Chapter 11 Questions to be graded: 5. Were the experimental and control groups similar in their type of feeding? Provide a rationale for your answer. Answer: Yes the experimental and control groups are similar in their feeding type because 40.6% in the experimental group decided to breast-feed‚ and 41.7% in the control group decided to breast-feed‚ that’s only 1.1% difference. 53.1% of the experimental group bottle-fed while 50.0% of the control group bottle-fed‚ a small 3.1% difference. Finally
Premium Arithmetic mean Standard deviation Median
Name: Suma Pole Class: 362V (Work book Exercises 11 and 16) 06/12/15 Exercise 11: Using Statistics to Describe a Study sample. 1. What demographic variables were measured at the interval level of measurements? Age‚ Income‚ Length of labor‚ Return to work and number of hours working per week. 2. What statistics were used to describe the length of labor in this study? Mean and standard deviation were used to describe the length of labor. These were appropriate since mean and standard deviation can
Premium Arithmetic mean Standard deviation
Comparison and Contrast of Andy Grove and Michael Dell Contributions to the Field Andy Grove and Michael Dell made major contribution to the field of technology. Not speaking to product contributions‚ but the effective management tools‚ leadership‚ poise and strategic thinking are perhaps their most impressive contributions to the field. Andy Grove brought definition to the words “crises management‚” and has forever changed
Premium Psychology Management United States
Practice Problems 1-KEY 1. The closing stock price of Ahmadi‚ Inc. for a sample of 10 trading days is shown below. Day Stock Price 1 84 2 87 3 84 4 88 5 85 6 90 7 91 8 83 9 82 10 86 For the above sample‚ compute the following measures. a. b. c. The mean = ∑X/n = 860/10 = 86 The median = (85+86)/2 = 85.5 The variance = ∑ X - X 2/ n-1 = {(84-86)2 + (87-86)2 + (84-86)2 + (88-86)2 + (85-86)2 + (90-86)2 + (91-86)2 + (83The standard deviation = √8.89 = 2.98 The coefficient of variation = 2.98/86 * 100%
Premium Standard deviation Arithmetic mean Normal distribution
(January 2001)‚ 45% of senior women (i.e.‚ women over the age of 65) use herbal therapies to prevent or treat health problems. Also a senior women who use herbal therapies use an average of 2.5 herbal products in a year. a. Give the null hypothesis for testing the first claim by the journal. b. Give the null hypotheses for testing the second claim by the journal. (a) Ho: p = .45 (b) Ho: p = 2.5 8.13 (2 points) DNA-reading tool for quick identification for species. A biologist an a zoologist
Premium Statistical hypothesis testing Null hypothesis Type I and type II errors
Luis Canostriuino Pulido from Columbia is a nursing student attending Inlet Grove Community High school. But unlike most of us who wake up at 5:30 or 6 and take a bus or car to school‚ he wakes up at 4am catches a bus‚ train then another bus to get to school and then does the same to get home every day. Motivated by his mother‚ the 14-year-old left his home country and all of his family with the exception of his mom‚ in search of a better Future. “It’s been a little bit weird and scary because
Premium High school School Family
PEARSON’S PRODUCT-MOMENT CORRELATION COEFFICIENT ANSWERS TO EXERCISE 23 Question 1 The r value for the relationship between Hamstring strength index 60o and the Shuttle run test is -0.149. This r value shows a weak correlation between the two variables‚ as it is less than the 0.3 threshold for significance. Therefore‚ the r value is not significant. Question 2 Between r=1.00 and r=-1.00‚ there is no difference in terms of strength. Both values are on the extreme ends of the spectrum and signify
Premium Statistics Statistical significance Statistical hypothesis testing
what variable in this study? Is this value significant? Provide a rationale for your answer. t = -3.15 describes mental health in this study. This is significant because mental health plays a big role in the outcome of MI patients. 3. Is t = −1.99 significant? Provide a rationale for your answer. Discuss the meaning of this result in this study. t = -1.99 describes health functioning. This is very significant. It is used to describe decline from illness or disease. It could solely explain
Premium Null hypothesis Statistical hypothesis testing Hypothesis
1-2 Test 100 points In order to receive full credit‚ please show all work for every problem. You are welcome to use your calculator‚ book and notes‚ but please take this test on your own. 1. In your own words‚ explain what parameters and statistics are and what the difference is between them. Give an example to clarify. (10 points) 2. According to Consumer Reports‚ a random sample of 35 new cars gave an average of 21.1 mpg. What is the variable being studied? What is
Premium Frequency distribution Scientific method Frequency
Elk grove needs a clean source of energy. In my opinion biomass would be a good energy source for Elk Grove. Biomass is an organic and renewable material that comes from plants and animals.Contains stored energy from the sun. Biomass can be converted to other usable forms of energy like methane gas or transportation fuels like ethanol and biodiesel. Biomass is a good resource because it’s renewable and it’s a clean energy source. Also biomass can be reproduced over a relatively short period
Premium Fossil fuel Petroleum Natural gas