value of r that minimizes this by taking the derivative‚ stetting it equal to 0‚ and solving for r. Use that to find h. You’ll find that the dimensions are different from an actual soda can‚ but I’m sure you can think of why this is the case. THE MATH PROBLEM: The surface area of a cylindrical aluminum can is measure of how much aluminum the can requires. If the can has a radius r and a height h‚ its surface area A and its volume V are given by the equations: A=2(pi)r^2 + 2(pi)rh and V=
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The 1970 Mustang Boss 302 is a beautiful‚ well-built piece of machinery. There are many different items‚ ranging from tiny to large‚ that make up a 1970 Mustang. The Boss 302 can be divided into four parts categories the body‚ the chassis‚ the drivetrain‚ and the interior. Without any one of these four parts the car would not be itself. The body is what gives the Mustang its beauty. The chassis keeps the car together and rolling. The drivetrain makes the car move‚ and without the interior‚
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candidates sitting the Year 7 Entrance Tests will automatically be considered for an Academic Scholarship; parents do not need to make a separate application. Year 9 Entry Assessment is made on the basis of three written exam papers in English‚ Maths and Science which are designed to enable candidates to show flair. Each paper lasts one hour. The papers all develop National Curriculum areas which are relevant to the age of entry. Applicants for the Academic Scholarships will come to Bethany
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Maths Project Class 9 PROJECT WORK: Creative Mathematics Project Ideas General Guidelines: * Each student is required to make a handwritten project report according to the project allotted Please note down your project number according to your Roll Number. Roll Number | Project Number | 1-5 | 1 | 6-10 | 2 | 11-15 | 3 | 16-20 | 4 | 21-25 | 5 | 26-30 | 1 | 31-35 | 2 | 36-40 | 3 | 41-45 | 4 | 46-50 | 5 | * A project has a specific starting date and an end date. *
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Item 4B Item 4B Rachel Reiser Maths C Rachel Reiser Maths C Question 1 ab1+f’(x)2 dx y = acosh(xa) If: coshx=12ex+e-x Then: cosh(xa) = 12(exa+e-xa) y = acosh(xa) ∴ y=a(exa+e-xa)2 y=a(exa+e-xa)2 dydx=f’x=ddxa(exa+e-xa)2 dydx=f’x=ddx12aexa+e-xa f’x=12a1aexa+-1ae-xa f’x=exa-e-xa2 f’x2=exa-e-xa22 f’x2=(12exa-12e-xa)(12exa-12e-xa) f’x2=14e2xa-14e0-14e0+14e-2xa f’x2=14e2xa-12+14e-2xa f’x2=14e2xa-2+e-2xa Assuming the catenary is symmetrical‚ the entire length of
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MATH PORTFOLIO NUMBER OF PIECES Kanishk Malhotra 003566-035 (May 2012) In physics and mathematics‚ the ‘DIMENSION’ of a space or object is informally defined as the minimum number of coordinates needed to specify each point within it. Thus a line has a dimension of one because only one coordinate is needed to specify a point on it. A surface such as a plane or the surface of a cylinder or sphere has a dimension of two because two coordinates are needed to specify a point on it (for
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CLASS 8:- Math Revision Worksheet Topic: Profit and Loss 1. A shirt is purchased for Rs 400 and sold for Rs 460. Find the profit and profit percentage. 2. Sonal purchased an article for Rs 2500 and sold it at 25% above the CP. If Rs 125 is paid as tax on it‚ find her net profit and profit percentage. 3. By selling an article for Rs 34.40‚ a man gains 7.5%. What is its CP? 4. On selling tea at Rs 40 per kg‚ a loss of 10% is incurred. Calculate the amount of tea (in kg) sold‚ if the total loss
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work on the rule of g. = 2(x2 -3)+5 The rule of f is applied to g. = 2x2 -6+5 In this step we simplify. (f °g)(x)= 2x2 -1 Final results. Now we will compose the second of the two functions. (h° g)(x) = h(g(x)) The rule of h will work on g. = h(x2 – 3) = ((7-(x^2-3)))/3 The rule of h is applied to g. (h ° g)(x) = (10-x^2)/3 The final results. Next we are asked to transform the g(x) function so that the graph is moved 6 units to the right and 7 units downward
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Math 5067 001 Homework 1 Due 9/11/13 1. Read Chapter 1 in the DHW text (sections 1.1 – 1.3 are mandatory) and answer the following: a. List at least three incentives for an insurance company to develop new insurance products. b. (Exercise 1.1 in DHW) Why do insurers generally require evidence of health from a person applying for life insurance but not for an annuity? c. (Exercise 1.3 in DHW) Explain why premiums are payable in advance‚ so that the first premium is due at issue‚ rather than in
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Formulas (to differential equations) Math. A3‚ Midterm Test I. sin2 x + cos2 x = 1 sin(x ± y) = sin x cos y ± cos x sin y tan(x ± y) = tan x±tan y 1∓tan x·tan y differentiation rules: (cu) = cu ′ ′ ′ ′ ′ (c is constant) cos(x ± y) = cos x cos y ∓ sin x sin y (u + v) = u + v (uv)′ = u′ v + uv ′ ′ ′ u ′ = u v−uv v v2 df dg d dx f (g(x)) = dg dx sin 2x = 2 sin x cos x tan 2x = sin x = 2 cos 2x = cos2 x − sin2 x 2 tan x 1−tan2 x 1−cos 2x ‚ 2 integration rules: cos x = 2
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