Summary This experiment will measure the rate of oxidation of iodide ions by persulphate ions to derive the rate law for the reaction. Starch will be added to the reaction to facilitate the measure of time during the reaction. The reactant solutions will contain (NH4)2SO4 and KI‚ represented as: (NH4)2S2O8 + 2KI -> I2 + (NH4)2SO4 + K2SO4 This can be simplified to: S2O82- + 2I- -> I2 + 2SO42- These equations can only be carried out and be visible after the iodine has completely
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The Effect of the Concentration of Sulphuric Acid on the Reaction Rate with Magnesium Sarah Cain SCH 4UB Mr. Lankin April 1‚ 2009 Introduction The nature of the problem is to design an investigation that examines a variable affecting the reaction rate. In this experiment‚ magnesium will be reacted with different concentrations of sulphuric acid. The reaction is shown by the following chemical equation: H2SO4 (l) + Mg (s) → MgSO4 (aq) + H2
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Name ____________________________ Date ____________ THE EFFECT OF CONCENTRATION ON THE RATE OF DIFFUSION PURPOSE: This experiment will explore the concentration gradient by measuring the rate of diffusion in a number of theoretical cells. The objectives for this lab are: (1) To define concentration gradient‚ (2) To explain experimental data concerning different concentration gradients‚ (3) To complete a data table and prepare a graph to illustrate the data‚ and (4) To apply information from
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Effect of Substrate Choice On Growth Of Mealworms Abstract: The experiment is designed to show which substrate A or B will better nourish a mealworm. A mealworm was placed in each substrate for a period of seven days and the change in mass from Day 1 to Day 7 was compared. The data was compiled and statistically analyzed. The experiment failed to reject the null hypotheses that there would be no difference in the two substrates regarding meal worm growth
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Chirag Patel Biology 157 Determining the Effect of Varying Substrate Concentration Question: How does concentration of potatoes affect the amount of oxygen produced with hydrogen peroxide and potatoes (enzymes)? Introduction The enzyme used for this experiment is Catalase. Catalase is inside mostly any living organism which uses oxygen. Its job is to break down hydrogen peroxide‚ into oxygen and water. (Formula) 2H2O2 ---> 2H2O + O2 (lab manual). There are limiting factors which if altered
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VARYING EFFECTS OF ENZYME CONCENTRATION ON REACTION RATES OF MALATE DEHYDROGENASE CELL BIOLOGY 13 NOVEMBER 2007 Enzymes are biological catalysts. They are proteins that speed up reactions with low concentrations. These enzyme proteins are made up of linkages of amino acids. The links coil‚ and coil again forming a tertiary structure. This structure has a groove in it called an active site. The active site is
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Hydrolysis Report Bile Esculin Hydrolysis‚ Starch Hydrolysis‚ UreaHydrolysis‚ Casein Hydrolysis Hydrolysis Report Introduction Hydrolysis is a chemical reaction that uses water to split complex molecules. The water molecule H2O is split in the mechanism of hydrolysis‚ hydrogen cations and hydroxide anions. When the enzyme catalyzes its reaction inside the cell‚ it is referred to as intracellular hydrolases. When the enzymes secreted from the organism to catalyze reactions outside the cell‚ it
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That is‚ the entering group does not for the most part have the same position on the ring as that purged by the halogen substituent. Case in point‚ the hydrolysis of 4-chloromethylbenzene at 340° gives an equimolar mix of 3-and 4-methylbenzenols: Significantly all the more striking is the elite development of 3-methoxybenzenamine in the amination of 2-chloromethoxybenzene. Notice that this outcome is an
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Objective To investigate the effect of carbon dioxide concentration on the rate of photosynthesis Introduction Photosynthesis is a process that is essential for every living organism. Organic substances‚ such as glucose‚ are made from carbon dioxide and water by light energy from the sun. The light energy is absorbed by chlorophyll and converted to chemical energy. During the process‚ oxygen is released as a by-product. The rate of photosynthesis is affected by a few of factors‚ including
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Determination of the Equilibrium Constant of an Unknown Ester Hydrolysis Reaction Abstract The experiments to follow determined that the equilibrium concentrations of the reaction: ester + water ↔ alcohol + acid‚ are equal to 0.0363 moles of ester‚ 0.2852 moles of water‚ and 0.0268 moles each of alcohol and acid. Using this information the equilibrium constant was determined to be 0.06938. 1. Introduction In this lab the equilibrium constant‚ Kc‚ for the acid catalyzed reaction
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