investigate the rate of reaction between Calcium Carbonate and Hydrochloric Acid. Just from looking at the aim of the investigation I already know that a salt would be formed because a carbonate with an acid forms a salt. In this investigation the substance that is formed is Calcium Chloride‚ Water and Carbon Dioxide. The symbol equation for this is: CaCo3  Ca2+ + Co32- Hcl  H+ + Cl- Add these all together to get CaCO3(s) + 2H+(aq) --> Ca++(aq) + H2O + CO2(g) The rate of reaction is just
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Biology Enzyme Catalase Investigation Aim: The aim of this investigation is to study and observe whether or not the concentration of hydrogen peroxide (varying from 10 – 30 millilitres) affects the rate of reaction. Hypothesis: With the increase of the concentration of Hydrogen Peroxide 3% substrate‚ I prediction that the rate of pressure increase will begin to amplify. The pressure is bound to increase because the catalase quickly reacts with the hydrogen peroxide; this is why the more substrate
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Effects of Pepsin VS. Trypsin in The Digestion of Protein Introduction As food is mechanically and chemically digested through our oral cavity then passes through our pharynx and down our esophagus‚ our food then enters the stomach. The stomach‚ being the main organ for storage‚ also helps with breaking down our food‚ but in order to accomplish that our pancreas helps by excreting an inactive digestive enzyme called pepsinogen. Pepsinogen is the inactive form of the more familiar enzyme called
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Abstract: After reviewing the basics of enzymes and catalysis‚ we take a dive into the wonderful world of catalase. Beginning with establishing a base line of just how much hydrogen peroxide there is in 5.0mL of the reacted solution; to figuring out exactly how much actually reacted after 300 seconds of catalyzed reaction. Follow the experiment from the beginning steps right to the end as you see where the students went wrong‚ interpretation of the results‚ and great answers to work sheet
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Hypothesis: If I increase the concentration of NaOH from 0.5M to 1M‚ then I will see the temperature slope increase in the reaction with an increased concentration because with an increase of moles‚ the particles will be colliding more often‚ therefore increasing the probability that the proper energy and alignment will occur to create more collisions in the same amount of time. Methods: List of Materials: • 110 mL of NaOH at 1 M (10 mL per run) • 110 mL of NaOH at 0.5 M (10 mL per run) • 220 mL
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Level 2 2010/11 ‘Seller concentration levels are of interest on both theoretical and public policy grounds’. Discuss. Market structure plays an important role in any industry. Examining the market structure is essential for firms to perform well and behave rationally. The key characteristics of market structure include the number and size of firms‚ the existence and height barriers to entry and exit‚ and the degree of product differentiation. Seller concentration refers to the number and level
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Lambda DNA with restriction enzymes. Aim: The objectives of this experiment are: Become more familiar with using micropipettes. Use restriction enzymes to cut DNA at specific sites. Use Ligase to rejoin some of the cut/separated DNA fragments. Learn to separate DNA using electrophoresis. Introduction: Restriction enzymes are proteins which cut dsDNA at specific regions depending on the enzyme used‚ determined by the nucleotide sequence of the DNA‚ i.e. each enzyme recognises specific nucleic
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Investigate Concentration of Substrate on Catalase enzyme 1. Aim/Prediction. Aim of this experiment is to investigate concentration of substrate on catalase enzyme‚ as well to see how they work in different concentrations of hydrogen peroxide (H2O2). Prediction would be‚ that the filter paper discs that were used‚ will rise up to the surface in a time in the tube of different concentration of hydrogen peroxide. And in different concentrations the time will be different. As higher the concentration would
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Given the evidence‚ it can be determined that a reaction will occur when reactants have a kinetic energy greater than the activation energy‚ this is a theory of collision theory. For example‚ in the first experiment‚ the test tube filled with 10 mL of 3% hydrogen peroxide and had scoop of manganese dioxide‚ had a greater reaction than the other test tube. Which simply contained 10 mL of 3% hydrogen peroxide. The factor that affected the reaction rate was that the manganese was seen as a catalyst.
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find the rate equation of the reaction of hydrogen peroxide and iodide ions. This will be achieved by using an iodine clock method and colorimetric analysis. 2. Draw a graph of rate against concentration for each reactant (Hydrogen peroxide‚ potassium iodide and H+ ions). 3. Finding the order for each reactant 4. Finding the rate-determining step. 5. Proposing a mechanism for the reaction. 6. Using Arrhenius’ equation to find the activation enthalpy. Background The basic reaction for this
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