Acid Base Titration Purpose: The purpose is to calculate the molarity of a NaOH solution by titrating the base with 5mL of standard HCl solution in each trial. By adding the base with unknown molarity to the acid with 0.10M the molarity of NaOH can be calculated. The base‚ NaOH‚ helps bring the pH of the acid‚ HCl‚ closer to seven‚ which neutralizes it. When using the buret the amount of NaOH used is able to be determined. Then by writing a balanced chemical equation and using the titration
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and 3 drops of phenolphthalein indicator was added to the flask and then titrated with the standard NaOH solution. Finally‚ the 2 infinity samples were titrated in the same way and the [HCl] was calculated. [HCl]t was calculated from each aliquot sampling. Lastly‚ Excel software was used to plot ([HCl] -[HCl]t) vs. time(t). The slope of the straight line through the points enabled the calculation for the rate of the reaction. Results
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account statements and calculating different ratios related to Profitability‚ Liquidity‚ Asset Management and Long-Term Debt Paying Ability. Also‚ I will be doing a comparative analysis of Wipro with its nearest competitor Hindustan Computer Limited (HCL). I will also be doing a sector outlook of the IT industry and the government policies related to the IT industry‚ the Holding pattern & ownership of shareholders‚ FII’s‚ Financial Institutions‚ public‚ etc.‚ the price trend of the Wipro’s stock in
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EQUILIBRIUM CONSTANT OF A REACTION Methodology The following stock solutions were prepared: 1.0 M HCl‚ 0.1 M HCl‚ 0.1 M KSCN‚ 0.002 M KSCN (in 0.1 M HCl)‚ 0.2 M FeCl3 (in 0.1 M HCl)‚ and 0.002 M FeCl3(in 0.1 M HCl). Using the prepared stock solutions‚ the standard (Table 1) and Unknown (Table 2) solutions were prepared. Table 2. Preparation of Standard Solutions 0.10 M KSCN 0.002 M FeCl3 0.1 M HCl Blank 2.0 ml 0.0 ml 8 ml S1 2.0 ml 0.1 ml 7.9 ml S2 2.0 ml 0.25 ml 7.75 ml S3 2.0 ml 0.5 ml
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objective of the Get Charged Up lab was to determine the charge on a metal ion reacting with HCl by determine the mole ratio in a reaction by determining the amount of excess reactant‚ amount of product‚ and amount of hydrogen gas produced as well as finding the best research method to determine the charge. To accomplish this‚ three different methods were used. Titration was used to react NaOH with HCl to determine the amount of H+ left over after the reaction is complete. Crystallization was
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Discussion 2mol of HCL * V = 50 cm3 * 1 mol 50/2=V V=25 cm3 Volume needed to neutralise 50 cm3 of 1 mol dm-3 of NaOH is 25 cm3 of HCL b) Independent variable: Volume of HCL Dependent variable: Temperature of mixed solution Controlled variables: Volume of alkaline‚ Concentration of acid‚ Concentration of alkaline c) Burette d)Fix the burette into a burette holder securely. Pour HCL into the burette with a funnel until it reaches the 0.0cm3 mark. e)The risk of using plastic cup
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pair of electrons. Yes‚ this is the same Lewis that wrote the Lewis Dot Structures in module 3. 3. What makes an acid to be classified as a ‘strong’ acid? (2.01) A strong acid is one that breaks apart close to 100% when in solution. HCl is an example. When HCl is dissolved in water‚ it breaks apart into H+ and Cl- ions. Not all acids break apart. Those chemicals that do not break apart well are considered ‘weak’ acids. 4. List three general properties of acids. (7.01) Acids have a sour
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acid. Magnesium reacts with magnesium is react with hydrochloric acid to form hydrogen gas. The aim of this experiment is to determine the value of x in the following equation: Mg + X HCl → MgCl2 + X/2 H2 A known amount of magnesium is reacted with a large excess of HCl‚ and the volume of H2 evolved is measured. As HCl is in excess‚ all the magnesium will be consumed‚ and the yield of both MgCl2 and H2 is dependent on the amount of magnesium used. A comparison of the amount of hydrogen produced with
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Chemistry Lab Report Stoichiometry Design Experiment Percentage Yield of Calcium Carbonate and HCl I. Background Information When marble chips and hydrochloric acid are added together‚ they form sodium chloride‚ water‚ and carbon dioxide. This reaction can be displayed by the balanced equation below; CaCO3 (s) + HCl (l) NaCl(s) + H2O(l) + CO2 (g) As the carbon dioxide is formed‚ it will leave the open beaker as a gas. This will result in a loss of mass. The mass change can then be
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Introduction Extraction is a purification technique used in organic chemistry to separate compounds from a mixture of two or more compounds. There are three different extraction techniques: liquid-liquid extraction‚ solid-liquid extraction and chemically active extraction. All three types of extraction follow the same principle. Organic molecules dissolve in organic solvents and polar molecules dissolve in aqueous solvents. This phenomenon is observed because of the intermolecular forces between
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