Date: 25th November‚ 2011 Aim: To show that when Hot and Cold water are mixed‚ heat lost by hot water is equal to heat gained by cold water. Theory: This Lab is done to demonstrate “the Law of Conservation of Energy”‚ which implies: - “the heat lost by one (1) substance must be equal to the heat gained by another substance within the system”. Apparatus: Two (2) similar Calorimeters: a Thermometer: a Measuring Cylinder: a Bunsen burner: a Tripod: an Asbestos Gauze Cork Mat. Procedure:
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Date of Experiment- 11/27/12 Date Report Submitted 11/27/12 Title: Caloric Content of Food Purpose: to be able to measure the energy content of foods Procedure: We are going to take food items and burn them to heat water to be able to determine the amount of “energy” a food source can emit. Data Tables: |Data Table 1: Food Item - Observations | |Food
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In part A of the experiment the two values obtained for the specific heat capacity of the metal were about .0500 J/mol. This is a large deviation‚ with both of these values identifying very different metals. The average heat capacity identified the metal used as brass. The average heat capacity calculated was .3776 J/mol and the actual heat capacity of brass is .375 J/mol. The second run displayed the closest value to the actual value. A source of error that may have caused a large divide in the
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Molar Heat of Combustion Aim: To find the molar heat of combustion for four different alkanols: 1. Methanol 2. Ethanol 3. 1-Propanol 4. 1-Butanol - And to compare the experimental value with the theoretical. Background: The Molar Heat of Combustion of a substance is the heat liberated when 1 mole of the substance undergoes complete combustion with oxygen at standard atmospheric pressure‚ with the final products being carbon dioxide gas and liquid water. (Ref. “Conquering Chemistry‚ Roland
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We can assume that the specific heat capacity of water is 4.18 J / (g × °C) and the density of water is 1.00 g/mL. qwater = m × c × ΔT m = mass of water = density x volume = 1 x 26 = 26 grams ΔT = T(mix) - T(water) = 38.9 - 25.3 = 13.6 q(water) = 26 x 13.6 x 4.18 q(water) = 1478 Joules SPECIFIC HEAT: qmetal = -205 J = 15.363 g X c X (27.2 - 100.3 C) c = 0.183 J/gC PART2. Using the formula qmetal = m × c × ΔT‚ calculate the specific heat of the metal. Use the data from your
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Calorimetry Lab Report Waris Butt PHY 112 Mr. Fasciano Class #18336 06/08/14 Purpose: Heat flow will occur between objects in contact until no more heat flow is detectable. Using calorimetry to analyze heat flow quantitatively and the equation: Q = mc ΔT‚ to determine the specific heat capacity of an object and heat flow from or to an object; respectively. Materials: Circle K 44 oz Styrofoam cup with lid Large Plastic
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Grade 11 physics: SPH3U1-01 | Physics Lab Report | Specific Heat Capacity of Brass | | Jin Jin Shi | 2012/12/6 | Instructor: Mr. Nailer | I. Introduction The amount of heat required to raise the temperature of a solid body depends on its change in temperature (ΔT)‚ its mass (m)‚ and an intrinsic characteristic of the material forming the body called specific heat (cp). The heat is calculated from the equation II. Purpose The purpose of this laboratory is to determine
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Experiment I: Thermochemistry Background: Thermochemistry is the branch of chemistry that focuses on the studies of chemical reactions or physical changes and heat associated with chemical reactions. According to the first law of thermodynamics‚ energy cannot be created or destroyed but it can be converted from one form into another and/or transferred between different atoms‚ molecules‚ or substances. In general‚ energy can be classified into two categories: kinetic and potential. Kinetic energy
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specific heat of solids 1. Introduction Heat capacity of a body is the quantity of heat required to raise the temperature of the body by 1oC. The specific heat of a substance is the heat capacity per unit mass. Thus‚ heat capacity = mass x specific heat. The specific heat is essentially a measure of how thermally insensitive a substance is to the addition of energy. Heat and temperature are really different quantities. Heat is a quantity of thermal energy‚ while temperature determines the
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EXPERIMENT AIM: To determine the experimental heat of combustion of methanol (CH3OH) and ethanol (CH3CH2OH). To decide which would be a better choice to take on a camping trip. MATERIALS: 1 Copper container 1 Clamp 1 Spirit Lamp with Wick Ethanol 1 Retort Stand Methanol 1 Box of Matches Water 1 Electronic Balance Thermometer PROCEDURE: Firstly‚ Measure the weight of the empty Copper container on the electronic balance. Record your results in a table. Secondly‚ fill the copper container with
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