of a component causes the equilibrium to shift to the side from which the component was removed. D. Is this reaction endothermic or exothermic? How do you know? When acid is added to water the reaction is strongly exothermic. Because the hydrogen ion is so tiny‚ a large amount of charge is concentrated in a very small
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uniform disk of radius R = 0.25 m has a string wrapped around it‚ and a m = 3 kg weight is hanging on the string. The system of the weight and disk is released from rest. a) When the 3 kg weight is moving with a speed of 2.2 m/s‚ what is the kinetic energy of the entire system? KETOT = KEwheel+KEweight = (1/2)(I)(w2)+(1/2)(m*v2) =(0.5* v2)(m+1/2M) =0.5*(2.2^2)*(3+(.5*15)) J b) If the system started from rest‚ how far has the weight fallen?
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ATOMIC WEIGHT OF MAGNESIUM LAB Introduction The main purpose for this experimental lab is to determine the atomic weight of magnesium‚ as well as an underlying purpose in determining the relationship between moles evolved and consumed. This can be demonstrated by measuring the hydrogen gas evolved by performing a chemical experiment when hydrochloric acid reacts with the magnesium. The formulated reaction includes; Mg + 2HCl → H2 + Mg2+(aq) + 2Cl- (aq) The major findings contributing
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Assessment of Catalase Function Lab Introduction The purpose of this lab report was to test and measure the rate of substrate destruction by an enzyme‚ we tested the destruction of hydrogen peroxide by the enzyme catalase. Hydrogen peroxide is a poisonous by product of metabolism that can damage cells if it is not removed. Catalase is an enzyme that speeds up the breakdown of hydrogen peroxide into water and oxygen gas. H2O2 + catalase → H2O + O2 A catalyst is a substance that lowers the
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puck of mass m initially at speed u collides head-on (without rotation) with a stationary puck of mass M. Find the velocities of both puck after the collision if: i) the collision is fully elastic ii) the collision if fully inelastic. i) momentum: kinetic energy: mu = mv+MV (+ve in direction of initial u) 1 /2 m u2 = 1/2 m v2 + 1/2 M V2 2 eqns in 2 unknowns: V = (u - v) m/M substitute in K eqn: u2 = v2 + (M/m) V2 = v2 + (M/m) (u - v)2 (m/M)2 = v2 + (u - v)2 (m/M) let ρ = (m/M) ⇒ v2 (1 + ρ) - 2ρ
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In this essay‚ it will be discussed how the Kinetic Molecular Theory explains many gas law specifically Boyle’s gas law‚ Charles’ gas law‚ and Avogadro’s gas law. To understand what will be talked about is to first know what the Kinetic Molecular Theory is. In our textbook is says it is “A simple model for gases that predicts the behavior of most gases under many conditions.” First off‚ we will take a look at Boyle’s Law. As stated in our lab manual “at constant temperature the pressure which a given
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Purpose Since there are two possible oxidation numbers for the iron nails‚ by this experiment we will need to determine the actual oxidation number of the iron in this experiment. Hypothesis As said in the introduction there will be two possible decomposition reactions: Fe (Ⅱ) + CuCl2 (aq) → Cu + FeCl2 2Fe (Ш) + 3CuCl2 (aq) → 3Cu + 2FeCl2 We can measure the mass of the two iron nails‚ and the copper after the reaction. Thus‚ we can compare the ratio of the mole and the mass of iron and copper. Procedure
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Organic molecules are the molecules of life that include Carbon and Hydrogen. Organic molecules consist of four important classes which are lipids‚ carbohydrates‚ proteins and nucleic acids. The most important organic molecule is Carbon. Carbon can form with up to 4 different atoms to form chains‚ rings and branches. Organic molecules also contain monomers. Monomers are the “building blocks” of macromolecules. Macromolecules are made up by chains of monomers‚ these are called polymers. Continuing
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of R Lab 3 Report must be typed and submitted to Turn it in by Wednesday Sept 24th 11:59pm. Title +1 Purpose +1 Procedure +2 Data Table +4x Balanced Chemical Equation +2 Calculations Calculate R for each trial and then average. +5 Calculate % error +2 Type and Answer Discussion Questions +8 Additional Questions for Calculating the R Lab 1. One mole of hydrogen gas has a mass of 2.02 g. Use your value of molar volume to calculate the mass of one Liter of hydrogen gas at
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2.5.1. Processing Steps of Hydrogen Production from LPG Conventional process for producing hydrogen from light hydrocarbons involves the following process steps: • Feed preparation • Sulfur removal • Steam reforming • CO shift conversion • Autothermal reforming • Process gas cooling • Synthesis gas purification (PSA pressure swing absorption) [5] 2.5.1.1. Sulfur Removal LPG feed first passes through an ambient temperature sulfur adsorption vessel
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