Thermochemistry Lab Purpose: This lab taught procedures for determining heat of capacity of a calorimeter and measuring enthalpy of change for three reactions. It also enforced methods of analyzing data obtained through experimentation and calculating enthalpy. These procedures are used in the branch of thermodynamics known as thermochemistry which is the study of energy changes that accompany chemical reactions. Concepts from this lab can be used to determine the potential energy of a chemical
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suspended from the ceiling of a large room. The steam temperature entering the pipe is 120 oC‚ and the air temperature is 20 oC. The overall heat transfer coefficient on the outer surface of the covered pipe is 10 W/m2.K. if the velocity of the steam is 10 m/s‚ at what point along the pipe will the steam begin condensing and what distance will be required for the steam to reach a mean temperature of 100 oC? Question 2: Consider a horizontal‚ thin walled circular tube of diameter D = 0.025 m
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................................................ 6 5. SYSTEM ARCHITECTURE ................................................................................................................... 7 5.1 MULUNGUSHI UNIVERSITY ONLINE CLEARANCE SYSTEM (MU-OCS) ............................ 7 5.1.1 ACCOUNTS ................................................................................................................................ 7 5.1.2 THE LIBRARY ..................................................
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substitution reaction. Chemical Equation: Materials: Name of Compound Molecular weight MP/BP Grams Used Moles Used Methyl benzoate 136.16 g/mol -12.5 OC /199.6 OC 0.28g 2.056*10-3 Sulfuric acid 63.01 g/mol 10 OC /337OC 0.8g 1.2*10-2 Nitric acid 98.08 g/mol -42 OC /83 OC 0.2g 2.039*10-3 Methyl 3-nitro benzoate 181.15 g/mol 78 OC /279 OC 0.107g 5.906*10-4 Procedural Details To a reaction tube 0.6 mL of concentrated sulfuric acid was added; followed by 0.28g
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Aluminum Hot Plate Temp. (oC) ±.1 93.6 93.5 93.5 Room Temp (oC) ±.1 22.4 22.3 22.3 Combined Temp. (oC) ±.1 25.9 24.0 24.5 Specific Heat (J/kg0C) 504.3 324.0 671.1 PART B: Specific Heat of Water 700C 800C 900C Room Temp (oC) ±.1 21.2 24.7 24.9 Hot Plate Temp. (oC) ±.1 70 80 90 Final Temp. (oC) ±.1 41.5 47.2 51.0 Temp. Final (oC) 45.6 52.4 57.5 Part C: Heat Fusion of Ice Ice Mass (g) ±.1 63.9 46.0 43.5 Initial Temp (oC) ±.1 21.8 20.4 23.5 Final Temp (oC) ±.1 4.8 6.6 6.0
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(g/mol) Density(g/cm3) M.P.(oC) B.P.(oC) Solubility Ferrocene C10H10Fe 186.03 1.49 172 oC-174 oC 249oC Insoluble in water‚ soluble in organic solvent Acetyl-ferrocene C12H12FeO 228.08 - 81 oC -83 oC 161 oC - 163 oC (at 4 mm) Very slightly soluble in water‚ soluble in organic solvent Ethyl Acetate C4H8O2 88.11 0.897 -83.6 oC 77.1 oC Slightly soluble in water (~8.3g/100mL‚ 20 oC)‚ very miscible with alcohol‚ ether‚ acetone‚ benzene. Hexane C6H14 86.18 0.6548 -95 oC 69oC Immiscible with water
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raise the image of the brand. We have a room for price increasing as it isshown that other OC brands with price 5-10 times higher can have better sales than Maya. For this re-positioning OC pills‚ we should target to the urban market. For rural market‚ I also agree withSchellstede to use RMPs as the linkage (influencer) to the rural area target group because RMPs havegreat influence in providing knowledge of OC pills and ultimately change consumers behavioral intent. 2) Why is this difficult market
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UNIVERSITY OF DAR –ES-SALAAM COLLEGE OF NATURAL AND APPLIED SCIENCES DEPARTMENT OF MOLECULAR BIOLOGY AND BIOTECHNOLOGY MC206: FOOD MICROBIOLOGY PRACTICALS PRACTICAL 1 MICROORGANISMS IN THE ENVIRONMENT GROUP #:1 NAME: DUSENGEMUNGU Léonce REG #: 2011-04-07086 COURSE INSTRUCTOR: Dr Mugassa S.T Rubindamayugi
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specific heat capacity of solution 4.2 J g-1 oC-1 Ө temperature change oC To determine precipitation heat of silver chloride‚ AgCl In this experiment you must have the following data; Data tabulation Initial temperature of sodium chloride NaCl /oC x oC Initial temperature of silver nitrate‚ AgNO3 /oC y oC Average initial temperature for both solution Highest temperature for the solution z oC Temperature change z – (x + y) oC = Ө oC 2 Chemical equation for the
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process are given in Table 1 below. Table 1: Stream Data Stream Supply Temperature TS (oC) Target Temperature TT (oC) Heat Duty (MW) No Type H1 H2 H3 C1 C2 Hot Hot Hot Cold Cold 150 40 130 150 50 30 40 100 150 140 7.2 10 3 10 3.6 You are required to perform a heat recovery analysis for the plant section stated above. Given the Tmin for the process is 10 oC‚ conduct the Problem Table Algorithm and determine the pinch temperature and the minimum
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