"Ksp calcium chloride" Essays and Research Papers

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    solubility guidelines lead (II) chloride (PbCl2) is a possible precipitate. This is because even though most chlorides are soluble‚ lead chloride is considered insoluble (p.2‚ Lesson 17). Step 2: PbCl2 ↔ Pb2+ + 2Cl- Q = [Pb2+] [Cl-] 2 Step 3: Ksp = 1.2 x 10-5 (from table 17.1‚ p.5) Step 4: V2 = 20.0 mL (volume of Pb (NO3)2) + 45.0 mL (volume of CaCl2) = 65.0 mL C2 = C1 V1 V2 Looking at lead nitrate solution before being mixed with the calcium chloride solution. The dissociation

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    compounds in different solute-solute and solvent solute interactions. Description We will be mixing ionic compounds in solute-solute and solvent solute interactions. We will be combining sodium‚ potassium‚ calcium‚ magnesium‚ copper‚ iron‚ nickel and silver and some anions like chloride‚ sulfate‚ nitrate‚ oxalate‚ phosphate‚ and hydroxide. We will be seeing which one forms a precipitate or rings. Most likely the anions will be the insoluble. From there we will be making a flow chart that will

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    inorganic lab 1

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    drugs and dosage form Part 1: Examples of Drugs and dosage forms having acid radicals Part 2: How to analyze bromide‚ chloride‚ nitrate‚ carbonate and sulfate radicals Lab 4: Qualitative analysis of Basic Radicals present in drugs and dosage form Part 1: Examples of Drugs and dosage forms having basic radicals Part 2: How to analyze aluminium‚ iron‚ zinc‚ potassium‚ calcium‚ sodium radical Lab 1 Principle of identification of Inorganic drugs‚ compound‚ ions which is already identified but

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    School Topic : Solubility product of Constant (Ksp) Grade : XI Semester : 2 Time Allocated : 30 minutes I. Competency Standard Understanding properties‚ measuring method and applying of acid base solutions. II. Basic Competency Predicting precipitation from a reaction based on solubility and solubility product constant principle III. Indicator 1. Explain the meaning of Solubility Product Constant (Ksp) 2. Write down the Solubility Product Constant’s

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    mohr method

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    Title: Determination of chloride by the Mohr Method Objective: To determine chloride by using Mohr Method. Introduction: The Mohr method is the method used to determine the chloride ion concentration of a solution by titration with silver nitrate. As the silver nitrate solution is slowly added‚ a precipitate of silver chloride forms. Ag+ + Cl-  AgCl(s) (Ksp for AgCl is 1.810-10) The chloride ion (Cl-) is an important anion found in solids and solutions. Chloride is the predominant anion

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    August 28‚ 2009 [PROBLEM SET FROM R. CHANG TEST BANK] Chapter 16 Acid-Base Equilibria and Solubility Equilibria Student: ___________________________________________________________________________ NOTE: A table of ionization constants and Ka’s is required to work some of the problems in this chapter. 1. In which one of the following solutions will acetic acid have the greatest percent ionization? A. B. C. D. 2. Which one of the following is a buffer solution? A. B. C. D. E. 3. 0.40 M HCN and

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    of lead(II) chloride (PbCl2) at 25oC. Ksp = 1.62e–5. A) 1.59e–2 B) 2.53e–2 C) 6.64e–17 D) 2.01e–3 E) 2.01e–2 2. The two salts AgX and AgY have very similar solubilities in water. It is known that the salt AgX is much more soluble in acid than is AgY. What can be said about the relative strengths of the acids HX and HY? A) Nothing. B) HY is stronger than HX. C) HX is stronger than HY. D) The acids have equal strengths. E) Cannot be determined. 3. Solubility Products (Ksp) BaSO4 1

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    Selective precipitation of the Barium Magnesium Group Chem 112-004 Abstract The purpose of this experiment is to separate and identify the cations of Ba+‚Sr2+‚Ca2+‚ Mg2+ and NH4+ using differences in solubility and confirming test to identify the unknown solution used in this experiment. In this experiment the methodology used by the group is to perform the tests for both the unknown and the cations (Ba+‚Sr2+‚Ca2+‚ Mg2+ and NH4+) using the known as a control for comparison and identification

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    solubility-product constant‚ Ksp‚ for Cu(OH)2 at 25 °C. Ksp = [Cu 2+][OH –]2 = [1.76 x10–7][3.53 x10–7]2 = 2.20 x10–20 (b) The value of the solubility-product constant‚ Ksp‚ for Zn(OH)2 is 7.7 x10–17 at 25 °C. (i) Calculate the solubility (in moles per liter) of Zn(OH)2 at 25 °C in a solution with a pH of 9.35. Zn(OH)2 Zn 2+ + 2 OH – Ksp = [Zn 2+][OH –]2 pH 9.35 = pOH 4.65; [OH –] = 10–4.65 = 2.24 x10–5 M Zn2+ = Ksp/[OH -]2 = 7.7x10-17/[2

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    Molar Solubility

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    Unur Abdul Kader T.A: Katie Experiment 22: Molar Solubility‚ Common-Ion Effect Abstract The purpose of this experiment was to determine the molar solubility‚ the solubility constant‚ and the effect of a common ion on the molar solubility of calcium hydroxide. To accomplish this the experiment was split into two parts; part A and Part B. in Part A of the experiment a standardized 0.05 M solution of HCl was titrated into a 25 mL solution of saturated Ca(OH)2 which contained 2 drops of orange methyl

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