Determination of Cations and Anions through Elimination and Confirmation Tests By: Symantha Resendiz Introduction A topic of great importance to all scientists is the identification of compounds‚ which is relevant in all aspects of their work in some way shape or form. Weather it may be determining what is causing sickness or what is polluting the air‚ it is very prevalent in the science world. In project 2‚ identification of cations and anions was preformed through a series of confirmation
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used to electroplate objects. This is useful for coating a cheaper metal with a more expensive one‚ such as copper or silver. How it works The negative electrode should be the object that is to be electroplated The positive electrode should be the metal that you want to coat the object with The electrolyte should be a solution of the coating metal‚ such as its metal nitrate or sulfate Here are two examples. Electroplating with silver The object to be plated‚ such as a metal spoon‚ is connected
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Elements‚ Mixtures and Compounds An element is a pure substance made of one type of particle (atom). Particles can join up with other particles of the same type to form molecules. Examples: Hydrogen = H2 . This means there are two atoms of hydrogen joined together to form a molecule of hydrogen gas. Oxygen = O2‚ Nitrogen is H2‚ Chlorine is Cl2. A compound is a pure substance of two or more elements chemically combined together in a set ratio. Example: Water = H20 this means there are always
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........................................................................ 15 Project C • Properties of a Liquid Substance.......................................................................................... 23 Project D • Inorganic Forms of Copper ................................................................................................... 29 Project E • Analysis of Lead in Soil......................................................................................................... 35
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Compound Katie Sanders Science Block 3 February 29‚ 2012 Title: Analysis of a Hydrated Crystalline Compound Purpose: The purpose of our experiment was to determine the amount of water in copper sulfate pentahydrate expressed as a percent. Hypothesis: I think that bluestone crystals are 20% water‚ because it’s called pentahydrate (penta means five) and 1/5 of 100 (since it’s expressed as a percent) is 20‚ so I think bluestone crystals are
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Magnesium‚ Zinc‚ Iron‚ Lead and Copper. In descending order. B. Before Copper in descending order. C. If a reaction takes place then the metal displaces the original metal. D. 1. 0 2. +2 3. -1 4. 0 5. +2 6. -1 7. and 8. Iron is the reducing agent so it is oxidized and Nickel is the oxidizing agent so it is reduced. Table: Substances Observations Magnesium and Sodium Sulfate Bubbles Zinc and Magnesium Sulfate No reaction Lead and Zinc
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drops of the following solutions into seven wells in rows A through E: cobalt (II) nitrate‚ copper (II) nitrate‚ iron (III) nitrate‚ barium nitrate‚ and nickel (II) nitrate. Afterward‚ two drops of each of sodium phosphate‚ sodium iodide‚ sodium sulfate‚ sodium chloride‚ sodium bicarbonate‚ sodium carbonate and sodium hydroxide were added to the five vertical wells under columns 1-7. |cobalt(II)nitrate|copper(II)nitrate|iron(III)nitrate|barium nitrate|nickel(II)nitrate| sodium phosphate|Precipitated
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Cobalt (II) Nitrate‚ 0.1 M - 2 mL in Pipet1 Copper (II) Nitrate‚ 0.1 M - 2 mL in Pipet‚ 1 Iron (III) Nitrate‚ 0.1 M - 2.5 mL in Pipet‚ 1 Nickel (II) Nitrate‚ 0.1 M - 2 mL in Pipet‚ 1 Sodium Bicarbonate‚ 0.1 M - 2 mL in‚ Pipet‚ 1 Sodium Carbonate‚ 0.1 M - 2 mL in Pipet‚ 1 Sodium Chloride‚ 0.1 M - 2.5 mL in Pipet‚ 1 Sodium Hydroxide‚ 0.1 M - 2 mL in Pipet‚ 1 Sodium Iodide‚ 0.1 M - 2.5 mL in Pipet‚ 1 Sodium Phosphate‚ 0.1 M - 2 mL in Pipet‚1 Sodium Sulfate‚ 0.1 M - 2.5 mL in Pipet CAUTION! Sodium hydroxide
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remain after the reaction comes to an end. An understanding of chemical equilibrium and how it can be manipulated is essential for anyone involved in Chemistry and its applications. Iron-Silver Equilibrium In the first phase of the experiment‚ iron sulfate was mixed with silver nitrate‚ and the reaction produced solid silver and iron nitrate‚ which is formally written as Fe2+ (aq) + Ag+ (aq) ⇄ Ag (s) + Fe3+ (aq) It has a net equation of: Fe2+ (aq) + Ag+(aq) ↔ Fe3+(aq) + Ag(s) The mixture was then
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6.02 x 1023 atoms Ca 1 40.01 g Ca 1 mol Ca atoms 3. What is the mass of 6.20 moles of potassium iodide? Mol( grams 4. How many moles are contained in 84.2g of potassium sulfate? 5. Calculate the number of molecules in 3.34 moles of carbon dioxide. 6. What is the mass of 3.01 x 1023 atoms of sulfur? 7. What is the mass of 2.41 x 1024 molecules of water? 8. What is the formula mass (molar
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