Chemistry 11 Final Examination Review - Answers Part A - True or False. Indicate whether each of the following statements is true or false. Correct the false statements. F 1. The mass of an electron is equal to the mass of a proton. The mass of an electron is less than the mass of a proton. T 2. The mass of a proton is approximately equal to the mass of a neutron. T 3. The atomic number represents the number of protons in a nucleus. T 4. The proton has a mass of approximately
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(bubbles are a good example of this). The new product formed is the chemical change; it is more than just physical. A. Materials: a. 4 small test tubes b. 100ml beaker c. Stirring rod d. Cu e. Zn f. Mg g. MgO h. NaCl i. Cu(NO3)2 j. CuCO3 k. NaOH (4mL) l. HCl (4mL) m. Burner Fuel n. Test tube clamp o. 24 well plate p. Test tube cleaning brush q. Matches r. 96 well plate
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and electrolyte and a salt bridge. In a galvanic cell one metal can undergo reduction and the other oxidation. A typical galvanic cell is based on the spontaneous redox reaction: Net Ionic Equation Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s) Half Equations Zn(s) → Zn2+(aq) + 2e– Cu2+(aq) + 2e– → Cu(s) The anode will undergo reduction (Zinc) and the cathode will undergo oxidation (Copper) The two half cells must be physically separated so that the solutions do not mix together. A salt bridge
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Nonylphenol and bisphenol A binding studies with antioxidant enzymes through homology modeling and molecular docking methods M. Jayakanthan1#‚ R. Jubendradass2‚ Shereen Cynthia D’Cruz2‚ P. P. Mathur1‚2‚3* 1 Centre for Bioinformatics‚ School of Life Sciences‚ Pondicherry University‚ Pondicherry- 605 014‚ India 2 Department of Biochemistry and Molecular Biology‚ School of Life Sciences‚ Pondicherry University‚ Pondicherry - 605 014‚ India 3 KIIT University‚ Bhubaneswar - 751024‚ India
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bromide ---> FeBr3 + 3AgI d.r.‚ yes rxn 6. 2LiCl + I2 ---> 2LiI + Cl2 s.r‚ no rxn‚ I not replace Cl 7. 4K + O2 ---> 2K2O comb. 8. MgCO3 ---> MgO + CO2 dec.; yes rxn 9 2AlCl3 + 3MgCO3 ----> Al2(CO3)3 + 3MgCl2 d.r.‚no rxn‚ MgCO3 insol. 10. Zn + H2SO4 ---> ZnSO4 + H2 s.r.‚ yes rxn 11. Mg + 2AgNO3 ---> Mg(NO3)2 + 2Ag s.r.‚ yes
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Purpose: To find out the percent yield of copper in the reaction between copper sulfate (CuSO4) and Iron (Fe). Materials: Balance 100-mL beaker 250-mL beaker Bunsen burner Copper sulfate crystals Glass stirring rod 100-mL graduated cylinder Iron filings Ring stand and ring Wire gauze Procedure: 1. Record mass of clean 100-mL beaker. 2. Add 8.0 grams of copper sulfate crystals to beaker. 3. Add 50.0 milliliters of distilled water to the crystals. 4. Put wire gauze on ring on ring
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Various Metal Activity (Zinc (Zn)‚ Magnesium (Mg)‚ and Copper (Cu)) in the Color of Rainwater and Amount of Rust in the Iron Nail “ Hypothesis If the type of metal that has the highest activity will be used ‚ then there will be the least amount of rust found in the nail and the color of the rainwater would be the lightest. Independent Variable • Types of metals used in wrapping Title: “ The Effect of Various Metal Activity (Zinc (Zn)‚ Magnesium (Mg)‚ and Copper (Cu)) in the Color of Rainwater
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Comparative study of commercial antacids Problem Solving Assessment 1. The electrode potentials of some metal electrodes are Cu2+ / Cu = 0.34 V ‚ Pb2+ / Pb = — 0.13 V Ag+ / Ag = 0.80 V‚ Zn2+ / Zn = — 0.76 V. Which of the following reactions will not occur ? (a) Zn + Cu2+ → Zn2+ + Cu (b) Zn + Pb2+ → Zn2+ + Pb (c) Cu + 2Ag+ → Cu2+ + 2 Ag (d) Cu + Pb2+ → Cu2+ + Pb 2. The property of a colloidal solution in which the dispersion medium moves when placed in an electric field is called
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HKDSE CHEMISTRY – A Modern View (Chemistry) Coursebook 3 Suggested answers |Chapter 25 Simple molecular substances with non-octet |Page Number | |structures and shapes of simple molecules | | |Class Practice |1 | |Chapter Exercise
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Reducing Sugars : Sugars that contain aldehyde groups that are oxidised to carboxylic acids are classified as reducing sugars. Common test reagents are : Benedicts reagent (CuSO4 / citrate) Fehlings reagent (CuSO4 / tartrate) They are classified as reducing sugars since they reduce the Cu2+ to Cu+ which forms as a red precipitate‚ copper (I) oxide. Remember that aldehydes (and hence aldoses) are readily oxidised (review ?) In order for oxidation to occur‚ the cyclic form must first ring-open
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