A: Formulation of the LP Model X1(Pizza)‚ X2(hotdogs)‚ X3(barbecue sandwiches) Constraints: Cost: Maximum fund available for the purchase = $1500 Cost per pizza slice = $6 (get 8 slices) =6/8 = $0.75 Cost for a hotdog = $.45 Cost for a barbecue sandwich = $.90 Constraint: 0.75X1 + 0.45X2+ 0.90(X3) ≤ 1500 Oven space: Space available = 3 x 4 x 16 = 192 sq. feet = 192 x 12 x 12 =27648 sq. inches The oven will be refilled before half time- 27648 x 2 = 55296
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The three products/variables in this problem that must be considered for purchase are: x1: Pizza Slices x2: Hot Dogs x3: Barbeque Sandwiches The objective is for Julia to maximize profits. Julia’s goal is to earn a profit of at least $1‚000.00 after each game. Profit = Sell – Cost Profit Function: Z = 0.75(X1) + 1.05(X2) + 1.35(X3) Constraints and Cost: The maximum amount of funds available for purchase is $1500.00 Cost per pizza slice = $0.75 because Julia purchases each pizza for $6.00
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CLICK TO DOWNLOAD MAT 540 Week 6 Homework Complete the following problems from Chapter 2: 1. Problems 2‚ 6‚ 7‚ 12‚ 16‚ 20 2. Chapter 2 2. A company produces two products that are processed on two assembly lines. Assembly line 1 has 100 available hours‚ and assembly line 2 has 42 available hours. Each product requires 10 hours of processing time on line 1‚ while on line 2 product 1 requires 7 hours and product 2 requires 3 hours. The profit for product 1 is $6 per unit‚ and the profit
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Mat 540 Quiz 3 Question 1 .2 out of 2 points Correct The following inequality represents a resource constraint for a maximization problem: X + Y ≥ 20 Answer Selected Answer: False Correct Answer: False Question 2 .2 out of 2 points Correct Graphical solutions to linear programming problems have an infinite number of possible objective function lines. Answer Selected Answer: True Correct Answer: True Question 3 .2 out of 2 points Correct Surplus variables are only associated
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Abstract— The work deals with the healing of the coverage hole identified in a location unaware network using fuzzy logic. The hole identification is done based on the Delaunay Triangulation method and the Empty circle concept. The main contribution here is that the healing of the coverage hole is done on a location unaware network based on the energy‚ angle and distance of the nodes involved in the healing process using the fuzzy rule set. Only the partial location information like the distance
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The homework problems for Module 4 are: 2-24‚ 34‚ 36‚ 38 (you only have to do part A for these problems. You do not have to do the part B graphical solutions) and 3-10‚ 12 (parts B and C for Problem 12)‚ 28‚ 30. Please use Excel solver function. I posted an annotated solution to Problem 2-5. This problem is an examplar for both the chapter 2 and 3 problems. In this example I show how I typically set up a problem. First I set up the linear programming model and then develop a parallel set-up
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Homework #1 Solutions 3.1 a. Let X1 =the number of hours of process 1 used X2 =the number of hours of process 2 used The objective is to minimize the cost of producing the three products A‚ B and C. The constraints are on the demand of each product. Min 4X1 + X2 subject to 3X1 + X2 ≥ 10 (A’s demand) X1 + X2 ≥ 5 (B’s demand) X1 ≥ 3 (C’s demand) X1 ‚ X2 ≥ 0 (nonnegativity) b. From the graph we can see that the isocost line just leaves the feasible region where the demand for C and B intersect. The
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C2 differentiation Maximum points‚ minimum points and points of inflection All 3 types of point are easy enough to spot on a graph: • Maximum points are the tops of ‘peaks’ • Minimum points are bottoms of ‘troughs’ • Points of inflection are where a curve stops turning ‘left’ and starts turning ‘right’ (or vice versa). An example is the point (0‚1) on the curve [pic]+1 Notes (i) Any point on a curve where the gradient is zero can be
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University of Las Vegas Nevada Alejandra Parra Case 8-1: Product Mix Managerial Report 04/04/2013 Product Mix Information * TJ’s Inc.‚ makes 3 nut mixes for sale to grocery chains located in the Southeast. The three mixes are: Regular Mix‚ Deluxe Mix and Holding Mix. Each are made by mixing different percentages of these 5 nuts as follows: | Almond | Brazil | Filbert | Pecan | Walnut | Regular Mix | 15% | 25% | 25% | 10% | 25% | Deluxe Mix | 20% | 20% | 20% |
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1) The model for the transportation problem consists of 18 decision variables‚ representing the number of barrels of wastes transported from each of the 6 plants to each of the 3 waste disposal sites: = Number of Barrels transported per week from plant ‘i’ to the j-th waste disposal site‚ where i = 1‚ 2‚ 3‚ 4‚ 5‚ 6 and j = A‚ B‚ C. The objective function of the manager is to minimize the total transportation cost for all shipments. Thus the objective function is the sum of the individual
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