EXPERIMENT 1 COLLIGATIVE PROPERTIES OF SOLUTIONS Date: December 03‚ 2013 Locker 21 Members: Vanessa Olga Dagondon Christine Anne Jomocan Janica Mae Laviste Nablo Ken Menez A. TYPES OF DISPERSED SYSTEMS Results and Discussion The first part of the experiment aims to differentiate the different dispersion systems. In this experment‚ three systems are introduced: true solution‚ colloidal dispersion and coarse mixture. The said three systems are classified through a property of colloids known as the
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point trials that resulted in a melting point of 120°C to 122°C. The melting point range is small‚ which indicates a relatively pure substance. I did a mixed melting point trial to find out what substance I had. I used Benzoic Acid and Succinimide because they were the two substances in my melting point range. Just by comparing the characteristics of the two substances to my unknown‚ I assumed it to be Benzoic Acid. My unknown and Benzoic Acid had a fine‚ powdery texture to it‚ while Succinimide looked
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32 48 13 32 48 14 32 48 Ratio: 48:32=6:4=3:2=1.5 Conclusion: Answer the following questions in complete sentences‚ giving detailed explanations and support for each of your answers. 1. Explain in your own words what it means for a chemical system to be in the state of dynamic equilibrium. After a reaction has occurred for awhile at a given temperature‚ the forward and reverse reaction rate will eventually be equal. Although you may get this confused‚ the concentration may not be
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Introduction: The objective of this experiment is to become familiar with the methods of separating substances from one another using decantation‚ extraction‚ and sublimation techniques. Most materials in our surroundings are mixtures of two or more substances in which each substance retains its own chemical identity and therefore its own properties. Mixtures are either homogeneous or heterogeneous. Mixtures that don’t
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Experiment 1 Separation of Mixtures Summary of Principles: Most of the materials we encounter in everyday life are not pure substances. Many materials such as sand are formed from physical combination of various substances‚ and are called mixtures. Mixtures can be classified into homogeneous and heterogeneous. The purpose of this lab is to learn how to separate individual components from a mixture through decantation‚ filtration‚ distillation‚ and crystallization. Pre-Lab Questions: Attached
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stated that “for one thing‚ genes help control production of behavior relating chemicals. One suspect substance is the neurotransmitter serotonin.” Someone that has a chemical imbalance in the brain can cause depression and violence. Serotonin is chemical in our brain that controls ones mood. When a person is clinically classified as depressed he or she is prescribed to take serotonin to balance out the chemical imbalance that is causing these irrational mood swings. If we were to evaluate
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how matter is classified? Answer: * Pure Subtance * Mixture Q2(NCERT): What is meant by a pure substance? Answer: A sample of matter containing only one substance is called a pure substance. In other words all constituents of the substance are same in their chemical nature. Q3: What are the characteristics exhibited by a pure substance? Answer: 1. A pure substance contains only one kind of atoms or molecules. 2. It is perfectly homogenous 3. It has definite composition
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The Company………………………………………………….2 Overview of the Products……………………………………..3 Detailed Description of Work…………………………………………5 Chemical Analysis Group……………………………………..5 OJT Trainee Tasks…………………………………………….5 Testing Capabilities…………………………………………....5 CAG Activities…………………………………………………11 Incoming Inspection…………………………………..11 In-Process Monitoring………………………………..15 Qualification of New Chemicals…………………….17 Failure Analysis………………………………………18 Relation of Work to Studies………………………………………….19 Values Acquired/Reinforced………………………………………
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Chem Exam - ‘98 1. Solve the following problem related to the solubility equilibria of some metal hydroxides in aqueous solution. (a) The solubility of Cu(OH)2(s) is 1.72 x10–6 g/100. mL of solution at 25° C. (i) Write the balanced chemical equation for the dissociation of Cu(OH)2(s) in aqueous solution. Cu(OH)2 Cu 2+ + 2 OH – (ii) Calculate the solubility (in mol/L) of Cu(OH)2 at 25 °C. (1.72 x10–6 g/0.100 L)(1 mol/97.5 g) = 1.76 x10–7 mol/L (iii) Calculate
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is often endangered. Use of chemicals in food is rampant around Bangladesh with the proportion of adulterated food items in the market varying between 70 and 90 percent. Despite negative health impacts‚ countrywide drives against fake and adulterated food through operation of mobile courts and sprouting of ‘formalin free’ markets‚ the problem persists. The main objective of this paper is to examine the perception of the citizens (customers and sellers) towards chemical mixed hazardous products in
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