Biology Controlled Assessment. Kenishia Pascal 10x3. Investigating How Different Concentration Effects The Rate Of Reaction. Strategy A Possible Factors * Source of catalase * Concentration * Surface Area of enzyme * Concentration of enzyme * pH * Temperature Chosen Factor We chose to investigate the concentration of enzyme as we had previously investigated the optimum temperature for catalase in the preliminary investigation. Concentration of enzyme
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Abstract: The purpose of this lab was to use potentiometry to measure the concentration of a specific chemical species in a solution. This was conducted in 2 stages. The first stage involved making a solution of potassium iodide. The potassium iodide was then diluted to several different concentrations that were ran in potentiometer to find the mV of each solution which would then be used to find the PH of the solution. After analyzing a sample of each concentration an unknown solution was compared
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Hydrogen Summary * This is how hydrogen fuel cells work: 1. Gas stored in tanks 2. Atoms reach anode 3. Become hydrogen ion and a free electron 4. Ion goes through electrolyte layer 5. Hydrogen ion passes‚ but free electron does not 6. Free electron runs through external circuit from anode (-) to cathode (+) 7. Current of electrons creates electricity 8. Hydrogen ion enters cathode and combines with oxygen to become water which is better for the ecosystem because
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There are three reactions in the iodine clock reaction. The first reaction is IO3-(aq) + 3 HSO3-3 SO4-(aq) + I-(aq)+ 3 H+(aq)‚ where the iodate ions become iodide ions1. The second reaction is 6 H+(aq) +IO3-(aq) + 5 I-(aq) 3 I2(aq) + 3 H2O(l) where the iodate ions become molecular iodine2. The third reaction involves molecular iodine becoming a dark blue starch;I2(aq) + starch blue-black complex3. These three reactions react in a sequence. In any reaction the concentration is exponentially related
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Determining Order from Rates of Reactions AP Chemistry Purpose The focus of this experiment is to recognize that when aqueous solutions of potassium iodate ion (KIO3-) and bisulfite ion (HSO3-) are mixed‚ a series of reactions will occur‚ and the final reaction is signaled by the appearance of a dark blue color. My partners and I investigate how the concentration of the reactants affects the rate of reaction. The purpose of this lab is to find
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A salt with this anion is sometimes called an acid oxalate‚ monobasic oxalate‚ or hydrogen oxalate. The equilibrium constant (Ka) for loss of the first proton is 5.37×10−2 (pKa = 1.27). The loss of the second proton‚ which yields the oxalate ion has an equilibrium constant of 5.25×10−5 (pKa = 4.28). These values imply that‚ in solutions with neutral pH‚ there is no oxalic acid‚ and only trace amounts of hydrogen oxalate.[1] The literature is often unclear on the distinction between H2C2O4‚ HC2O4-
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Synthesis and Decomposition of Zinc Iodide Partners: Sonya Pasia and Kristen Kobayashi CH 085-01 20 September 2011 Zinc Iodide (ZnI2) was an interesting binary compound to experiment with. In this experiment‚ weakly acidified water (25mL distilled water with 18 drops 5M acetic acid solution) was used as an aid to bring molecules of the zinc and iodide atoms together‚ by dissolving iodine molecules‚ so that bonding would transpire to produce a reaction. Deprived of water‚ the Zn and I2 molecules
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3A Task 1 Aim: the aim of the experiment is to find the best temperature to ferment yeast at. Hypothesis: the yeast will ferment the best at 60 degrees Celsius. Independent variable: the temperature of the water the yeast is put in to ferment. Dependent variable. The amount of air bubbles the yeast produces. Controlled variable: the amount of yeast and glucose in each syringe. Uncontrolled variables: human error in counting. Materials : Plastic soft drink bottle cut to size Marking pen
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exchange of positive and negative ions between reacting solutions of two ionic compounds. Thus‚ in this example the precipitate must be either silver chloride‚ AgCl or sodium nitrate‚ NaNO3. Sodium nitrate dissolves readily in water and is therefore soluble. Thus we can conclude that silver chloride is the insoluble precipitate. We can represent the formation of this precipitate by a net ionic equation: Ag+ +NO3 ̄ +Na++Cl ̄→AgCl+NO3 ̄+Na+ Net: Ag+ (aq)+Cl ̄ (aq)→AgCl(s) Ions present in the solution but
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Testing for Ions Analysis Chemical Changes of Test Solutions Test Solution Silver Nitrate Barium Chloride Potassium Thiocyanate Sodium Sulfate - Stayed white in color - Turned cloudy in color - Precipitation formed in solution - Stayed white in color Potassium Chloride - Turned cloudy in color - Precipitation formed in solution - Stayed white in color - Stayed white in color Iron (III) Nitrate - Stayed orange in color - Stayed orange in color - Changed color from orange
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