Redox potential – CV Acetonitrile Adjusted sensitivity Each ;line represents diff scan rates all been overlayed on one digarm Scan rates ranged from 0 .1 s-1 to 1 Peak due to iodide oxidation is read from +peak to – peak bottom line. Iodide to triiodide Glycol Didn’t work Using equation ip = 2.69 ×105 n3/2 A D1/2 C ν1/2 compare to linear equation y = mx+c y = peak current x = V1/2 c = zero Therefore m is = everything else C = concentration 0.05 M ethylene glycol (acetonitrile
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NAME: Aleema Chelsea Chinchamee LAB PARTNERS: Karishma Ramrattan‚ Vishma Ramsumair and Sharona Badree ID #: 814003081 DATE (of lab session): Tuesday 24th March‚ 2015 DEMONSTRATOR: Maurissa Course Code & Title: BIOL 1362- Biochemistry I Title of Lab: Investigating Enzymatic Activity in Sweet Potato‚ Irish Potato Extract and Milk. Aims: 1. To determine the effect of ascorbic acid on Polyphenol Oxidase (Phenolase). 2. To determine the level of specificity of Phenolase using the
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Alcohol C2H5OH + HCl + ZnCl2 C2H5Cl + H2O Isopropyl Alcohol (CH3) 2CHOH + HCl (CH3) 2CHCl + ZnC2 + H2O Tert-butyl Alcohol (CH3) 3COH + HCl + ZnCl2 (CH3) 3CCl + ZnCl2 +H2O Benzyl Alcohol C6H5CH2OH + HCl + ZnCl2 C6H5CH2Cl +ZnCl2 +H2O B. Oxidation of Alcohols Test Sample Equation Ethyl Alcohol C2H5OH + KMnO4 CH3COOH + H2O + MnO2 +K+ Isopropyl Alcohol 2(CH3)2CHOH + KMnO4 2(CH3) 2CO + 2H2O + MnO2 + K+ Tert-butyl Alcohol No reaction Benzyl Alcohol C6H5CH2OH + KMnO4 C6H5COOH + H2O +MnO2
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“CLONING OF HORSE RADISHPEROXIDASE GENE IN E.coli FOR EXTRACELLULAR EXPRESSION” Project report submitted to Jawaharlal Nehru Technological University Hyderabad in partial fulfillment for the award of degree of Bachelor of Technology in Biotechnology Submitted by M.RAVI TEJA (08311A2338) & V.MAYURI (08311A2358) Under the Guidance of DR.CHAND PASHA Department of Microbiology Osmania University [pic] Department Of Biotechnology SREENIDHI INSTITUTE OF SCIENCE AND TECHNOLOGY Yamnampet
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Chemistry 217 Dr.Rudolf Rednose Tues/8am/S-473 Determining the Percent Oxygen in the Air INTRODUCTION: Recent tragedies in coal mines have exemplified the importance for us humans to breathe an adequate amount of oxygen if we are to survive. But what amount of oxygen is adequate? How can we know the amount of oxygen present in what we consider fresh air? The purpose of this experiment was to determine the percent oxygen typically present in air. The conclusion of the test suggested that
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Clays are one of the important natural materials‚ which have been examined for catalytic applications. Clays are characterized by a layered structure and hence they are slippery when wet. They are broadly classified as cationic or smectite type (having layer lattice structure in which two-dimensional oxyanions are separated by layers of hydrated cations) and anionic or brucite type (in which the charge on the layer and the gallery ion is reversed complimentary to smectite type). Anionic clays are
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Chemical Reactions Chemical Change • reorganization • original substances form new substances with different formulas • may or may not involve a change of state • symbols used to describe chemical reaction are known as a chemical equation • Chemical equations do not have equal signs (=) they have an arrow Chemical Equations • Must follow the Law of Conservation of Matter • atoms can neither be created or destroyed during a chemical reaction • What
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chain respectively. The Krebs cycle uses the two pyruvates produced in glycolysis to make 2 ATPs per glucose and energy. This occurs through the oxidation of a pyruvate‚ wherein one of the three carbons will bond to oxygen and leave the cell as carbon dioxide (CO2)‚ leaving a two-carbon molecule called acetyl coenzyme A.
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put it through a series of reactions that change it¡¦s state of matter and chemical formula‚ but in the end‚ we will return it to it¡¦s normal solid state. Determine the percentage yield (quantitative). Define what happen at level of electron for oxidation/reduction‚ double replacement‚ neutralization and decomposition. There are five reactions that the copper will go through. 1. Cu(s) + 4HNO3(aq) --- Cu(NO3)2(aq) + 2H2O(aq) + NO2(aq) 2. HNO3(aq) + NaOH(aq)--NaNO3(aq) + H20(l) 3. Cu(OH)2(s)--CuO(s)
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Primary alcohols undergo oxidation to form carboxylic acids in two stages‚ it forms an aldehyde and then to the acid. In this experiment‚ we are used to prepare benzoic acid from benzene. Potassium permanganate is used this operation as an oxidizing reagent‚ it is used to oxidize the benzoic acid as well as acting as a catalyst for the reaction. Potassium permanganate (KMnO4) is a very strong oxidant which is able to react with many functional groups‚ such as secondary alcohols‚ 1‚2-diols‚ aldehydes
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