Sample Term Test 2A 1. A variable X has a distribution which is described by the density curve shown below: What proportion of values of X fall between 1 and 6? (A) 0.550 (B) 0.575 (C) 0.600 (D) 0.625 (E) 0.650 2. Which of the following statements about a normal distribution is true? (A) The value of µ must always be positive. (B) The value of σ must always be positive. (C) The shape of a normal distribution depends on the value of µ. (D) The possible values of a standard normal variable
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slight blemishes. The table below displays a manager’s probability assessment of the number of blemishes on one piece of new furniture. Number of Blemishes 0 1 2 3 4 5 Probability 0.34 0.25 0.19 0.11 0.07 0.04 1. On average‚ how many blemishes do we expect on one piece of new furniture? 2. What is the variance of blemishes on one piece of new furniture? (round to the nearest hundredth) QUESTION 22 The probability that a person catches a cold during the cold-and-flu season
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1 Marks: 1 Assume that X has a normal distribution‚ and find the indicated probability. The mean is μ = 60.0 and the standard deviation is σ = 4.0. Find the probability that X is less than 53.0. Choose one answer. a. 0.5589 b. 0.0401 c. 0.9599 d. 0.0802 Question2 Marks: 1 Use the given degree of confidence and sample data to find a confidence interval for the population standard deviation. Assume that the population has a normal distribution. Weights of eggs: 95%
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Case Study - Hamilton County Judges Case (Chapter 4) Commom Pleas Court Q. 1Probibility of Cases Being Appealed and Q. 2 Probability of Q.3 Probability of Judge Reversed Appeal Rank Reversal Rank Fred Cartolano 0.04511 14 0.00395 Thomas Crush 0.03529 4 0.00297 Patrick Dinkelacker 0.03498 3 0.00636 Timothy Hogan 0.03071 2 0.00358 Robert Kraft 0.04047 10 0.00223 William Matthews 0.04019 7 0.00795 William Morrissey 0.03991 6 0.00726 Norbert Nadel 0.04427 13 0.00676 Arthur Ney Jr. 0.03883 5 0.00435
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2 Single Gene Inheritance WORKING WITH THE FIGURES (The first 14 questions require inspection of text figures.) 1. In the left-hand part of Figure 2-4‚ the red arrows show selfing as pollination within single flowers of one F1 plant. Would the same F2 results be produced by cross-pollinating two different F1 plants? Answer: No‚ the results would be different. While self pollination produces 3 : 1 ratio of yellow versus gene phenotype‚ cross pollination would result in 1 : 1 ratio‚ in
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process prioritizes risks according to their potential effect on project objectives. Qualitative risk analysis is one way of determining the importance of addressing specific risks and guides risk response measures Definitions of the levels for probability and impact and expert opinion help correct biases in the data used in qualitative analysis. Qualitative risk analysis should be reviewed during the project’s life cycle to stay current with changes in project risks. The process can lead to further
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Waterfall vs Agile Development A Director of IT Programs at a large Aerospace Defense contracting company has been asked to develop a financial system that allows the Program Managers for the company to do their Earned Value Analysis. The development of this system will allow the company to manage their programs more efficiently and maintain the Government certification of their Earned Value systems. If the company loses their certification the government can withhold 5% of their profits on
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cycle. D) termination stage of the project life cycle. Answer: D 5) The greatest project risk occurs when: A) the probability of the event is high and the consequences of the event are high. B) the probability of the event is high and the consequences of the event are low. C) the probability of the event is low and the consequences of the event are high. D) the probability of the event is low and the consequences of the event are low. Answer: A 6) The greatest project opportunity occurs
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given in the Repair time and Probability information table as found in the case. The created table was defined as “Lookup” in the array information for VLookup function in Microsoft Excel. Next‚ based on the probability information provided‚ a Cumulative Probability column was generated by adding the probability numbers given (each with the number above it) and distributing the probability to the number of possible repair days from 1-4. For example‚ a .20 probability
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whether or not the said Physical Education Captain is‚ in fact‚ unfairly manipulating the outcome. By the laws which govern classical probability‚ it can be said that the probability of a fair coin landing as heads or tails during a toss is 0.5. If a series of subsequent coin tosses are carried out and one outcome is being particularly favoured‚ therein lies the probability of the coin being fixed‚ or biased. This may be due to external factors‚ namely which hand was used to make the toss and which coin
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