. In this example A could have a charge of positive 2 (+2) and B could have a charge of negative
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Qualitative Observations of Double Displacement Reactions Lab Table 1.0 Qualitative Observation of Products Formed |Balanced Chemical Equations |Qualitative Observations | |BaCl2 (aq) + 2NaOH (aq)( BaOH2(aq) + 2NaCl(s) |An aqueous solution formed | | |Precipitate
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created. In chemical analysis‚ the amount of an object is determined using a process called titration. According to Petrucci et al.‚ titration is a reaction carried out by the carefully controlled addition of one solution to another. It has several types like acid-base titrations and redox titrations. This experiment focuses on the latter type‚ the redox titration. A redox titration is based on an oxidation-reduction reaction between analyte and titrant (Harris‚2009). It involves the transfer
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Introduction The purpose of this lab was to find the theoretical and experimental percentage yields of the double displacement reaction between the solutions Lead (II) Nitrate (PbNO3) and Potassium Iodide (KI). It is important to obtain amounts of Lead (II) Nitrate and Potassium Iodide as close to 1.44g as possible. This reaction creates Lead (II) Iodide and Potassium Nitrate. The precipitate during this reaction is Lead (II) Iodide. The balanced equation is Pb(NO3)2 + 2KI= PbI2 + 2KNO3. In this lab the Lead
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