Chapter 7 Circuit Analysis Techniques
15. Derive the Thevenin equivalent of the circuit shown in Figure 7.47a.
Req= (R1+R2)//(R3+R4)= 5.2k//1.5k= 1164 x 10^3= 1.2kΩ
Rth= Req+R5= 1.2kΩ+1kΩ= 2200 x 10^3= 2.2kΩ
Vth= Vs= 9V
16. Derive the Thevenin equivalent of the circuit shown in Figure 7.47b.
Req= R1+R2= 22+33= 55Ω
Vth= Vs x R3/Req+R3+R4= 12V x 120Ω/55+120+51 = 6.37V
Rth= (R1+R2)//(R3+R4)= (22+33)//(120Ω+51Ω)= 41.6Ω
17. Derive the Thevenin equivalent of the circuit shown in Figure 7.48a.
Req= R1//R2 = 1.2k // 1.8k = 720Ω
Vth= Vs x R3/ Req+3 = 10V x 1kΩ/720Ω+1kΩ = 5.81V
Rth= Req//R3= 720Ω//1kΩ = 418.6Ω = 418.6 =419Ω
18. Derive the Thevenin equivalent of the circuit shown in Figure 7.48b.
Vth= Vs x R3/R2+R3= 6V x 150Ω/75Ω+150Ω= 4V
Rth= R2//R3 = 75Ω//150Ω= 50Ω
Chapter 9 Alternating Current and AC Measurements
1.Calculate the period of the waveform shown in Figure 9.44.
T= (4div) x 20 ms/div= 80 ms/div
2. Calculate the period of the waveform shown in Figure 9.45.
T= (5div) x 100µs/div= 500µs/div
3. Calculate the period of the waveform shown in Figure 9.46a
T= (8div) x 10µs/div= 80 µs/div
4. Calculate the period of the waveform shown in Figure 9.46b.
T= (4div) x 20 ms/div= 80 ms/div
7. Calculate the frequency of the waveform shown in Figure 9.47a
T= (6div) x 5µs/div= 30µs/div f= 1/T= 1/30µs= 33333 x 10^3= 33.33kHz
8. Calculate the frequency of the waveform shown in Figure 9.47b.
T= (10div) x 10ms/div= 100ms/div f= 1/T= 1/100ms= 10Hz
13. Determine the peak-to-peak and half-cycle average voltages for the waveform shown in Figure 9.48a.
Vpp=2Vpk= 2x18V= 36Vpp
Vave= 0.637Vpp= 0.637 x 18V= 11.46V
14. Determine the peak-to-peak and half-cycle average voltages for the waveform shown in Figure 9.48b.
Vpp=2Vpk= 2x50mV= 100mVpp
Vave= 0.637Vpp= 0.637 x 50mV=31.85mV
15. Calculate the rms values of load voltages and current for the circuit shown in Figure 9.49a.
Vrms= 0.707Vpk= 0.707 x 30V= 21.21V
Ipk= Vpk/RL= 30V/470Ω= 0.0638 x 10^-3= 63.8mA
Irms=