Samuel Haleem Assignment 1 1. The Chi Square (c2) test: Phenotype Expected Ratio Expected Counts (Ei) Observed Counts (Oi) Deviation (di) = (Ei-Oi) di2 = (Ei-OI)2 di2/Ei Purple 3 429 430 -1 1 0.002 Yellow 1 143 142 1 1 0.007 a. c2 = S (di2/Ei) = 0.009 b. Results indicate that the null hypothesis supported. 2. Human Phenotypes: a. The data: Trait Dominant Phenotype Recessive Phenotype Ear Lobe 12 7 Pigment Distribution 1 18 Hairline 8 11 Little Finger 12 7 Tongue Roller 16 3 b. Do the ratios of the
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How does variation play a role in population’s phenotypes? Phenotypes are characteristics of an organism which we notice through different physical features such as hair color‚ body weight‚ capabilities‚ the way someone might behave‚ etc. Variation is the differences in an individual in the population‚ Variation plays an important role in phenotype because it helps us understand life.‚ we see a variety of attributes everywhere each one mirrors an alternative important reason. For example‚ a bear
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THE VICTORIA SCHOOL SANTIAGO JACOME LAB REPORT PTC BIOLOGY SL AIM: The aim of this lab is to analyze the genotype differences of classmates that are able to taste PTC‚ Thiourea and Sodium benzoate and determine the phenotypes found. Testing the ability to taste PTC has been a mainstay activity in human genetics for generations of teacher and students. The ability to taste PTC is inherited. Traditionally this is presented as a case of simple Mendelian inheritance involving a dominant allele for tasting
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Ethanol sensitivity in Drosophila melanogaster based on genotype Alexa Shumate Department of Biology Randolph-Macon College Ashland‚ Virginia Introduction With a better understanding of the genes and behaviors associated with ethanol sensitivity‚ there will be new treatments available for alcohol dependence. The main problem in determining what causes dependence to alcohol is whether it is an environmental factor or if it is the genes associated with ethanol
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Module 01 Lab Worksheet: General Review Introduction This week’s lab will focus on reviewing the concepts of anatomical terminology‚ metric conversion and genetics‚ specifically the concept of dominant and recessive alleles in a human pedigree. Objectives Objectives for this week’s lab include: 1) Review anatomical terminology‚ 2) Demonstrate metric conversion knowledge‚ and 3) Review the concepts of genetic inheritance and demonstrate knowledge of the inheritance patterns of dominant and recessive
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curved wings in Drosophila. Results Part A Cross A (wildtype females X curly males) Male Female Wild type 1 2 Curly wing 0 1 Table 1. The number of the phenotypes and sex of offspring of the Cross A Cross B (curly females X curly males) Male Female Wild type 2 1 Curly wing 3 0 Table 2. The number of the phenotypes and sex of offspring of the Cross A 2. The cross A and B look like sex-linked traits‚ but it is not sex-linked dominant curly wing mutation and sex-linked recessive
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rules of probability apply to genetics. T 2. If an individual has a Gg genotype‚ half of his gametes should have the G allele‚ and the other half should have the g allele. F 3. A Punnett square is a chart that allows you to easily determine the expected genotypes in the offspring of two parents. (expected percents) T 4. In a cross between two homozygous dominant individuals‚ 25% of the offspring may have the recessive phenotype. F 5. A parent cell makes gametes through the process of mitosis. T 6
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i. Allele ii. Genotype b. Dominant alleles are represented by: i. an upper case letter ii. a lower case letter iii. it does not matter what type of letter is used c. In fruit flies‚ gray body color is dominant over black body color. Using the letter G to represent body color‚ what is the genotype of a heterozygous gray bodied fly? i. GG ii. gg iii. Gg iv. GGgg d. All of the offspring of two gray bodied flys are also gray. What can you conclude about the genotypes of the parent flies
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homozygous and heterozygous genotypes and phenotypes. Homozygous Genotype Phenotype Heterozygous 4. The dominant allele for smooth pod shape in peas is S. The recessive allele for constricted pod shape is s. In the Punnett square‚ show the result of crossing two heterozygous parents (Ss). Write the genotype and the phenotype of each type of offspring in the space provided. S S s s Genotype: Genotype: Phenotype: Phenotype: Genotype: Genotype: Phenotype: Phenotype: For Questions 5–9‚ refer
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markers and phenotypes of weedy rice plants (seed awn and pericarp colour).Besides‚ this practical was aimed to understand chi-square analysis to test the genetic association. Understanding the concept of linkage disequilibrium was also one of the objectives of this practical. Chi-square statistical analysis was used to identify the association between markers and phenotypes of weedy rice plants tested. Results: For Awn and Awnless: Table 1.0: Chi-square calculation of phenotype I (awn-awnless)
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