Syllabus for GPAT - 2013 PHARMACEUTICS Introduction to Physical pharmacy Matter‚ Properties of Matter: State of matter‚ change in the state of matter‚ latent heats and vapor pressure‚ sublimationcritical point‚ Eutectic mixtures‚ gases‚ aerosols-inhalers‚ relative humidity‚ liquid. Complexes‚ liquid crystals‚ glassy state‚ solids- crystalline‚ amorphous and polymorphism. Micromeretics and Powder Rheology: Particle size and distribution‚ average particle size‚ number and weight distribution‚ particle
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A miser is ever in want. --Greek proverb Preparing to experiment You will be provided with the following materials: Redox Reactions Reactions involving oxidation and reduction processes are very important in our everyday world. They make batteries work and cause metals to corrode (or help to prevent their corrosion). They enable us to obtain heat by burning fuels--in factories and in our bodies. Many redox reactions are complex. However‚ combustion and synthesis (from elements) are
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Lab 5 – Weather and Climate Change Lab 5 - Demonstration 1: Modeling the Water Cycle POST LAB QUESTIONS 1. Which water cycle processes are represented in this model and by what components? Answer = Condensation and evaporation are represented in the model. Condensation formed inside the jar and under the lid and the warm water evaporated. 2. Which processes are not represented? How could the model be altered to include these processes? Answer = Precipitation and infiltration did not get represented
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-2013 GRADE -9(Boys) CHEMISTRY. 1. Evaporation of a liquid can take place a)At its boiling point b) Below its boiling point c) At all temperatures d) At a fixed temperature 2.Evaporation of water will increase with a) addition of a solute to it b) decrease in temperature c) increase in temperature d)less surface area 3.Diffusion is faster in the case of a)Oxygen b) nitrogen c) hydrogen d) Carbon dioxide 4.During evaporation‚ particles of a liquid change to vapours
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Lab 5 – Weather and Climate Change Lab 5 - Demonstration 1: Modeling the Water Cycle POST LAB QUESTIONS 1. Which water cycle processes are represented in this model and by what components? Answer = Evaporation‚ condensation‚ sublimation‚ and precipitation. 2. Which processes are not represented? How could the model be altered to include these processes? Answer = Transpiration‚ surface run-off‚ infiltration‚ and percolation. With or by adding sand and possibly plants to the assignment
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filtration and evaporation. Filtration is a process where solids and liquids can be separated. The liquid that passes through the filter paper is called a filtrate. Evaporation is a process where two liquids or a solid mixed into a liquid can be separated. To separate two liquids mixed together‚ the liquid
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energy in the form of heat. This heat energy causes the water in the world ’s oceans‚ lakes‚ etc. to warm and evaporate. As the water is heated‚ it changes its phase from liquid to gas. This gas is called water vapor and this process is called evaporation. When plants give off water vapor‚ it’s called transpiration. When water evaporates‚ it rises into the cooler air‚ collects‚ and forms clouds. There‚ the water vapor molecules cool down and change back into liquid water. This is called condensation
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for a cactus‚ that would soak up the water‚ and thus ideally show the percentage water loss by weighing the before and after evaporation weights. Independent Variable The independent variable is the total surface area for each size of the blocks and I think this will affect the dependent variable as larger blocks‚ I hypothesize‚ will have less water loss by evaporation as there is less surface area for it‚ as opposed to the smaller (2cm x 2cm x 2cm) blocks‚ that have a larger total surface area
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temperature for Air dry bulb temperature‚ wet-bulb temperature‚ cooling tower inlet temperature and cooling tower outlet temperature operating with ClO2 Generator for typical Summer day June- 2014 are given in table-1. From the table its seen that the evaporation losses ‚ cycle of concentration and make-up water fluctuate the effectiveness of cooling tower compared with the at the time of manual chemicals doses. At 2:00PM in June 2014 the dry bulb temperature (DBT) is 320C‚ wet-bulb temperature is 240C‚
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Q-3. * Because the perfumed incense is in solid state and by lighting of it‚ it changes from solid state to gaseous state the moment it turns in to gaseous state and gases have a property to spread in all directions. After lightening the incense the molecules of perfume are in a gaseous state and mixing with the molecules of air in the room. All of them undergo random motion at all times as a result of the internal ("heat") energy that they have absorbed. The molecules often bump into each other
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