To provide an understanding of the concept of friction‚ and To calculate the coefficient of friction of an object by two methods. Materials From: Label or Box/Bag: Student Provides Qty Item Description: 1 1 1 1 1 1 1 From LabPaq Ramp board: 3 - 4 feet long‚ 10 cm wide Can of soft drink or item of similar weight Friction block set-PK Protractor Scale-Spring-500-g Tape measure‚ 1.5-m Tape measure‚ 3-m Discussion and Review Whenever a body slides along another body
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deforming of metal parts or melting of metal components. In this cooling process‚ a liquid gets circulated throughout the engine. We have to use a liquid that can absorb all that heat. A homogeneous mixture consisting of a solute and a solvent based on colligative properties‚ which means solution’s properties will differ depend on the proportion of solute present. Solutions have both a lower freezing point and a higher boiling point than pure solvent. The more solute is present the bigger the difference between
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the cetyl alcohol solution and use it to calculate the value of the freezing point depression constant‚____‚ for BHT. 3.) Use the calculated value of ___ to find the molecular mass of the unknown solute. Discussion: 1. Give a definition of colligative properties. 2. Draw a phase diagram of a pure substance‚ and show how addition of a solute affects this diagram. 3. What is the least precise measurement? How does this limit your significant digits? 4. Why is it advantageous to choose a solvent
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depression defined as a vertical medium in reference to boiling point elevation. The general definition is the effect of lowering the freezing point of a substance due to an increased amount of solute added to the solvent. This effect is known as colligative property. The equation that shows this relationship is: ΔT= Kf * m Eq. 1 The goal of this experiment was to determine the molar mass of aspirin using the freezing point depression method. First‚ the freezing temperature of the pure solvent
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References: 1. Hands-on Labs‚ Inc. LabPaQ CK-College General Chemistry. Observation of Chemical Changes. Pgs 15-20. Englewood‚ CO. USA.
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of water in molarity AND molality. Assume the density of the solution is 1g/mL. 18. You need to prepare 25.0mL of a solution of 1.5M HCl. Your lab provides you with 6M HCl stock solution. How do you prepare the solution you need? 19. What are colligative properties and list the 4 we discussed in class? 20. Draw an osmotic cell with a 1M NaCl solution on one side
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icJohn Melvin Mateo BS AT - 1A NSCI 121 Assignment no.1 (Finals) 1.)What is Osmosis? Osmosis is the diffusion of the movement of water from a region of higher concentration to a region of lower concentration through a cell membrane or other semi-permeable membrane until an equilibrium is reached. It is a special case of diffusion (passive transport). Basic Explanation : Osmosis can occur when there is a partially permeable membrane
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Keith Shearer Lab Group 3 January 19‚ 2015 Objective Is to measure various food items and become familiar with different energy units like calories and joules. Also‚ we will be using simple household products and follow the standard safety procedures of this lab. Materials Procedure First‚ use a digital scale to determine the empty weight of the 100ml beaker. The‚ you are going to fill the beaker half way with water (approximately 50ml) and weigh it again. Take the water and beaker weight
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osmosis does not require input of energy‚ it does use kinetic energy [6] and can be made to do work.[7] The osmotic pressure is defined to be the pressure required to maintain an equilibrium‚ with no net movement of solvent. Osmotic pressure is a colligative property‚ meaning that the osmotic pressure depends on the molar concentration of the solute but not on its identity. Osmosis is essential in biological systems‚ as biological membranes are semipermeable. In general‚ these membranes are impermeable
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Chemistry 121 Colligative Properties Lab Demonstration of Selected Calculations from Choice I Determination of Kf for Naphthalene To determine the Kf for naphthalene‚ we need to find the difference in the freezing point of pure naphthalene and the solution of 1‚4-dichlorobenzene in naphthalene. Let’s say that we did this experiment‚ used 1.00 g 1‚4-dichlorobenzene in 10.00 g naphthalene‚ and found that the freezing temperature of pure naphthalene was 78.2°C‚ while that of the solution was 75
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