2 Results..................................................................................................................3 Calculations..........................................................................................................5 Error Analysis.......................................................................................................6 Graphical Representation....................................................................................7 Discussion and Conclusion
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Problem 1 In addition to determining sample size‚ ACL can also select a random sample for you. Draw a sample of Accounts Receivable (AR) transactions from the Roger Company AR table assuming the confidence is 95‚ the upper error limit is 9 percent‚ and the expected error rate is 5 percent. 1. Open the Roger_Company_AR table 2. Select Sampling >> Sample Records and the Sample window appears 3. Make sure Record is the chosen Sample Type 4. Under Sample Parameters‚ click on the Random
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The standard error of the mean is the standard deviation of the sampling distribution. 4. Assuming no measurement error‚ the reliability of an estimate of a population parameter can be assessed in terms of its standard error. 5. The standard error of the mean can be estimated by using the sample standard deviation‚ s‚ as an estimator of . 6. z values calculate the area under the sampling distribution. 7. When the sample size is over 10% of the population size‚ the standard error formulas overestimate
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group‚ with each student’s name and student number included in the document. This assignment has a total of 40 marks available and may contribute up to 10% of your final mark in this subject. Question 1 (5 marks) Recall the concept of the sampling error from the first and second weeks of semester. In lectures in Week 6‚ we considered an example in which Optus was estimating the mean telephone expenditure of a household. In the context of that example‚ answer each of the following questions. Where calculations
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practices in small businesses of Victoria and Western Region of Melbourne. The following report will include the research objectives‚ various methods of data collection‚ survey method‚ the sample size and sampling method‚ the research process and common errors as well as the designed questionnaire. By discussing these data collection methods and design the questionnaire‚ it would help the academics to get a close look at the preparation of investigations and involve more individuals participating in our
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96/30)=13.7 s-1 2. Calculate the theoretical speed of the object: Trial 1: Fc = W= 0.2kg*9.8N kg-1= 1.96N → ac= Fc/m=254. 5m s-2 Vt= √ac*r= 14.3m s-1 3. Calculate the percentage error in magnitude of the speed Trial 1: % Error= (Vt-V)/V = 4.38% Trial Measured Speed (m s-1) Theoretical Speed (m s-1) % Error Centripetal Force (N) 1 13.7 14.3 4.38% 1.96 2
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Finding the Activation Energy of the reaction between Hydrochloric Acid and Sodium Thiosulfate The equation for the reaction is: S2O32- (aq) + 2H+(aq) ⋄ SO2 (g) + S(s) + H2O (l) Equipment - 2 boiling tubes - 400 cm3 beakers - Marker pen - Stand and clamp - Timer - Bunsen burner‚ tripod and gauze - 0 – 100 oC thermometer - 2 x 10 cm3 measuring cylinders - Access to a fume cupboard. Method 1. Label two boiling tubes A and B. Mark a dark spot on the side of a 400cm3 beaker‚ then ½ fill
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Our Research Proposal Topic:Newspaper reading habits 1) Problem Definition: -What is the purpose of the study? Our purpose is to find out the number of students who prefer newspapers in our college campus. -How much is already known? So far there is no data collected on this topic. But the reason behind choosing this topic is to know how many people prefer newspapers over any other source of news related information such as magazines‚ journals‚ internet
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Deviation 0.220 0.220 0.207 0.206 Level of Significance (alpha) 0.010 0.010 0.010 0.010 Critical Value (lower tail) -2.576 -2.576 -2.576 -2.576 Critical Value (upper tail) 2.576 2.576 2.576 2.576 Hypothesized value 12 12 12 12 Standard Error 0.040 0.040 0.038 0.038 Test Statistic -1.027 0.713 -2.935 2.161 p-value 0.304 0.476 0.003 0.031 Only sample 3 leads to the rejection of the hypothesis H0: µ = 12. Thus‚ corrective action is warranted for sample 3. The other samples indicate
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control purposes. Class Interval = {u – [Z*Error]‚ u + [Z*Error]} = {12 – [2.58*0.038]‚ 12 + [2.58*0.038]} = {11.901‚ 12.098} Sample 1 Sample 2 Sample 3 Sample 4 SAMPLE MEAN 11.958 12.028 11.889 12.081 From the data it was found that the mean of sample 3 does not fall with class interval and therefore corrective action must be taken on it. 4) Discuss the implications of changing the level of significance to a larger value. What mistakes or error could increase if the level of significance
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