"Caco3 hcl" Essays and Research Papers

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    Pre Lab 8

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    63.546g) = 9.835 X 10-4 moles The balanced equation for zinc and HCl is Zn + 2HCl = 1H2 + 1 ZnCl2 H=1‚ Zn = 65.38‚ Cl=35.45 Molar Mass of HCl = 101.83 (3.73 X 10-2 moles Zn) (2HCl/1Zn) = 7.46 X 10-2 moles HCl The amount of HCl that should be used is: 50mL of HCl = .05 L of HCl 7.46 X 10-2 moles of HCl X 2 = .1492 moles of HCl used and the molarity would be .1492 moles HCl/ .05 liters HCl = 2.984 molarity. The amount of unreacted HCl in the solution is shown here: 0.1492 moles used - .0746 moles needed

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    Acid-Base Titration Lab

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    Unknown HCl Molarity of NaOh | Trial 1 | Trial 2 | Trial 3 | Trial 4 | Initial Volume of NaOH(mL) | 0.00 | 11.00 | 20.85 | 30.45 | Final Volume of NaOH(mL) | 11.00 | 20.85 | 30.45 | 39.98 | Volume of NaOH used(mL) | 11.00 (Cancel out) | 9.85 | 9.60 | 9.53 | Average Volume of NaOH = (9.85+9.60+9.53)/3 = 9.66mL Sample Calculations: (9.85+9.60+9.53)/3 = 9.66mL The average volume of NaOH used. Calculations: 1. Moles NaOH = M x V = (0.1M) (0.00966L) = 0.000966 moles 2. Moles HCl = moles

    Free PH Hydrochloric acid Acid

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    Laboratory Report

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    DEMONSTRATOR: RICHARD TIA DATE: 2ND APRIL‚ 2009. AIM To prepare and standardize HCl solution. INTRODUCTION Standardization is a process of determining the relationship between the measured signal and the amount of analyte. Standardization can be defined also as a titration experiment in which the concentration of a solution becomes

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    2.3 Magnesia-Doloma Refractories: The MgO-CaO system is remarkable for the high liquidus and solidus temperatures over the complete range 100% MgO- 100% CaO‚ as the eutectic for the CaO–MgO binary system occurs at 2370 ºC [3‚ 52]. MgO–CaO bricks are high-value refractories composed of lime (CaO) and periclase (MgO). MgO –CaO refractories has some advantageous and disadvantageous compared to MgO and CaO refractories (Table 1). Table 1 Typically‚ these refractories are composed by 50-80 wt. % of

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    Hydrolysis of tert-butyl Chloride in different solvents Practical conducted on 5 March‚ 2013 Reported by Pham Vu Hung on 10 March‚ 2013  Introduction: This practical is meant to measure the rate of reaction of the hydrolysis of tertiary-butyl chloride –a colorless‚ liquid organic compound at room temperature that is sparingly soluble in water - in water/acetone and water/isopropanol mixtures. Since there are many influencing factors for the rate of reaction‚ all are kept constant but the

    Free Chemical kinetics Chemical reaction Solvent

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    PreLab assesment

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    of HCL that is neutralized by 30.5 mL of 0.50 M NaOH:  H30+ (aq) + Cl- (aq) + Na+ (aq) + OH- (aq) --> Na+ (aq) + Cl (aq) + H20 (l))  0.50 M means 0.50 mol/L --> 0.50m mol/mL you added 30.5 mL so:  0.50 *30.5 = 15.25 mmol NaOH.  This means there is also 15.25 mmol HCl in your original solution.  So there is 15.25 mmol / 25 mL --> 15.25/25‚0=0‚ mmol/mL --> 0‚61 mol/L  ANSWER: 0.61 M HCl  6. Calculate the molarity of 15 mL of NaOH that is neutralized by 38.8 ML of 0.20 M HCl 0.20 m HCL 0.20

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    5. Write a balanced reaction of zinc with HCl. 6. How many moles of HCl are needed to react completely with all of the zinc in a post 1982 penny? 7. In a procedure developed to determine the percent zinc in post 1982 pennies‚ 50 ml of an HCl solution was used to react (dissolve) all of the zinc in the penny. To ensure complete reaction‚ the solution contains twice as many moles of HCl that is actually needed. What concentration of HCl should be used? 8. In the scenario

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    Antacid Stomach Lab

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    results among the four brands we tested‚ with 0.011 mols of HCl. Introduction: Stomach acid‚ or gastric acid‚ is the chief cause of the discomfort associated with heartburn.

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    Aim: To react NaHCO3 with HCl to form NaCl and two other products and then calculate the mole relationships between NaHCO3 and NaCl and calculate a balanced equation for this reaction. Safety: • Wear safety goggles at all time • Handle all chemicals with care • Use equipment like tongs when handling warm/hot objects • If chemicals are spilt on self‚ wash off immediately • Stand at all times Hypothesis: The NaHCO3 will react successfully with the HCl and will form NaCl‚ H2O and

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    Water Analysis

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    of this experiment was to determine the pH level of an unknown HCl solution. While doing so‚ we would also be receiving a good and fundamental understanding of how to use modern lab equipment to determine the chemical and physical properties of water bodies. Method: Make sure safety gear is always on and equipment is always clean. Part 1- Direct Analysis by pH Test Kit We grab a 50ml beaker and obtain a sample of unknown HCl as said to do in the procedure section in page 3. A pH test kit

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