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    Nu 545 Exam 1 Study Guids

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    |Unit 1:The Cell/Genes & Gene-Environmental Interaction/Mechanisms of |This unit will cover Chapters 1-3 & Chapters 6-10 in your McCance & Huether | |Self-Defense |text. | |Study Guide Unit 1 | NU 545 |

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    receptor proteins are intracellular proteins‚ or protein fractions‚ that have a high specific affinity for binding a known stimulus to cellular activity. Receptor proteins may be located at cell surfaces or within the interior of cells. They may detect hormones or instead keep track of what otherwise is going on in cell ’s environment. They may be enzymes or serve to relay the occurrence of signal reception in other ways such as by opening up ion channels. Receptor proteins are often targets for drug

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    Social interactions between cells are absolutely necessary. Possibly the most fundamental social interaction is those that hold cells together. Cohesion between cells is essential to form organized multicellular structures‚ that can respond and withstand various external forces that mean to pull them apart. Cell cohesion is governed by a complex network of proteins and polysaccharide chains. These mechanisms of cohesion govern the architecture of the body and the making and breaking of these attachments

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    channels and enzymes and assisting in trafficking of proteins to the cell membrane (5‚ 8). Why is PIP2 then so important in hippocampal cells? PIP2 is a substrate for hydrolysis by the enzyme phospholipase C (PLC)‚ whereby the products of this interaction are the secondary messengers‚ diacyl Glycerol (DAG) and inositol trisphosphate (IP3) (6‚ 8) that are involved in the regulation of physiological processes on the plasma membrane including calcium mobilisation‚ which all contribute to mediation of

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    Study Guide Science

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    Chemistry of Life 25% Lecture 4 – Biological Molecules 25% Lecture 5 – The Cell 20% Lecture 6 – Cell Membranes Example Question 1. White blood cells are responsible for engulfing and digesting foreign objects such as bacteria and viruses. What organelle do you expect them to have a relatively large amount of? A) Lysosome B) Ribosome C) ER D) Golgi apparatus E) Mitochondria 2. 3. This type of cell junction seals cells together into watertight sheets. A) Microtubules B) Desmosomes C) Tight

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    Patho

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    ____ 1. Eukaryotic cells are characterized by a lack of a distinct nucleus‚ whereas prokaryotic cells have intracellular compartments bordered by membranes and a well-defined nucleus. ____ 2. Lipids and proteins are the major components of the plasma membrane. ____ 3. Lysosomes remain fully active by maintaining an acid pH created by pumping hydrogen ions into their interiors. ____ 4. The chief function of ribosomes is to provide sites for lipid synthesis. ____ 5. If cells are deprived of

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    Mr Teenoh

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    laboratory you will investigate the effect of solute concentration on water potential as it relates to living plant tissues. OBJECTIVES Before you begin this lab you should understand: - the mechanisms of diffusion and osmosis and their importance to cells - the concept of water potential - the relationship between solute concentration‚ pressure potential and the water potential of a solution - the concept of molarity and its relationship to osmotic concentration **also read the section on water potential

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    Golgi Apparatus

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    vesicles composed of membranes from the ER‚ so it can inspect them for flaws and discard any extra materials added during their manufacture‚ wraps them up and then targets them for packaging. The Golgi complex is especially active in processing proteins for secretion. The Golgi releases a special enzyme called lysosomes‚ which clean off any extra amino acids‚ and once the package is ready‚ it is pinched off the Golgi and released into the cytoplasm. Once the Golgi apparatus membrane buds off and forms

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    Investigating the effect of temperature on the permeability of the plasma membrane of beetroot tissue. Aim- To determine the temperature at which the beetroot plasma membrane is destroyed by heat. Table of results: Temperature of water bath(degrees Celsius) Absorbance(au) (+ or – 0.06au) Repeat 1 Repeat 2 Repeat 3 Mean of results. 30 0.5869 0.6029 0.5946 0.5948 40 0.4161 0.4436 0.7056 0.4298 50 0.4343 0.4077 0.4137 0.4185 60 0.3486 0.4466 0.7991 0.3976 70 1.0500 0

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    Determining the Rate of Osmosis with Water and Sucrose 10/3/2012 Determining the Rate of Osmosis with Water and Sucrose Author: Results: Bag 1 had a rate of osmosis equal to 0.01 grams per minute. Bag 2 had a rate of osmosis equal to 0.0543 grams per minute. Bag 3 had a rate of osmosis equal to 0.0471 grams per minute. Bag 4 had a rate of osmosis equal to 0.0886 grams per minute. Bag 5 had a rate of osmosis equal to -0.0914 grams per minute (Figure A). Figure A: Shifting of mass

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