affecting reaction ratesProcedure A: Effect of ConcentrationAim: To investigate how the concentration of a reactant affects the rate of reaction. Hypothesis: The more concentrated the reactant‚ the faster the rate of reaction. Materials: 2M hydrochloric acid solution‚ magnesium wire‚ distilled water‚ 4 test-tubes‚ measuringcylinder. Procedure:1)10mL 2M hydrochloric acid solution is poured into a test-tube using a measuring cylinder. 2)A 3cm length of magnesium wire is added to the acid‚ and the
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Effect of Temperature on Solubility of a Salt Ahmed Mohammed 17-nov-2013 Abstract In this experiment‚ you will study the effect of changing temperature on the amount of solutet will dissolve in a given amount of water. In this experiment‚ you will completely dissolve different quantities of potassium nitrate‚ KNO3‚ in the same volume of water at a high temperature. As each solution cools‚ you will monitor temperature using a computer-interfaced Temperature Probe and observe
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Calculating the Enthalpy Change of Reaction for the Displacement Reaction between Zinc and Aqueous Copper Sulphate Data Collection and Processing Observations: * Drops of water left on the inside of the measuring cylinder * Hole in the lid‚ possible escape route for gas or splash-back * The polystyrene cup felt warm during the reaction By extrapolating the graph we can estimate what the rise in temperature would have been if the reaction had taken place instantaneously. I can
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Determining Order from Rates of Reactions AP Chemistry Purpose The focus of this experiment is to recognize that when aqueous solutions of potassium iodate ion (KIO3-) and bisulfite ion (HSO3-) are mixed‚ a series of reactions will occur‚ and the final reaction is signaled by the appearance of a dark blue color. My partners and I investigate how the concentration of the reactants affects the rate of reaction. The purpose of this lab is to find
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Investigation of Action of Saliva and 3 M Hydrochloric Acid in Two Carbohydrate Solutions Title : Investigation of Action of Saliva and 3 M Hydrochloric Acid in Two Carbohydrate Solutions Objective : To investigate the action of saliva and 3 hydrochloric acid in two carbohydrate solution Results Table1: Observation Conclusion Solution A Benedict’s test: Blue coloration turned to brick red precipitate. Reducing sugar is present in the solution A. Iodine test: The coloration remained
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For known amounts of reactants‚ theoretical amounts of product can be calculated in a chemical process. These calculated products are determined using the limiting reagent‚ (the substance that runs out first which stops the reaction) and are called the theoretical yield. The theoretical yield is the amount of product that should be acquired during the experiment if all aspects go perfectly. However‚ due to experimental errors‚ very few labs do so. These results are called actual yield. The percent
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Chemical reactions proceeding until all the reactants are used is a common misconception. Chemical reactions actually behave differently. The general reaction equation is a A + b B → c C +d D in this equation A and B are the reactants forming the products C and D. However‚ unlike the common thought that the reaction ends when it runs out of A and B it actually does not. In most reactions C and D start to react to form A and B at a certain point as you can see in the equation c C + d D → a A + b
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Aim: To determine the rate law of chemical reactions Introduction: The aqueous solution of potassium peroxydisulphate can oxidize potassium iodide as follow: Equation: K S 0 (aq) + 2KI (aq)->2K S0 (aq)+I (aq) 2 2 8 2 4 2 KI(aq) +I (aq) -> KI (aq) 2 3 _________________________________________________ K S 0 (aq) +3KI(aq) -> 2K S0 (aq)+ KI (aq) 2 2 8 2 4 2 The rate law of this reaction can be represented as follow: Rate=k[S208 2-]^a [I-]^b When the concentration of peroxydisulphate ions
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will increase the speed of reaction as the greater the surface of the solid reactants‚ the more particles are required to expose and ‘cover’ the capacity of the solid. Increased surface area results in an increased chance of collisions between reactant particles. Since the collisions become more frequent and abundant‚ the rate of reaction increases. Aim The aim of the experiment is to see if a greater surface area of a dissolvable tablet creates a faster or slower reaction Independent Variable
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The reaction order‚ based on the rate law‚ was first order with respect to crystal violet and second order with respect to OH-. The rate law was as follows: Rate law = k [CV]1[OH-]1 where k equaled 2.61. In order to determine the reaction order with respect to crystal violet‚ the graph that described the relationship between ln[CV] and time (seconds) was Figure 2. Not only did Figure 2 generate a more linear relationship‚ but it had the highest R2 value of 0.992 than ([CV] versus time) and ([1/CV]
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