A PROPOSED STUDY ON THE EFFECTS OF MECHANICAL PRETREATMENT ON Ulva reticulata FOR THE PRODUCTION OF BIOETHANOL Presented to: The Chemical Engineering Department College of Engineering and Architecture Cebu Institute of Technology – University Cebu City‚ Philippines In Partial Fulfillment of the Requirements for the Course Chemical Engineering Research 1 Macapaz‚ Donald G. Lluz‚ Ian Rome C. Alqueza‚ Mary Anne A. Mangila‚ Jennifer Y. Miparanum‚ Cherry Pearl A. October 2011 A PROPOSED
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Name: _Leroy Johnson __________________________________ Date: ______________Comprehensive Study Guide. Test will only be Multiple choice 1. The feature that most clearly separates eukaryotes from prokaryotes is the presence of _______ in eukaryotic cells. A) ribosomes B) oxidative phosphorylation C) DNA molecules -D) a nucleus 2. Cytoplasmic organelles are - A) absent in prokaryotic cells; present in eukaryotic cells. B) present in both prokaryotic and eukaryotic cells
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gyMicrobiology: is a study of microorganisms (microbes‚ germs) and their activities Microorganism: An organism or a virus too small to be seen without a microscope (smaller than 0.5mm) Misconceptions of Microorganisms * All microorganisms are pathogenic (disease producing) FALSE * The majority of bacteria are harmless and beneficial TRUE Aspects of microbiology * Basic biological science * About living cell and how they work * About microbial diversity and their evolution
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reactions. Enzymes are produced in living cells and are involved in speeding up biochemical reactions. They have an active site to which specific substrate binds. They increase the rate of reactions by decreasing the amount of activation energy meaning that the barrier to a reaction is lower when an enzyme is being used. The combination of enzyme and substrate creates a new energy outline hence causing a decrease in the amount of activation energy.(Lesson 6.5 A Catalyst and the Rate of Reaction). Once
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lipids‚ carbohydrates‚ protein? Certain conditions are required for digestion. I will find that enzyme is required for digestion of lipids‚ carbohydrates‚ protein. There are many conditions that are necessary for digestion of lipids‚ carbohydrates‚ protein such as pH and enzyme and substrate. The test tube that digestion of lipids occurs in was test tube 1‚3‚4‚ test tube 2 there was no digestion because there was no enzyme. Test tube 1 was the fastest for digestion because the substrate‚pH and enzyme
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Lab: Growing Yeast This experiment will take two days to complete. Background Information: Yeast is a very important group of fungi. The common yeast used in baking bread grows very fast. The basic idea in this lab is that the yeast will use an energy source and in doing so‚ will produce carbon dioxide gas. You’ll measure the amount of carbon dioxide (CO2) released during the growth of yeast. The growth of the yeast stops when the energy source has been used up by the yeast and CO2 production
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Homework Title: Photosynthesis and Respiration 1) Define these terms and arrange them from smallest to largest: Ch 5 WIO #3 • Thylakoid membrane Answer: Thylakoid membrane is a compartment in a plant cell that has light pigment that carry out the photosynthesis process. • Chloroplast Answer: Chloroplast is a type of organelle found in plants and algae that carry our photosynthesis. • Reaction center Answer: Reaction center is where chlorophyll a molecule and other
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diversity and characteristic features; Viruses. Biochemistry: Biomolecules and their conformation; Ramachandran map; Weak inter-molecular interactions in biomacromolecules; Chemical and functional nature of enzymes; Kinetics of single substrate and bi-substrate enzyme catalyzed reactions; Bioenergetics; Metabolism (Glycolysis‚ TCA and Oxidative phosphorylation); Membrane transport and pumps; Cell cycle and cell growth control; Cell signaling and signal transduction; Biochemical and biophysical
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Introduction to Biochemistry (CHEM 501) Final Exam 12/17/2007 1. The anaerobic conversion of 1 mol of glucose to 2 mol of lactate by fermentation is accompanied by a net gain of: a) b) c) d) e) 1 mol of ATP. 1 mol of NADH. 2 mol of ATP. 2 mol of NADH. none of the above. 2. The conversion of 1 mol of fructose 1‚6-bisphosphate to 2 mol of pyruvate by the glycolytic pathway results in a net formation of: a) b) c) d) e) 1 mol of NAD+ and 2 mol of ATP. 1 mol of NADH and 1 mol of ATP. 2 mol of NAD+
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Title : Investigation of Action of Saliva and 3M Hydrochloric Acid in Two Carbohydrate Solutions Objective : To investigate the action of saliva and 3M hydrochloric acid in two carbohydrate solutions Results : Table 1: Observations Conclusions Solution A Benedict’s test : Initial blue solution changed to brick-red precipitate. Little amount of brick-red precipitate suspended in solution. The solution was translucent. Iodine test : Yellowish-brown remained the same. Abundant amount of
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