Experiment 39 Oxidation – Reduction Titrations II : Analysis of Bleach A. Standardization of 0.05 M Na2S2O3 Solution KIO3 concentration 0.01 M Volume of KIO3 Trial #1 Trial #2 Final burette reading 15.01 mL 30.00 mL Initial burette reading 0.00 mL 15.01 mL Milliliters of KIO3 used 15.01 mL 14.99 mL Volume of Na2S2O3 Trial #1 Trial #2 Final burette reading 13.40 mL 25.78 mL Initial burette reading 0.03 mL 13.37 mL Milliliters of Na2S2O3 used
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Name: Date of experiment: 04/02/12 Date of report: 04/03/12 Title: Oxidation – Reduction Activity Series Purpose: To determine relative oxidizing and reducing strengths of a series of metals and ions. Oxidation and reduction reaction occur simultaneously side by side. A reduction reaction occurs only if an oxidation reaction occurs and vise-versa. Electrons are given in oxidation while in reduction electrons are gained. Oxidizing agent is a chemical substance which has a large tendency to
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8.07 Work File: Oxidation Reduction Reactions 1. What is the difference between an oxidizing agent and a reducing agent? The oxidation number (overall charge of the atom) is reduced in reduction and this is accomplished by adding electrons. The electrons‚ being negative‚ reduce the overall oxidation number of the atom receiving the electrons. Oxidation is the reverse process: the oxidation number of an atom is increased during oxidation. This is done by removing electrons. The electrons‚ being
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2 electrons NH3OH+ --> something + 2e- Oxidation number of N in NH3OH+ is -1‚ therefore the oxidation number for N on the product side must be +1 because it gains 2 electrons. N2O has an oxidation number of +1 for N‚ so that would work. Data:Equation 1: NH3OH+ + 2Fe+3 --> something + 2Fe+2 Equation 2: 8H+ + 5Fe+2 + MnO4- --> 5Fe+3 + Mn+2 + 4H2O Equation 3: 6H+ + 2MnO4- + 5H2C2O4 --> 2Mn+2 + 10CO2 + 8H2O Conclusion: Therefore the concluded reaction would be: NH3OH+ + 2Fe+3 --> N2O + 2Fe+2
Free Manganese Mole Potassium permanganate
1. Mechanism of oxidation process In an oxidation process of silicon that usually takes place at very high temperature (thermal oxidation)‚ silicon (Si) reacts with either water vapor (H20) or oxygen (O2) to form silicon dioxide‚SiO2 on the silicon surface. The reaction is represented by following equations: Dry oxidation: Si + O2 → SiO2 Wet oxidation: Si + 2H2O → SiO2 + 2H2 The oxidation process can be implemented through diffusion
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potassium permanganate solution was titrated thrice to give clear Mn2+ with an analyte of acidified FeSO4 until all the Fe2+ in the solution was oxidized to Fe3+. The color of the MnO4-/Mn2+ was used as the indicator for the titration. A balanced oxidation-reduction‚ the molarity/normality of the standards potassium permanganate‚ and the volume of potassium permanganate used allowed the determination of the concentration of the FeSO4. Equipment and Chemicals: Chemicals: * Iron (II) ammonium sulfate
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This experiment was a Landolt Iodine clock reaction - Oxidation of Bisulphite by Iodate. It involved conducting three measured experiments. The first variable tested was concencentration. This was tested by conducting two experiments‚ each varying the concentration of either the NaHSO3 or KIO3. The varying of NaHSO3 involved using 0.1 Molar of KIO3 against decreasing concentrations of NaHSO3 (0.25 M‚ 0.125 M‚ 0.0625 M and 0.03125 M). When decreasing the concentration of KIO3‚ 0.25 M of NaHSO3 was
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Title : reduction of camphor to isoborneol Hend Altajjar Date: 01\30\2015 disk no. 116 lab report experiment procedure I scaled up 0.120 g of camphor ‚ the I added 1.0 ml of methanol in a 10-ml Erlenmeyer flask. I stirred with a glass stirring rod until the camphor has dissolved. Then I
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OIXDATION(AND(REDUCTION(–(REDOX(CHEM(1( ( KEY(REDOX(CONCEPTS( •! Oxidation)and)reduction)are)electron(transfer(processes)(reactions).)) o! Oxidation(–(Loss)of)electrons)) !! Reductant((reducing)agent))–)undergoes)oxidation.)) o! Reduction(–(Gain)of)electrons)) !! Oxidant((oxidising)agent))–)undergoes)reduction.)) ! Example:(((((((((((Mg(s)(+(2H+(aq)( (Mg2+(aq)(+(H2(g)( o! This!reaction!can!be!broken!up!into!two!halfEreactions(( !! Oxidation:)Mg(s))")Mg2+)+)2e:)(lost)electrons))( !! Reduction:)2H+)+)2e:)")H2)(gained)electrons))(
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STK 1084 Inorganic Chemistry I‚ LU 3 Oxidation – Reduction Reactions‚ Prepared By: Dr. Tay Meng Guan‚ Faculty of Resource Science and Technology‚ Universiti Malaysia Sarawak. LU 3 Oxidation and Reduction Reactions 3.1 Ideas of Oxidation and Reduction Oxidation of an atom can be occurred in the following conditions: 1. Losing an electron from the orbitals. e.g.: A A+ + e- 2. Adding an electronegative element (e.g.: F‚ Cl‚ Br‚ O) to a molecule. e.g.: A + F AF 3. Losing hydrogen
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