CE 371 HOMEWORK 2 1) Find the difference in pressure between tanks A and B if d1=300mm‚ d2=150mm‚ d3=460mm‚ d4=200 mm and S.GHG =13.6 w=9.80 kN/m3 2) Determine the elevation difference‚ h‚ between the water levels in the two open tanks shown in the figure. w=9.80 kN/m3 3) An air-filled‚ hemispherical shell is attached to the ocean floor at a depth of 10 m as shown in the figure. A mercury barometer located inside the shell reads 765 mm Hg‚ and a mercury U-tube manometer designed to give the
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On June 19th‚ 1623 in Clermont‚ France Blaise Pascal was born. Out of four children he next to last to be born‚ and was the only boy . When Blaise was just a couple of years old he mother died‚ and got really close to his sisters. His father was a judge in his home town‚ though he moved to Paris to pursue his personal scientific studies‚ and to teach his son‚ who was a child prodigy in 1631. Etienne‚ his father wanted Blaise to be able to seek out his own curiosity‚ though some people think that
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Jack’s heart pounds as he casts panicked looks around the classroom. He doesn’t recognize the professor‚ he doesn’t know any of the students‚ and he can’t even figure out what the subject is. In front of him is a test. At the very last minute his roommate awakens him. It’s only another anxiety dream. The very fact that dreams like Jack’s are common suggests that college is a stressful situation for young people. The cause of this stress can be academic‚ financial‚ and personal. Academic stress
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Salvation The young Langston Houghes was pressured into believing in Jesus by the church who is responsible for his loss of faith. Langston was in his aunt’s church were a revival was being held “to bring the young lambs to fold…” Langston along with the other “young lambs” were all placed on the mourners’ bench on the front row. Each child one by one accepted Jesus until Langston was last. Langston eventually stood and claimed to have seen Jesus. Langston’s church was responsible for Langston’s
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Knife Gate Valves for Pulverized Fuel application Standards applicable:NFPA 8503 – Standard for Pulverized Fuel Systems –1997 Edition – is Obsolete and consolidated in NFPA 85 – Boiler and Combustion Systems Hazards Code – 2001 Edition (NFPA 85 is consolidation of NFPA 8501‚8502‚8503‚8504‚8505 &8506) Clauses applicable for Knife Gate valves for pulverized fuel application in NFPA 85 :1.3.171 1.3.171.1 Valve Barrier Valve – A valve‚ not necessarily gas tight‚ used to inhibit hot gases from traveling
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Boyle’s Law 1.Example #1: 2.00 L of a gas is at 740.0 mmHg pressure. What is its volume at standard pressure * (740.0 mmHg) (2.00 L) =(760.0 mmHg) (x) * X =(740 mmHg) (2.00L) / (760.0 mmHg) Answer : 2. 5.00 L of a gas is at 1.08 atm. What pressure is obtained when the volume is 10.0 L? * 1.08 atm) (5.00 L) =(x) (10.0 L) * X = (1.08 atm) (5.00 L) / (10.0 L) Answer: 3. 2.50 L of a gas was at an unknown pressure. However‚ at standard pressure‚ its volume was determined to be 8.00 L. What was
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School of Technology‚ Energy and Apprenticeship Instrumentation Control & Electrical Technology (ICET) ICS3305 – F2013 Classroom Exercise # 3 (Process variable Review) PRESSURE CONVERSION TABLE mH2O mH2O psi inHg mmHg mbar Pa 1 0.70307 0.34532 0.01359 0.01019 0.000102 psi 1.42233 1 0.49115 0.01934 0.0145 0.00015 What is the absolute pressure equivalent to 150 psi_g in psi_a? inHg 2.8959 2.03602 1 0.03937 0.02953 0.000295 mmHg 73.55592 51.71493 25.4 1 0.75006 0.0075 mbar 98.0665 68.9476 33
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Kinetic theory of gases Question: How does odor travel from one place to another? Kinetic theory of gases A gas is composed of atoms or molecules The gas particles are in constant random motion Kinetic energy is transferred between particles as they collide Pressure The force exerted per unit of area Formula: pressure/force area Measured by barometer A vacuum is empty space‚ with no particles or pressure. Atmospheric pressure is the collision air particles with objects Units of
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Chapter 3 Pressure Measurement Examples Example 3.3 A special high pressure U tube manometer is constructed to measure pressure differential in air at 13.8 MPa and 20oC. When an oil having a specific gravity of 0.83 is used as the fluid‚ calculate the differential pressure in N/m2 that would be indicated by a 135 mm reading. p − pa = m g h( gc m − f ) = (0.83)(1000) = 830kg/m 3 = = p 13.8 × 10 6 = f a RT (287)(293) g h( m − f ) p − pa = gc = 9.81(0.135)(830 − 164.11) = 881.51N/m 2 Example
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"fluid mechanics lab" Experiment number "1" (bourdon gauge apparatus) Report date: 20/2/2011 Delivered date:27/2/2011 Submitted by: Eyyass Bassam Hamdan Major: mechanical engineering Student number: 30815150521 To Doctor : Abd-el hadi Lecture time: Sunday‚ 8-11 Summary: In this experiment we are going to measure the pressure of gage and absolute by using a dead weight device which it use bourdon tube to measure the pressure. Introduction: We are going
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