Math Essay 2
Running header: TWO-VARIABLE 1
Two-Variable Inequalities
Danielle Smith
MAT 222 Week 2 Assignment
Instructor Thompson
September 15, 2014
TWO-VARIABLE 2 Two-Variable Inequalities This week we are doing two variable inequalities. The two variable inequalities are independent and dependent variables with graphing. I am going to work on the problem number 68 from page 539 from our book (Dugopolski, 2012). The problem is asking about the way to ship with the shipping restrictions. There is a graph that shows all of the possibilities of the number of refrigerators and the number of TVs that will fit on the 18-wheeler truck. First we need to write out the inequality to describe this region. Then answer two questions first one being will the truck hold 71 refrigerators and 118 TVs or will the truck hold 51 refrigerators and 176 TVs? The book shows a graphing points at (0,330) and (110,0). m=y, -y =330-0=330=-3 x ,-x 0-110 -110
This is the first slope is -3.
Now we can form a linear equation to write. y,-y =( x-x) slope point y-330=-3(x-0) y-330=-3x we simplify the parenthesis y=-3x+330 add 330 to each side
3x+y<330 add 3x to each side
The graph is a solid line rather than a dashed line indicating that points on the line itself are part of the solution set.
TWO-VARIABLE 3 There are two more questions we must answer. First will the truck hold 71 refrigerators and 118 TVs?
3x+y<330 Inequality
3(71)+118<330 simplify parenthesis
213+118<330 add
331<330
The answer is no it’s will not hold the 71 refrigerators and 118 TVs.
The next question is will the truck hold 51 refrigerators and 176 TVs. Using the same steps above to solve.
3x+y<330
3(51) +176<330
153+176<330
329<330
We found out that the truck will hold the 51 refrigerators and 176 TVs. Just like last week we found out that using algebra is something you will do in real life. If not the people will be loading and unloading the trucks repeatedly to see what fits
Two-Variable Inequalities
Danielle Smith
MAT 222 Week 2 Assignment
Instructor Thompson
September 15, 2014
TWO-VARIABLE 2 Two-Variable Inequalities This week we are doing two variable inequalities. The two variable inequalities are independent and dependent variables with graphing. I am going to work on the problem number 68 from page 539 from our book (Dugopolski, 2012). The problem is asking about the way to ship with the shipping restrictions. There is a graph that shows all of the possibilities of the number of refrigerators and the number of TVs that will fit on the 18-wheeler truck. First we need to write out the inequality to describe this region. Then answer two questions first one being will the truck hold 71 refrigerators and 118 TVs or will the truck hold 51 refrigerators and 176 TVs? The book shows a graphing points at (0,330) and (110,0). m=y, -y =330-0=330=-3 x ,-x 0-110 -110
This is the first slope is -3.
Now we can form a linear equation to write. y,-y =( x-x) slope point y-330=-3(x-0) y-330=-3x we simplify the parenthesis y=-3x+330 add 330 to each side
3x+y<330 add 3x to each side
The graph is a solid line rather than a dashed line indicating that points on the line itself are part of the solution set.
TWO-VARIABLE 3 There are two more questions we must answer. First will the truck hold 71 refrigerators and 118 TVs?
3x+y<330 Inequality
3(71)+118<330 simplify parenthesis
213+118<330 add
331<330
The answer is no it’s will not hold the 71 refrigerators and 118 TVs.
The next question is will the truck hold 51 refrigerators and 176 TVs. Using the same steps above to solve.
3x+y<330
3(51) +176<330
153+176<330
329<330
We found out that the truck will hold the 51 refrigerators and 176 TVs. Just like last week we found out that using algebra is something you will do in real life. If not the people will be loading and unloading the trucks repeatedly to see what fits