A Project Report on “Sales and Distribution of Financial Product” From At Success Advisory Services Pvt. Ltd.‚ Bokaro Submitted to SIKKIM MANIPAL UNIVERSITY SUBMITTED BY AHMED-YACIN YOUSSOUF FARAH ROLL NO. - 560954319 in partial fulfillment o f the requirement for the award of the degree Of MBA IN Marketing July‚ 2010 Sometimes words fall short to show gratitude‚ the same happened with me during this project. The immense help and support received from Reliance Money
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related matters‚ Handling Industrial Relations; Liaison with Advocates‚ Legal vetting of documents including Power of Attorney‚ Bank Guarantee‚ Works Contracts etc‚ Replying to Legal Queries of different departments (In Contracts‚ Land Acquisition‚ Sales‚ Personnel: Labour matters etc)‚ Preparing Company Guidelines‚ Managing the Legal team‚ Direct Interaction with Top Management] ACADEMIC RECORD ➢ B.A.LLB (Hons)‚ a five-year integrated course‚ at National Law Institute University [N.L.I.U.]‚ Bhopal
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NORMAL DISTRIBUTION 1. Find the distribution: a. b. c. d. e. f. following probabilities‚ the random variable Z has standard normal P (0< Z < 1.43) P (0.11 < Z < 1.98) P (-0.39 < Z < 1.22) P (Z < 0.92) P (Z > -1.78) P (Z < -2.08) 2. Determine the areas under the standard normal curve between –z and +z: ♦ z = 0.5 ♦ z = 2.0 Find the two values of z in standard normal distribution so that: P(-z < Z < +z) = 0.84 3. At a university‚ the average height of 500 students of a course is 1.70 m; the standard
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false alarm probability (Type-I error) for each case. The corresponding probability measures are obtained from the Normal table as P(3 " Z) = 0.00135 P(2 " Z) = 0.02275 P(1 " Z) = 0.1587 Solution: ! i) Use the Binomial distribution to ! calculate the probability measures. ! 3! 3! P(Y ! 2 n = 3‚ p = 0.02275) = (0.02275)2 (1" 0.02275) + (0.02275)3 = 0.00153 2!1! 3!0! Type-1 Risk considering both sides: ! = 0.00306 ii) 5! 5! (0.1587)4 (1" 0.1587) + (0.1587)5 = 0.00277 4!1! 5!0!
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8/13/08 4:39 PM Page 299 Confirming Pages C H A P T E R 6 The Normal Distribution Objectives Outline After completing this chapter‚ you should be able to 1 2 3 Identify distributions as symmetric or skewed. 4 Find probabilities for a normally distributed variable by transforming it into a standard normal variable. Introduction 6–1 Normal Distributions Identify the properties of a normal distribution. Find the area under the standard normal distribution
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Erika Thompson PMB410 Professor Dekker 03/22/2013 EVM ANSI 748-B Earned Value Management System (EVMS) guiding principles incorporate top business practices to give strong benefits for program or enterprise planning and control. The process includes the incorporation of program scope‚ schedule‚ and cost objectives‚ establishment of a baseline plan for success during the execution of a program. The structure provides a solid foundation for problem recognition‚ corrective actions‚ and management
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VAC = BAC –EAC €10‚ 000 – €11‚ 507 = €1‚ 507 (extra money required) If you end up spending more than your budget‚ the VAC will be negative… just like CV and SV! Finding missing information Let’s say you’re given... … the CPI and Earned Value‚ and you want to figure out the actual costs. Why would you ever see this? Sometimes it’s hard to figure out how important a project is unless you know how much it’s really spending—if a project is more expensive‚ people in your company probably
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Probability distribution Definition with example: The total set of all the probabilities of a random variable to attain all the possible values. Let me give an example. We toss a coin 3 times and try to find what the probability of obtaining head is? Here the event of getting head is known as the random variable. Now what are the possible values of the random variable‚ i.e. what is the possible number of times that head might occur? It is 0 (head never occurs)‚ 1 (head occurs once out of 2 tosses)
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_____ 1. What is mean‚ variance and expectations? Mean - The mean of a discrete random variable X is a weighted average of the possible values that the random variable can take. Unlike the sample mean of a group of observations‚ which gives each observation equal weight‚ the mean of a random variable weights each outcome xi according to its probability‚ pi. The mean also of a random variable provides the long-run average of the variable‚ or the expected average outcome over many observations
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When I read the story A Rupee Earned by I.F Bulatkin I related to it most. The story is about a young lazy boy that sits on his ass all day doesn’t do anything to support the family. When his father got a notice that he will only alive for so many days he told his son that if he could earn one rupee all of his dad’s fortune will be his. I haven’t been in a situation like the lazy boy but my family always told me that if you work hard now in school when you get older all that hard work will payoff
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