"Stoichiometry of a precipitation reaction full lab" Essays and Research Papers

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    EXPERIMENT 4 TITLE Complex Formation and Precipitation. INTRODUCTION Precipitation is the formation of a solid in a solution as the result of either a chemical reaction‚ or supersaturating a solution with a salt resulting in solid material collecting on the bottom of the beaker (Housecroft & Constable‚ 2006). When the solution has been supersaturated by a compound and no more material can be supported by the solution‚ it considered as precipitate. Commonly‚ the solid will fall out of the

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    1- The reaction HCl + KOH KCl + H2O is a a. synthesis reaction c. neutralization reaction b. ionization reaction d. decomposition reaction 2- What is the value of the self-ionization constant of water? a. 0 c. 1.00 107 b. 1.00 1014 d. 55.4 3- Pure water contains a. water molecules only. b. hydronium ions only. c. hydroxide ions only. d. water molecules‚ hydronium ions‚ and hydroxide ions

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    Lead Iodide Reaction Lab

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    The lab today was focused on finding the ratio of reactants to products to be either 1 to 1 or 1 to 2. In our case the reactants was Lead (II) Nitrate and Potassium Iodine. These two when mixed together make Lead Iodide and Potassium Nitrate. We also had to try and find if the number of moles of Lead(II) Nitrate was the same as the final number of moles for Lead Iodine after the experiment. Our data for the lab had pinpoint accuracy. Proved by the data table below Trials Volume of Pb(NO3)2 Mol

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    Chemical Reaction Lab

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    Introduction The reaction rate of a chemical reaction is determined as the change in the concentration of a reactant or product over the change in time. [1] The rate of a reaction is determined by experiment. Many factors influence the rate of a reaction: the nature of the reaction‚ concentration‚ pressure‚ temperature‚ and surface area‚ presence of catalyst and intensity of light. [2] For a chemical reaction‚ the rate law or rate equation is a mathematical expressed equation that links the reaction rate with

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    Chemistry Lab Report Stoichiometry Design Experiment Percentage Yield of Calcium Carbonate and HCl I. Background Information When marble chips and hydrochloric acid are added together‚ they form sodium chloride‚ water‚ and carbon dioxide. This reaction can be displayed by the balanced equation below; CaCO3 (s) + HCl (l) NaCl(s) + H2O(l) + CO2 (g) As the carbon dioxide is formed‚ it will leave the open beaker as a gas. This will result in a loss of mass. The mass change can then be

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    Reaction of Metals Lab

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    I. Title: Reaction of Metals II. Problem: The purpose of the experiment was to determine if and how different metals react to different solutions. III. Hypothesis: IV. Materials: Dropper‚ Beakers‚ wax pencil‚ Goggles‚ eight test tubes‚ a rack for the tubes‚ three strips of Zinc‚ two strips of Copper‚ three strips of Magnesium‚ steel wool‚ Lead nitrate‚ Silver nitrate‚ Copper sulfate‚ Magnesium chloride‚ Zinc chloride‚ Sodium chloride‚ and Potassium. V. Procedure: In tube 1 add five

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    Abstract: The main objective of this Lab‚ is to experiment with stoichiometric measurements‚ since it is one of the most important subjects in chemistry. In addition‚ stoichiometric measurement is widely used in chemistry‚ because it indicates the proportion of mass in which various substances react. By examining one specific example of stoichiometric determination‚ which is: “Stoichiometry and limiting reacting”‚ we found out the different mass proportions in which substance react. In this case

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    Chapter 3 Stoichiometry

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    Chapter 4 — Intro—1 1 CHAPTER 3 Topic Scopes: Stoichiometry and Solution Concentration • Molarity‚ molality‚ parts per million & percentage (w/w‚ w/v and v/v) • Stoichiometry calculation • Limiting reactant • Theoretical yield‚ actual yield and percentage yield 1 2 Mole Concept No. of Moles = Molarity (M) • Molarity (molar concentration) is the number of moles of a solute that is contained in 1 liter of solution Mass (g) molar mass (g/mol) No. of Moles = Molarity (mol/L)  volume (L) Molarity

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    2 Heat of Precipitation

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    Thermochemistry Heat of precipitation - precipitate is unsoluble salt - precipitate must be prepared through double bond decomposition or precipitation method Do you still remember what is meant by double bond decomposition? [please refer to salts notes] General equation double bond decomposition/precipitation; Ionic equation for precipitation reaction. Salt Solubility in water Li+‚ Na+‚ K+‚ NH4+ All salt dissolve in water Nitrate‚ NO3- All nitrate salt

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    compound. 2. A. Copper can be produced from the reaction of aluminum and excess copper(II) sulfate: Al(s) + CuSO4(aq)  Al2(SO4)3(aq) + Cu(s) B. How many moles of aluminum is necessary to produce 4.50 g of Cu if the reaction is 91% complete? 3. A. How many grams of disulfur dichloride is produced from the reaction between 20 g of sulfur and 80 g of chlorine? B. How much of the excess reactant remained? (The reaction is 100% complete.) S8(s) + Cl2(g) → S2Cl2(g) 4.

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