not supported by the lab. Based on the lab’s evidence‚ the things that need to be accounted for are not just ionic or covalent bonding‚ but also polar and non polar substances. If this hypothesis was correct‚ the citric acid should have dissolved in hexane‚ and not in dissolved in water‚ but instead it did the opposite. The solutes that would dissolve in acetone would be the sodium phosphate‚ ammonium chloride‚ sugar‚ citric acid‚ urea‚ and
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the two compounds more completely. The boiling point (bp) of our unknown compounds was taken from the flat regions of the fractional distillation curve. Our unknown mixture contained hexane (bp 69 ºC) and toluene (bp 110.6 ºC). Analysis via gas chromatography allowed us to determine the relative percentage of hexane and toluene at fractions near the beginning and end of our distillations. Relative percentages have been recorded in the table below‚ and our calculations are shown on page 5. Conclusion
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mixture of hexane and acetone was determined to best solvent for this extraction. Knowing this add one mL of the pure hexane and one mL of the pure acetone to the mortar. Grind the contents until the cell walls have been adequately broken. Transfer the mixture to a centrifuge tube to separate the sample into layers‚ to help remove the water. Once the sample is finished spinning extract the organic layer and place in a test tube. TLC: To determine which mixture acetone and hexane is the best
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Final Year Project Progress Report Title: Fat Content Analysis and Characterization of Food Class and Group No. : AS114103/2A1 Student Names : Chan Hoi Ching (120586347) : Chan Wai Yi (120464356) : Cheung Kit Cheung(120552694) : Lam Chi Ching (120224281) : Lam Pik Shan (120181829)
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then we started with station 4‚ solubility‚ we had add a small amount of 4 different liquids (Hexane‚ Ethanol‚ Water‚ or Vegetable oil) to a well‚ then we had add a solid (Salt‚Sugar‚ or Lard) to each of the 4
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group. Waxes are non crystalline. Example: Bees wax‚ Carnauba wax‚ opal wax. Etc. Properties of oil: 1. At room temperature oils liquid. 2. Oils contains large proportion of unsaturated fatty acid. 3. Oils are insoluble in water but readily soluble in Hexane‚ ether‚ benzene‚ Carbon tetra chloride‚ etc. 4. Oils are easily hydrogenated like alkenes. 5. Oils react with Iodine‚ chlorine in aqueous alcoholic solution to form iodo-chloro derivatives. Terms related Definitions: Iodine value: Iodine value may
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depends on the essential principles as does in thin layer chromatography. It was used in this experiment in separating and analyzing the different components of Capsicum frutescens (siling labuyo) with the use of solvents such as Hexane (C6H14)‚ Dichloromethane (CH2Cl2)‚ Hexane/Dichloromethane (1:1)‚ and Dichloromethane/Methanol (MeOH) (1:1). The components found in the experiment were carotenoids (carotenes and lutein)‚ xanthophylls (capsanthin) and anthocyanins. Introduction [1]Column Chromatography
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Observations recorded. These steps will then be repeated using hexane as the solvent instead of water. Part II: Solubility Testing of the Halogen Make baseline observations of what each of the ions and molecules looks like in water and in hexane. First‚ 1mL of the aqueous (water) solution of iodine will be added to a test tube using a dropper in lieu of a graduated cylinder. Appearance of solution will be recorded. Then‚ 1mL of hexane will be added to the test tube mix. Observations of both layers
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in Part I. List compound on one axis of your table and solvent system on the other. If multiple spots were present for a compound‚ give Rf value for each component and state if the component was major or minor. | 100% hexane | 25% EtOAc in hexane | 10% EtOAc in hexane | Fluorene | 0.34 cm | 0.94 cm | 0.67 cm | 9 - fluorenol | 0.00 cm | 0.49 cm | 0.05 cm | 9 - fluorenone | 0.00 cm | 0.69 cm | 0.21 cm | 2. Explain how Rf values were generally affected by polarity of the solvent/eluent
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alcohol (intermediately polar)‚ and hexanes (nonpolar). When benzophenone is mixed with water the results turned out to be insoluble because benzophenone is a pure hydrocarbon‚ which are very insoluble in water. When benzophenone was mixed with methyl alcohol‚ it was soluble because Methanol can hydrogen bond to the carbonyl oxygen of benzophenone. When benzophenone was added to hexanes it was partially soluble because “likes dissolve likes” benzophenone is polar and hexane in non polar. When the next compound
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