Week 10: Oxidation and Reduction Reactions: The Reactions of Copper Data: Part I: Preparing a solution of copper (II) nitrate Initial mass of copper wire: .520g Mass of copper wire after vigorously scouring: .518g Observations of Copper (II) ribbon mixed with HNO3: Solution turned green. Thick brown gas formed. Copper (II) bubbled vigorously. Cu (II) dissolved‚ solution appeared green/blue. After the addition of H2O a blue crusty precipitate formed. Part II: Synthesis of solid copper
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acid as a catalyst. The product was washed with sodium hydrogen carbonate‚ as well as with water‚ then dried with anhydrous sodium sulfate. The product was then distilled using a Hickman still and characterized using infrared spectroscopy. The percent yield of isopentyl acetate was 61.52%. This may have been low due to not all of the condensed product being removed from the Hickman still‚ some product being lost during transfer of the product from the reaction tube into the Hickman still‚ or the
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x 295.15 K = 0.00133 mol H2 ! ! ! ! 4. If magnesium was the limiting reactant in this lab‚ calculate the theoretical yield of the gaseous product. Show all steps of your calculation. (4 points) ! .032 g Mg * 1 mol Mg / 24.305 g Mg * 1mol h2 / 1 mol Mg = 0.0131 mol ! ! ! ! ! 5. Determine the percent yield of this reaction‚ showing all steps of your calculation. (3 points) ! ! Percent Yield = 0.00133 /0.0131 mol H2 × 100 = 10. 15 % ! ! ! ! ! ! Conclusion:
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either chemical as long as the plant is capable of producing both. BioPharma has forecast that its sales for the two chemicals are likely to be stable for all parts of the world‚ except for Asia without Japan‚ where sales are expected to grow by 10 percent annually for each of the next five years before stabilizing. The Japanese plant is a technology leader within the BioPharma network in terms of its ability to handle regulatory and environmental issues.
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Bromination of Acetanilide Objective: The objective of this experiment was to use melting point and NMR to determine which of two isomers‚ ortho or para‚ would most likely form after brominating Acetanilide through electrophilic aromatic substitution. Procedure/Observations: 1. Weigh out ~280 mg of acetanilide in a 10 mL r.b. flask with a stir bar. 2. Then‚ add 2.0 mL of glacial acetic acid using a calibrated Pasteur pipet. 3. Stir the mixture until all of the acetanilide has dissolved
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the organic layer (isoamyl acetate)‚ anhydrous sodium sulfate was added to dry it. Based on the results and observation obtained‚ we were able to synthesize isoamyl acetate and we were able to solve for its percentage yield by determining the limiting reactant‚ and theoretical yield. Keywords: Extract‚ Fischer reaction‚ Isoamyl acetate‚ Reflux‚ Synthesis Introduction Esters are a compound formed from a carboxylic acid‚ RCOOH‚ and an alcohol‚ R’OH [1]. They are most commonly known as a substances
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an esterification reaction between acetic acid and isoamyl alcohol‚ using concentrated sulfuric acid as a catalyst. The product was washed with sodium hydrogen carbonate‚ as well as with water‚ and then dried with anhydrous sodium sulfate. The percent yield of isoamyl acetate was 52.79%. The product was isolated using a combination of techniques – acid-base extraction‚ drying‚ and in special cases distillation. Introduction: The importance of banana oil as an artificial flavoring in the food
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Lab #4 The Synthesis of Organic Polymers CHM2123‚ Section C October 21‚ 2014 Introduction: Organic polymers are macromolecules that are composed of smaller molecules called monomers. There are two main groups of polymers: natural polymers and unnatural (synthetic) polymers. Natural polymers include proteins such as cellulose and starch and are a necessity for our existence. On the other hand‚ synthetic polymers such as the polycarbonate in our lab goggles
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1.TITLE: To prepare isopentyl acetate (isoamyl acetate) 2. AIM: To make an ester referred to as banana oil from acetic acid and isopentyl alcohol 3.THEORY: This ester is often referred to as banana oil‚ since it has the familiar odor of this fruit O O CH3 H+ CH3 CH3C OH +
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Actual: Melting pt (or bp) 81-83 C N/A Literature: 312-315 C N/A Experimental: Percent Yield Calculation: Limiting Reagent: 1 mg= .001 g‚ 100 mg= .1 g vanillin Moles vanillin = .1g/152.15 g/mol= 6.57x10^-4 moles Density H2O2= 1.45 g/mL Mass H2O2= 1.45 g/mL x .75mL = 1.088g Moles H2O2= 1.088g/34.015 g/mol =.032 moles Limiting reagent = Vanillin Theoretical Yield: 1 mol Divanillin= 2 moles Vanillin Moles divanillin= .5 mol vanillin= 6.57x10^-4 mol/ 2 = 3.29x 10^-4
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