1. The mole is a counting unit of chemistry that denotes a specific amount 2. Avogadro created this unit 3. He used 12 grams of carbon to figure out his unit‚ weighed out 12 grams and did multiple test calculations 4. Abbreviation for the mole is mol 5. Avogadro’s number is 6.022 x 10^23 6. 1 mole= 6.022 x 10^23 7. Avogadro used the number to create molar mass 8. Molar mass is the weight of an atom in 1 mol‚ g/mol is the unit 9. MM is the abbreviation for molar mass 10. A mole is defined
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of atoms of an element equal to the number of atoms in exactly 12.0 grams of carbon-12? Mole or Avogadro’s number 5. How many atoms are in a sample of an element whose mass is numerically equal to the atomic mass of that element? 6.02x1023 6. For what substance do we use formula units? Ionic compound 7. At STP‚ equal volumes of different gases contain what? Same number of particles = 1 mole 8. Identify the value for standard temperature. 25C 9. Identify the value for standard pressure
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I. Title: Iron-Copper (II) Chloride Reaction II. Purpose: The purpose of this lab is to see how iron reacts with a copper (II) chloride solution. III. Equipment and Reagents Scoop copper (II) chloride (CuCl2) Beaker Iron (Fe) Wash Bottle water (H2O) Scale Hydrogen chloride (M HCl) Filter Paper IV. Procedure: 1. Obtain a clean‚ dry 250 mL beaker. 2. See teacher to obtain a scoop of CuCl2 in the beaker. 3. Add approximately 50 mL of tap water to
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Purpose: To find number of moles of Fe+3 which react with one mole of NH3OH+ in order to partially balance the equation: NH3OH+ + 2Fe+3 "" ? + 2Fe+2 and to find the missing product. Procedure: H2C2O4 and H2SO4 were titrated with potassium permanganate. The molarity of the permanganate was then found because the molarity of the H2C2O4 and H2SO4 were already known. Then hydroxylammonium chloride and ferric sulfate and water was titrated with known potassium permanganate to get the molarity of the
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(amu) 1 mole f X=atomic mass in grams 1 mole of something = 6.022 x 1023 units of that substance 1 mole of a compound =66.022 x 1023 atoms 6.022 x 1023 amu =1 g 2. What is the mass of 6 atoms of Fe? Answer: 6 atoms of Fe x 55.85 amu÷atom of Fe x 1 g of Fe÷6.022 x 1023 amu = 3. How many atoms does it take to make 1 g of Gold (Au)? Answer: 197.0 g Au =1 mole of Au 1 g of Au=? 1 mole of Au/197 g Au
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Solution: 0.7533g of Na2EDTA mixed with 500ml DI water Table A: Standardization of EDTA Trial | Start Volume | End Volume | Amount of EDTA | 1 | 3.90ml | 29.85ml | 25.95ml | 2 | 5.35ml | 28.35ml | 23.00ml | 3 | 0.45ml | 23.50ml | 23.05ml | Moles
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point and mole ratio of the water to the anhydrous. Every substance has unique characteristics which help to determine the identity of it. The actual values of the properties can be compared to the experimental values. In real life‚ this can be used to determine the unknown medicines. Hypothesis: The hypothesis is that the alum can be verified by finding the properties; the actual melting point of alum is 92.5(http://cookeatshare.com/popular/melting-point-of-alum) and the actual mole ratio of
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1. If atomic mass of Mg atom is 24 g‚ find mass of 1 Mg atom. 2. Find mass of 1 molecule C2H6. (C=12‚ H=1) 3. Find mole of 6‚9 g Na. (Na=23) 4. Find mass of 0‚2 mol P4 . (P=31) 5. Find mole of 4‚48 liters O2 under normal conditions. 6. Find mass of Fe in the compound including 4‚8x1023 O atoms ;Fe3O4 . 7. 1. Find relation between number of molecules of given matters; 8. I. C2H2 that includes 2mol H atom 9. II. CH4 that includes N atoms (N is Avogadro number) 10. III. C3H4 that includes 1‚5 N C atoms
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Stoichiometry Chapter: Some Basic Concepts of Chemistry Mass and Stoichiometry Question 1 2.5 moles of sulphuryl chloride were dissolved in water to produce sulphuric acid and hydrochloric acid. How many moles of KOH will be required to completely neutralize the solution? Ans. SO 2Cl2 + 2H2O H2SO 4 + 2HCl Mol of HCl produced from 2.5 moles of SO2 Cl2 = 5 mol Mol of H2SO 4 produced from 2.5 moles of SO2Cl2 = 2.5 mol H2SO4 + 2KOH HCl + KOH K2SO 4 + 2H2O; KCl + H2 O Now‚ 5 mol of H2SO 4 require
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contains equal numbers of Na‚ O‚ and H atoms. Since this is the case‚ the atom ratio Na:O:H is 1:1:1‚ and so the simplest formula is NaOH. In terms of moles‚ we have one mole of Na‚ 23 grams‚ one mole of O‚ 16 grams‚ and one more of H‚ 1 gram. From this kind of argument we can conclude that the atom ratio in a compound is equal to the mole ratio. We get the mole ratio from chemical analysis‚ and from that the formula of the compound. In this experiment‚ we will use these principles to find the formula
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