The primary focus of experiment 4 was to teach a student the basic solubility rules of salts in aqueous solutions. After developing and using a scheme for the qualitative analysis of three cations in an aqueous mixture‚ a student would use a centrifuge to identify‚ precipitate‚ and separate the three ions in the mixture. After becoming familiar with all three cations‚ the student would use the scheme again to identify at least two of the cations in an unknown solution. In order to begin the separation
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Determining the value of molar mass of chosen compound Marta Dürrigl 1mmA Chemical reaction: b.) CaCO3 (s) + 2HCl (aq) ----------- CaCl2 (aq) + CO2 (g) + H2O(l) AIM: The aim of this investigation is to experimentally determine the molar mass of carbon dioxide (CO2) by measuring its volume and calculating its mass. CO2 which we will measure will arise as a product of a chemical reaction between Calcium Carbonate (CaCO3) and Hydrochloric acid (HCl) as it is shown in the chemical
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The Molar Mass of a Volatile Liquid Adam Kozdrowicz Adam Li 11/05/12 Mr. McCready Purpose: The purpose of this procedure is to determine the molar mass of an unknown liquid‚ evaporate a sample of a liquid substance‚ and measure certain physical properties of the substance as it condenses. Procedure: 1. Obtain safety goggles. 2. Trim a piece of aluminum foil so that it covers the top of a small 13 x 100 mm test tube. Secure the foil with electrical tape. Make sure
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Determining the Molar Mass of a Volatile Liquid Purpose: The purpose of this lab was to find the molar mass of a volatile liquid. Data Table: Mass of Test Tube and Stopper (g) | 10.864 g | Barometric Pressure (mmHg) | 749.31 mmHg | Temperature of Boiling Water (C) | 97.1 C | Mass of Test Tube‚ Stopper‚ and Condensed Liquid (g) | 10.890 g | Volume of Flask (mL) | 9.90 mL | Calculations: 749.31 mmHG*1 atm760 mmHg= .98593 atm 9.90 mL*1 L1000 mL= .00990 L 97.1 C+273=370.1 K Substituting
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blue color starts to fade After heating it is completely white – color has faded – and particles are smaller due to the stirring Calculations of Trial 1: Molar Mass of H2O = 2 x (1.01) + 16.00 = 18.02gmol1- How many moles of H2O evaporated Trial 1: 0.72g±0.04g/18.02gmol1- = 0.03995… ≈ 0.040mol±6.25% = 0.040mol±0.003mol Molar Mass of CuSO4 Cu: 63.55 gmol1- S=32.07 gmol1- O x 4= (16.00) x 4=64.00 gmol1- CuSO4= 159.62 gmol1- Moles of anhydrous part (CuSO4) 1.35g±0.02g/159.62 gmol1-=0
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LESSON 3: MOLAR VOLUME QUESTIONS 1. Calculate the density of the least dense gas‚ hydrogen‚ at 25⁰C and 101.3kPa. [0.083g/L] 2. Calculate the density of the densest gas‚ uranium (VI) fluoride (UF6) at 70⁰C and 25.0kPa. [3.09 g/L] 3. An unknown monoatomic gas X has a density of 5.37g/L at 25⁰C and 101.3kPa. Calculate the molar mass of the gas and determine its identity. [ 131.028g/mol; Xe] 4. Calculate the density of ammonia gas in grams per litre at 18⁰C and 100.4kPa. [0.706g/L] SCH3U0 Gases
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Solubility as a Property of Matter A Lab of Chemicals‚ Chromatography‚ and Crime! Chemistry is a natural science that deals with the composition of matter and the changes it undergoes. At crime scenes‚ investigators often find unknown materials that need to be identified. If an unknown material is a mixture‚ an investigator may want to know one or two things about it: What are the ingredients of the mixture? Is the mixture found at the scene the same as a known mixture? A mixture is a collection
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Determining the Absorbance Maximum Wavelength and Molar Extinction Coefficient to Find the Molarity of the Unknown DCPIP Background Information: A spectrophotometer is an instrument used to help determine the absorption spectrum of chemicals. It does this by reading the absorbance of the chemical at different wavelengths. All chemicals absorb light in their own distinct way. This distinction helps to identify unknown chemicals. The absorption of light within a chemical is also very important because
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Carlie Haeffner Qualitative Analysis March 20‚ 2015 The purpose of this lab is to identify unknown ions in a solution by using a type of chemical reaction called precipitate reactions. The key to finding which ions are present in a solution is to form a precipitate which makes the ions “come out” in a reaction (McNeil‚ 2013-2014). Water is used in these experiments to act as a solvent. Since water is a polar molecule‚ the slightly positive and negative charges will sometimes pull apart molecules
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Purpose/Objective The purpose of this experiment is to identify the periodic trends in the solubility of the alkaline earth metals and compare the results to that of lead Materials 1. Pencil 2. Lab notebook 3. 5 small test tubes 4. Droppers Chemicals 1. 0.2 M Mg(NO3)2 2. 0.2 M Ca(NO3)2 3. 0.2 M Sr(NO3)2 4. 0.2 M Ba(NO3)2 5. 0.2 M Pb(NO3)2 6. 1 M NaOH 7. 0.2 M NaBr 8. 0.2 M NaI 9. 0.2 M Na2SO4 10. 0.1 M Na2CO3 11. 0.2 M Na2C2O4 12. 1 M NaCl Data and Results Mg(NO3)2
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