F3.3 – LIMITING FACTORS • a factor that causes popn growth to decrease • two basic types: 1. density-independent factors 2. density-dependent factors 1. Density-independent factors • an abiotic event that affects all popn’s in the same way‚ regardless of popn density • e.g. fires‚ earthquakes‚ storms‚ temperature extremes… 2. Density-dependent Factors • a biotic interaction that varies in its effect on popn size‚ depending on the density of the popn involved • have greater impact on denser popn’s
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Limiting Freedom Paige Shields Ethics: Freedom Seminar June 27‚ 2012 Abstract The federal government is take their role a little too far by limiting some of the simplest freedoms that have been given to the American people. The American people are being used by the government to create the “perfect” society in unjust and unethical ways. They are using things such as seatbelt policies that are costing more money than we could ever imagine‚ smoking in public to limit the
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regulations because of the pollution it was causing. Hart and Nelson debated to reinforce citizen’s rights in order to sue the EPA over bad enforcement of the proposed law. However‚ Poage was more concerned over the industries that will be affected by limiting pesticides. Poage called for indemnification for manufacturers whose pesticides are legally removed from the market. Hart and Allen were largely against giving
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There are times of the year when students begin to be exhausted‚ and it is because of all the homework they have to do. As they sit down and pull out their piles of homework‚ it rises to the ceiling. Moreover‚ incalculable of kids go to bed extremely late at night because of it. Teachers should limit the amount of homework they give out. Too much homework has negatively affected kids‚ especially when it causes a tremendous deal of stress‚ too much time is required to complete it‚ and it impacts
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Homework has become part of the school life of the students. Homework is a schoolwork that the student is required to do at home‚ this is what help to the students to practice what they had learned in class‚ but now we wonder if homework is a real contribution in the learning of the students. All students have homework for school and mostly of them are having a great amount of homework which leads to the student to not having time for extracurricular activities such an academic activities or sports
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Determining the Stoichiometry of Chemical Reactions Objective In this lab we took Fe(NO3)3 and NaOH and mixed 7 different mole ratios in graduated cylinders to determine what the mole ratio is. We also did the same thing with solutions of CuCl2 and Na3PO4. We determine the mole ratios by graphing the volume of reactant #1 vs. volume of precipitate for each reaction. Data Part 1.) Cylinder 1 2 3 4 5 6 7 Fe(NO3)3‚ 0.1 M‚ ml 5 10 12 15 17 20 24 NaOH‚ 0.1 M‚ ml 55 50 48 45
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Results: Limiting Reactant: Eq 1 Limiting reactant = Benzoin Theoretical yield of Benzil: Eq 2 Theoretical Yield Benzil | 0.296 g | Mass of Crude Benzil | 0.188 g | Mass of Final Benzil | 0.127 g | % Yield | 43% | % Recovery | 66% | Table 1: Mass of crude/final Benzil‚ % yield‚ and % recovery Percent Yield: % Yield = (Final product/Theoretical product) x 100 Eq 3 = (0.127 g/0.296 g) x 100 = 43% yield Percent Recovery
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The calculations completed for this experiment include determining the amount of Na2CO3 needed to do a full reaction. This was calculated through stoichiometry calculations: Molar mass was first calculated for CaCl2*2H2O Ca = 40.078g Cl2 = 35.453g*2 = 70.906g 2H2 = 1.00794g*4 = 4.03176g 2O = 15.9994g*2 = 31.9988g 40.078g + 70.906g + 4.03176g + 31.9988g = 147.01456g or 147.0 g CaCl2 1g CaCl2 * 2H2O x (1 mol CaCl2 *2H2O/147g CaCl2 *2H2O) = 0.0068 mol of CaCl2*2H2O Molar mass was then
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lab. Hint: H2CO3 is not a final product of the double-replacement reaction; it breaks down (decomposes) immediately into two products. (3 points) NaHCO3 + HCl → CO2 + H2O + NaCl 3. The NaHCO3 is the limiting reactant and the HCl is the excess reactant in this experiment. Determine the theoretical yield of the NaCl product‚ showing all of your work in the space below. (5 points) NaHCO3 – The Empty Dish 37.06 (grams) – 24.35 (grams) = 12.71 (grams) NaHCO3
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42.3 43.3 Mass of dry product 0.9 g 2.00 3.00 Calculations 1. Determine the limiting reagent for each trial. Show your calculations. (Hint: See the example in the Introduction.) Example: Trial 1: Note: These should be about the same and either CaCl2 or K2CO3 can be the limiting reagent depending on their initial masses. Trial 2: Table 3: Comparison of theoretical and actual yields for CaCO3 Trial # Limiting Reagent Theoretical Yield of CaCO3 Actual Yield of CaCO3 % Yield Trial 1
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