liquid (ethanol) on the solubility of KNO3 in water. The results of the investigation support the hypothesis that water‚ which exhibits greater polarity‚ is able to dissolve a greater mass of KNO3 at lower temperatures compared to tested concentrations of Ethanol ranging from 12.5% to 30%. Furthermore‚ the results of the graph 1 show correspondence to the dielectric constant of each solvent as both the starting solubility of the solubility curves and the dielectric constant of the solvent decreases
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INVESTIGATE FACTORS INFLUENCING THE SOLUBILITY OF SALTS Research question How does temperature affect the dissolving time of various salts.? Hypothesis I predict that with water of high temperature the salts will dissolve quicker. Controlled Variable Amount of water (solvent) Amount of salt used (solute) Type of cups taken and their sizes Independent variable Temperature of water Dependent variable Time taken for each salt to dissolve Material Required Measuring
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Lab 3: Solubility of Organic Compounds Objectives: Understanding the relative solubility of organic compounds in various solvents. Exploration of the effect of polar groups on a nonpolar hydrocarbon skeleton. Introduction: The solubility of a solute (a dissolved substance) in a solvent (the dissolving medium) is the most important chemical principle underlying three major techniques you will study in the organic chemistry laboratory: crystallization‚ extraction‚ and chromatography.
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Solubility and Functional Groups _______________________________________________________ You will recall from general chemistry that a solution has two components: the solvent‚ which is the substance present in greater amount‚ and the solute‚ which is dissolved in the solvent. Solubility is defined as the mass (in grams) of solute dissolved in 100 g of solute at saturation. Molar solubility is defined as the amount (in moles) of solute per liter of saturated solution. The solubility of one compound
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PRACTICAL # 3 Title: Solubility Product of Ca(OH)2 Aim: To find the solubility and the solubility product of calcium hydroxide. Theory: Define‚ with equation‚ the solubility product. Find‚ from literature‚ the solubility product of calcium hydroxide at 25oC. Experimental: Reagents: solid calcium hydroxide‚ water‚ 0.1 moldm-3 hydrochloric acid Apparatus: Procedure:
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Determination of g by Free Fall Raw Data: Time (ms) ± 0.01ms Height of release of ball from the sensor plate (cm) ±0.1cm Trial 1 Trial 2 Trial 3 Trial 4 Trial 5 0.0 0.00 0.00 0.00 0.00 0.00 15.0 180.05 179.36 178.74 180.26 180.23 30.0 244.33 244.21 244.71 243.88 245.87 45.0 300.72 301.29 300.59 301.43 301.70 60.0 348.68 348.39 348.77 349.12 348.35 75.0 390.27 390.77 389.58 391.19 390.43 This table below is the results obtained during the experiment in cm/ms. This table below is the results
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INTRODUCTION Many substances contain water molecules as a part of their crystal structure. We call such solids hydrates‚ and we call the bound water the water of hydration. A hydrate has a definite number of water molecules bound to each anhydrous salt unit. The formula of the hydrate copper(II) sulfate pentahydrate is CuSO4 · 5 H2O The dot indicates that the molecules of water are attached to the ions in CuSO4 by weak bonds. We can drive off the water of hydration by heating the hydrate. If blue
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Effect of Temperature on Solubility Lab Purpose: What is the solubility of minerals in water? What is the relationship between temperature and solubility? Hypothesis: If salt and sugar are each tested in water of varying temperatures‚ then salt and sugar’s solubility will increase as the temperature also increases. Materials: Two 250 mL beakers Tap water 100 mL graduated cylinder Hot plate Two petri dishes Glass stirring rod Salt Sugar Thermometer
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reactants and products are constant. In this experiment set up‚ the reaction between ethanoic acid and ethanol to produce ethyl ethanoate and water is a reversible reaction as shown by the following equation: CH₃COOH + CH₃CH₂OH↔CH₃COOCH₂CH₃ +H₂O The Equilibrium Law states that at equilibrium the ratio [CH₃COOCH₂CH₃][H₂O]/[CH₃COOH][CH₃CH₂OH] is constant at constant temperature. This ‚ Kc‚ is called the equilibrium constant for the reaction. AIM: To verify the Equilibrium Constant for an Esterification
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Determination of a Rate Law Megan Gilleland 10.11.2012 Dr. Charles J. Horn Abstract: This two part experiment is designed to determine the rate law of the following reaction‚ 2I-(aq) + H2O2(aq) + 2H+I2(aq) + 2H2O(L)‚ and to then determine if a change in temperature has an effect on that rate of this reaction. It was found that the reaction rate=k[I-]^1[H2O2+]^1‚ and the experimental activation energy is 60.62 KJ/mol. Introduction The rate of a chemical reaction often
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