driving force for diffusion is You correctly answered: b. the kinetic energy of the molecules in motion. 2. In diffusion‚ molecules move You correctly answered: a. from high concentration to low concentration. 3. Which of the following dialysis membranes has the largest pore size? You correctly answered: d. 200 MWCO 4. Avogadro’s number is a constant for the number of You correctly answered: b. molecules. 09 Post-lab Quiz Results You scored 100% by answering 4 out of 4 questions correctly
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tube was placed within a 200mL beaker filled with distilled water and paced on a stir plate. A wavelength of 420 nm was chosen while recording the absorbance intensity of glucose‚ while a wavelength of 600 nm was chosen for starch as the respective molecules absorb most efficiently at these wavelengths. C1 is the concentration of glucose or starch in the internal solution and C2 is the concentration of glucose or starch in the external solution. Glucose durat ion of dialy sis (min) *Starch A420 Inter
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of Large Molecules.” Anal. Chem. 55‚ (1983)‚ 353-356. 11. Ross Willoughby‚ Ed Sheehan‚ Sam Mitrovich. “A Global View of LC/MS” Global View Publishing. 1998‚ 297-324 12. http://www.sisweb.com/referenc/source/exactmaa.htm 13. Reg Davis‚ Martin Frearson. “Mass Spectrometry” John Wiley and Sons 1990‚ 15-22 14. Susana Grimalt‚ Óscar J. Pozo‚ Jose M. Marín‚ Juan V. Sancho‚ and Félix Hernández. “Evaluation of Different Quantitative Approaches for the Determination of Noneasily Ionizable Molecules by Different
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Name two properties of this polymer. e) Name two uses for this type of polymer. 4. a) What is addition polymerisation? b) Polyethylene is an example of an addition polymer. Describe what happens to the ethene molecule during this process. c) The mechanism of addition polymerisation consists of three steps. Name each step and give a brief description of each. 5. a) What is condensation polymerisation? b) Where is condensation polymerisation
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Even though Avogadro acknowledged its existence such as hydrogen (H2) and oxygen (O2)‚ most workers still believed that diatomic molecules could not exist as charges repelled. Therefore‚ Avogadro’s Law was opposed by most chemists and did not get any spotlight for almost 50years. However‚ through different experiments there were some gaseous reactions that could not be explained without
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two non metals‚ that involves sharing pairs of electrons between atoms. Here is an example. Four atoms of hydrogen And one carbon atom And they combine together to create methane. Four pairs of electrons are shared in a methane molecule (CH4) (crosses) Each of the bonds represents a shared electron pair‚ these atoms bond due to the electrostatic attraction between the positive nuclei and the negative electrons
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the hygroscopic compounds the experiment allowed for the exploration of separation of hydrogen bonds to ionic solids through the use of heat. The reason that the water clings to the ionic compounds is due to its polarity‚ which causes the water molecules to get trapped inside of the compound and integrating into the crystal structure.
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Contents PART XV ANALYTICAL CHEMISTRY Chapter 63 Detecting the presence of chemical species Action of heating solid sample strongly 1 Chapter 64 Separation and purification methods Centrifugation Sublimation Partition equilibrium of a solute between two immiscible solvents Two-dimensional thin-layer chromatography 2 2 3 6 Chapter 65 Quantitative methods of analysis Detection of end point in acid-alkali titration 8 Chapter 66 Instrumental analytical methods More
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iron atoms and 3 oxygen atoms. (The subscript number‚ such as the two in O2 describe how many atoms of an element are in a molecule.) This unbalanced reaction can’t possibly represent a real reaction because it describes a reaction in which one Fe atom magically becomes two Fe atoms. Therefore‚ we must balance the equation by placing coefficients before the various molecules and atoms to ensure that the number of atoms on the left side of the arrow corresponds exactly to the number of elements
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were studied as well in this experiment helping us understand how the various molecules and its ions react in solvents. An example of this process is when calcium chloride dissolved in water. The polar water molecules attracted the oppositely charged Ca2+ and Cl- ions as calcium chloride is a polar molecule as well. The ions brake apart as the water attraction is greater than the ionic bond within the calcium chloride molecule. Solubility is also important for conductivity as some elements such as calcium
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