pressure decreases the volume increases. But the volume only increases very little even though the pressure has dropped significantly. 2) Do you think there is a point at which volume cannot be decreased any further for this sealed container of gas? Explain your answer in terms of what you know about the properties and characteristics of gases. [5 points] I think that the higher the pressure gets‚ the less volume there is. Part II: Charles’s Law Data and Observations: Present all relevant
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METHODS 2.1. Nature of Reactants 2.1.1 We placed 3mL of 3 M HCl into each of 3 seperate test tubes. Next we added mossy zinc to the first test tubes‚ Sn granules to the second and Cu filings to the third and compared the rates of evolution of hydrogen gas in each test tube. 2.1.2. We mixed 3mL of 0.02 M KMnO4 and 2mL of 3 M H2SO4 in a test tube and stirred using a glass rod. Next‚ we divided the solution into two. We added 2mL of 0.03 M Na2C2O4 solution to the first half and 2 ml of H2O2 to the second
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Formulas: Write the following formulas. Ideal Gas Law Molar Mass Relationships: The Dumas Method - In 1826 Jean-Baptist Dumas developed a method for determining the molar mass of liquids that can be boiled under laboratory conditions. At that time the concept of the mole was not yet understood so Dumas studied the relative densities of the vapors by using Boyle’s‚ Charles’ and Avogadro’s Laws. In this experiment the ideal gas law will be utilized to solve for the number of
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Ejectors Give Any Suction Pressure Recent tests on multistage ejector systems will simplify your task of designing vacuum-producing equipment for any pressure. F. DUNCAN BERKELEY GRAHAM MANUFACTURING CO.‚ INC.‚ BATAVIA‚ N.Y. B ecause of overlapping performance‚ it’s often a lengthy problem to arrive at the most economical design of an ejector. In practically every new application of high vacuum‚ we find it necessary to investigate thoroughly the many available means of producing vacuum
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8m/s^2)= 4410 Pa (b) presure between B and A = P_B - P_A = hdg = (0.5 m - 0 m )(900)(9.8)= 4410 Pa (c) presure betwewn C and A = P_C - P_A = hdg = (0.5 m - 0 m )(900)(9.8)= 4410 Pa What is the gas pressure inside the box shown in the figure? Height difference between gas and mercury h = 16 cm –6 cm = 10 cm = 0.1 m P = Po + Dgh Where Po= atmospheric pressure = 1 atm = 101.3 * 10 ^ 3Pa D = mercury = 13600 kg / m^ 3Plug the values weget P = ( 101.3 * 10^ 3 Pa) + (13328 Pa) =
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SECTION - A 1. Name the technique to separate [1] (a) Salt from Sea – water (b) Butter from curd 2. Define velocity. [1] 3. What do you mean by free fall? [1] 4. Mention any 2 advantages of using Italian bee variety in honey production. OR (a) Identify soluble and solvent in the following solutions: [3] (i) Aerated drinks (ii) Tincture of iodine (iii) Lemon water (b) State the principle of each if the following methods of separation of mixtures
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TITLE Vapour Liquid Equilibrium OBJECTIVE To find the Vapour-Liquid Equilibrium (VLE) relationship for binary mixture and to plot the equilibrium curve. INTRODUCTION The term equilibrium is referred to as when a system is in a static condition and there is absolutely no changes that occur as time goes by. Vapour-liquid equilibrium is a condition where a liquid and its vapor are in equilibrium with each other‚ a condition or state where the rate of evaporation is equal to the rate of condensation
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SCB 12204 THERMAL SCIENCE LAB REPORT EXPERIMENT 5 Objective: To study the relationship between pressure and temperature of vaporization of water. Apparatus: 1. Stopwatch Picture 1 : stopwatch 2. Vapor pressure machine Picture 2: Vapor pressure machine Procedures: Picture 3 :general start up and shut down procedure 1. The general start up was followed. (picture 3) 2. Make sure the entire valves were closed. 3. After that main switch
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temperature the kinetic energy of the particles also increases KINETIC ENERGY The energy possessed by an object in motion is called kinetic energy Matter around us exist in three different states – solid‚ liquid and gas. PHYSICAL PROPERTIES OF MATTER SOLID LIQUID GAS CHEMICAL PROPERTIES OF MATTER ELEMENTS MOLECULES COMPOUNDS SOLID STATE We can observe that all these have a definite shape‚ distinct boundaries and fixed volumes‚ that is‚ have negligible compressibility. Solids
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Orsat Gas Analysis Experiment I. Objectives To analyze the dry exhaust gas (DEG) from a combustion system using the Orsat apparatus. II. Apparatus As shown in figure‚ the Orsat apparatus consists of a water-jacketed 100-m1 burette B connected at its top to a glass manifold M and at its bottom to a leveling bottle L. The glass manifold M is connected to three reagent bulbs called pipettes P1‚ P2 and P3 via three cocks C1‚ C2 and C3. Each tube is filed with its own absorbing chemical solution:
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