measurement of the ability of an aqueous solution to carry an electric current. In this lab we produced conductivity tests to discover the differences between molecules and ions of various solutions such as Glucose‚ Sucrose‚ Ethanol‚ Sodium Chloride‚ Calcium Chloride‚ distilled‚ tap‚ pond and ocean water. The main point of the experiment was to test the hypothesis which is that distilled water has a decreased conductivity than other solutions. We wanted to find out specific data on these solutions in
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Name SOLUBILITY CURVES Answer the following questions based on the solubility curve below. Which salt is least soluble in water .. at 2O° C? 2. How many grams of potassium chloride can be dissolved in 200 g of water at 80° C? IO 3. At 40° C‚ how much potassium _ __nitrate coin be dissoiu$tl ^n 30D.g of water? ------W- ’1 80 70 ...- O --60 0 5© 40 4. Which salt shows the least change 30 In solubility from 0° - 100° C? 20 10 At 30° C‚ 90 g of sodium
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Strength In our positive control group‚ the rate of fermentation is the highest (Figure 2)‚ and the sample solution (corn syrup‚ yeast‚ and calcium chloride) was used up before the cut-off time (45 minutes). By
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by metal ions or by ammonium ions. Compounds in which the H+ ions in an acid have been replaced by ammonium ions (NH4+) are called ammonium salts. NOTE: •An anion is a negatively charged ion. Hence:•Hydrochloric acid gives chlorides. E.g. sodium chloride‚ ammonium chloride. •Nitric acid gives nitrates. E.g. barium nitrate‚ copper nitrate. •Sulphuric acid gives sulphates. E.g. silver sulphate‚ iron (ii) sulphate. •Phosphoric acid gives phosphates. E.g. sodium phosphate‚ ammonium phosphate. •Each
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into a metal salt. (5) Dip your wire into a metal salt either the nitrate or chloride and place the wire onto the tip of the blue flame. (6) Observe the change in colour of the Bunsen burners flame and record the observations as you go. (7) As long as you clean the wire as directed in step 3-4 you can proceed into testing the other metal salts. QUESTIONS: Q1: Were there any main difference between the chloride salts and the nitrate salts? If there was please comment on what it was Yes‚
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on the metal ion. This experiment contains Ammonium chloride buffer which is an inhalation irritant. Procedure: About 500 mL of approximately 0.004 M disodium EDTA solution needed. The solution should have between 0.7–0.8 g of Na2EDTA and dissolve in about 500 mL deionized water in a plastic bottle. The bottled is Sealed and shaken vigorously for a few minutes to dissolve the salt. Standardize the Na2EDTA solution using a stock calcium ion solution as the primary standard. Using a 10-mL
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Rationale: Mobility increases lung function and oxygen circulation. (Treas & Wilkinson‚ 2014‚ p. 616). d. Medications (cont’d) Amlodipine: 10 mg = 1 tab‚ oral‚ qAM for 90 days Amlodipine is an antihypertensive/calcium channel blocker which works by inhibiting the transport of calcium into myocardial and vascular smooth
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" Soap Lab. Web. 31 May 2012. <http://course1.winona.edu/jfranz/Lab/soaplab.htm>. Appendices Figure 1: synthetic detergent when added with (from left) Ferum (II) chloride‚Magnesium (II) chloride‚ and Calcium (II) chloride Figure 2: soap when added with (from left) Ferum (II) chloride‚ Magnesium (II) chloride‚ and Calcium (II) chloride Figure 3: observation on cleanliness of cloth strip (from left) tape water‚ detergent‚ soap
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Analytical chemistry Analytical chemistry is the branch of chemistry that deals with the separation‚ identification and determination of components in a sample. Analytical chemistry can be divided into two branches‚ qualitative and quantitative. Qualitative analysis It deals with the identity of the constituents that are in an analytical sample. Quantitative analysis It deals with the determination of how much of a given substance is in the sample. The quantitative analyses are classified
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dish and Na2CO3 __1.4__g Net mass of the Na2CO3 __0.7__g Step 6: Mass of filter paper __0.7__g Step 10: Mass of filter paper and dry calcium carbonate __1.2__g Net mass of the dry calcium carbonate _0.5___g (This is the actual yield) Step 11: Show the calculation of the theoretical yield of calcium carbonate. The mole ration between CaCl2-.2H2O and CaCO3 is 1:1 that means that if we have 0.00680 moles of CaCl2-.2H2O we will get 0.00680 moles CaCO3
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