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    Chemistry Assignment

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    contains four sections‚ SECTION A to SECTION D. Instructions:  Answer all questions in SECTION A - SECTION D. Make sure that the section heading is included and your answers are correctly numbered.  The assignment must have a completed cover sheet. It must be placed in the drop-box on or before the deadline.  st SECTION A ELECTRONIC STRUCTURE & IONIZATION ENERGY 1. 2. Write the electronic structure in s‚p‚d notation of the following: O‚ Na‚ Na+‚ Al‚ Cl- and Co

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           2.5  10-5 M        4.9  10-5 M        7.0  10-3 M        3.7  10-2 M 5. What is the pH of the buffer that results when 12.5 g of NaH2PO4 and 22.0 g Na2HPO4 are mixed and diluted with water to 0.500 L? (The acid dissociation constants for phosphoric acid are Ka1 = 7.5  10-3‚ Ka2 = 6.2  10-8‚ and Ka3 = 3.6  10-13) (Points : 10)        2.30        7.04        7.38        12.27        12.62 6. Which of the following combinations would be the best to buffer an aqueous

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    reactants. Very little data is available on how does the carbon chain length of carboxylic acid and alcohol affects the rate constant and equilibrium constant of esterification. Thus‚ the research topic of this investigation is: How does the carbon chain length of the alcohols and carboxylic acids affect the rate constants of the forward and backward reactions and equilibrium constant of the esterification reaction? The affect of the carbon chain length of carboxylic acid and alcohol was measured separately

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    Experiment 1 : Design and preparation of buffers effective at different pHs Abstract The body uses natural buffers to maintain the many different pH environments in our body. This is important for optimum activity of our enzymes. When doing experiments in vitro using these enzymes it is important to mimic intracellular conditions using artificial buffer systems in order to obtain accurate results. In this experiment the buffering properties of three artificial buffer systems containing acetic

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    Acid-Base Titration Using a pH Meter Bradley Holloway and Jennifer Parker Period 6 April 16‚ 2013 Introduction: In chemistry‚ the ability to find molarities of acidic and basic solutions is a convenient way to convert between moles of solute and the volumes of their solutions. Through the process of titration‚ the molarity of these acids and bases can be found to a high level of precision. To begin titration‚ one solution is added to a second solution slowly until a certain point

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    Acid is a proton donor and a base a proton acceptor * Lewis- An acid is an electron pair acceptor‚ and I base is an electron pair donor * Conjugate base & acids * Ka= [products]/[reactants] * Acid dissociation constant * 14.2 Acid Strength * In a strong acid dissociate almost 100% * Ka is large * Strong acid yields weak conjugate base * Weak Acid * Does not dissociate much * The weaker the acid‚ the stronger

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    Chemistry Graphing

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    10-8 | 3.0 | 7.5 x 10-4 | 7.5 x 10-8 | 6.0 | 1.43 x 10-3 | 1.43 x 10-7 | What would you expect for the reaction if 4.0 M acid had been used? About 9 x 10-8 Logger Pro Graph 3. A beaker containing 100 ml of water is heated at a constant rate for 10 minutes. The temperature of the liquid is

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    Purity of Aspirin Objectives - To research‚ using various sources‚ the history of aspirin‚ its use in medicine‚ methods of synthesizing it and of measuring its purity - To compare the % purity of a branded aspirin tablet with a generic aspirin tablet - To compare 2 methods of composition analysis of the two types of aspirin Research

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    zagam

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    of 0.1M of CH3COONa was taken in a 1000ml flask and 250ml of CH3COOH was added to it. 4. The solution was mixed well. 5. Its pH was tested and verified with pH meter. Observations: Henderson-Hansselbach Equation pH = pKa + log Dissociation Constant of CH3COOH Ka = -log Ka = log [H+] – log pKa = pH – log pH = pKa + log e.g. if we want to make a solution of 0.1M and 5.76pH ‚ then we know the pKa value of CH3COOH is 4.76 in pKa table‚ So‚ putting all values in formula we get. 5.76

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    Chemistry In Life

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    www.kalvisolai.com 5 Mark Compulsory Problems with Solution 1 +2 CHEMISTRY Q. 70 Compulsory Problems with Solution Problems are solved in easiest way (As per Government Answer Key) www.kalvisolai.com 5 Mark Compulsory Problems with Solution 2 SALIENT FEATURES Dear Students ❆ Q.No: 70 is asked as compulsory problem in Govt Exam. ❆ Two problems to be answered out of four problems. ❆ To simplify the problem‚ hints and expected compounds related to molecular formula‚ general formula are

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