"Tert butyl chloride" Essays and Research Papers

Sort By:
Satisfactory Essays
Good Essays
Better Essays
Powerful Essays
Best Essays
Page 13 of 50 - About 500 Essays
  • Better Essays

    Organic Chem

    • 938 Words
    • 4 Pages

    Separating the Layers o Drying Agents o Part 1: The Technique of Neutral Liquid/Liquid Extraction The description is for dichloromethane-aqueous solution mixture‚ but you will use the same technique for your tert-butyl methyl ether-aqueous solution mixture. Note‚ however‚ that the ether is less dense than water‚ while dichloromethane is denser than water. o Part 2: Acid/Base Liquid/Liquid Extraction (p.147-150 middle) 2) THIS HANDOUT: Scheme

    Premium Acetic acid Carboxylic acid Acid

    • 938 Words
    • 4 Pages
    Better Essays
  • Better Essays

    Liquid Sublimation

    • 3624 Words
    • 15 Pages

    ------------------------------------------------- Liquid–liquid extraction From Wikipedia‚ the free encyclopedia Liquid–liquid extraction also known as solvent extraction and partitioning‚ is a method to separate compounds based on their relative solubilities in two different immiscible liquids‚ usually water and an organic solvent. It is an extraction of a substance from one liquid into another liquid phase. Liquid–liquid extraction is a basic technique in chemical laboratories‚ where it is performed

    Premium Acetic acid Solubility Solvent

    • 3624 Words
    • 15 Pages
    Better Essays
  • Good Essays

    Separating Acids and Neutral Compounds by Solvent Extraction Introduction The purpose of this experiment was to use solvent extraction techniques in order to separate a mixture consisting of a carboxylic acid (p-toulic acid)‚ a phenol (p-tert-butylphenol)‚ and a neutral compound (acetanilide). Extraction is the process of selectively dissolving one or more of the compounds of a mixture into an appropriate solvent‚ the solution that contains these dissolved compounds is called an extract (Manion

    Premium Chemistry Solubility Solvent

    • 1456 Words
    • 6 Pages
    Good Essays
  • Good Essays

    Competing Nucleophiles Lab

    • 2607 Words
    • 11 Pages

    808-823‚ pp 836-842) Purpose: The purpose of this experiment is to determine the nucleophilic strength of chloride and bromide ions as it reacts with 1-butanol (n-butyl) and 2-methyl-2-propanol (t-butyl alcohol) under SN1 and SN2 conditions. Method: 40 g of ice and approximately 30 ml of sulfuric acid is cautiously added to a 100 mL beaker respectively. Weigh 7.6 g of ammonium chloride and 14.0 g of ammonium bromide and place it in another beaker‚ crushing the lumps until a powdery mixture

    Premium Nuclear magnetic resonance Nucleophile Chromatography

    • 2607 Words
    • 11 Pages
    Good Essays
  • Satisfactory Essays

    Boiling Point

    • 543 Words
    • 3 Pages

    BOILING POINTS AND MELTING POINTS PART 2 Name: Grethel Zegarra Date of Lab: October 26‚ 2010 Date lab is due: November 2‚ 2010 HYPOTHESIS The boiling point in degrees Celsius will increase as the number of carbon atoms increase. The melting point of the unknown will indicate its mixed substances. The boiling point will increase as a result of the different branching of the OH‚ the melting point will be affected by the different positioning of the OH on the benzene ring. PURPOSE To introduce

    Premium Temperature Carbon Organic chemistry

    • 543 Words
    • 3 Pages
    Satisfactory Essays
  • Good Essays

    both have the same function‚ they have different characteristics. “BHA is a mixture of the isomers 3-tert-butyl-4-hydroxyanisole and 2-tert-butyl-4-hydroxyanisole‚ also known as BOA.” The molecular formula of BHA is C11H16O2. BHA can be a yellow tainted or white waxy solid and can have an aromatic odor. BHT “also known as 3‚ 5-di-tert-butyl-4-hydroxytoluene; methyl-di-tert-butylphenol; 2‚ 6-di-tert-butyl-para-cresol‚” has a molecular formula of C15H240. BHT physically looks like a white powder. Even

    Premium Nutrition Food preservation Fat

    • 2156 Words
    • 9 Pages
    Good Essays
  • Better Essays

    Chemistry Abstract This experiment was performed to determine the rate constant k‚ for hydrolysis of tertiary butyl chloride to tertiary butanol. The solvent system for this reaction is 45% isopropyl alcohol and 55% water. The rate of hydrolysis of t-butyl chloride is measured by the decrease in the concentration of this reagent with time. The rate of decomposition of t-butyl chloride must be equal to the rate of formation of hydrochloric acid. The rate of hydrochloric acid formation was measured

    Premium Chemical reaction Chemistry Reaction rate

    • 840 Words
    • 4 Pages
    Better Essays
  • Better Essays

    Solid C Synthesis

    • 1956 Words
    • 8 Pages

    the percentage purity of solid C was found to be 6.01%.  The melting point range of purified solid C was 117.0 – 119.0C while the boiling point of liquid C was found to be 117C.  The identity of solid C and liquid C was found to be benzoic acid and butyl acetate respectively. INTRODUCTION The isolation of individual or groups of compounds can be accomplished

    Premium Solvent Liquid Solubility

    • 1956 Words
    • 8 Pages
    Better Essays
  • Good Essays

    phenols

    • 2109 Words
    • 9 Pages

    Synthesis of Phenols You can prepare phenols in large quantities by the pyrolysis of the sodium salt of benzene sulfonic acid‚ by the Dow process‚ and by the air oxidation of cumene. Each of these processes is described below. You can also prepare small amounts of phenol by the peroxide oxidation of phenylboronic acid and the hydrolysis of diazonium salts. Pyrolysis of sodium benzene sulfonate In this process‚ benzene sulfonic acid is reacted with aqueous sodium hydroxide. The resulting salt

    Premium Oxygen Sodium hydroxide Alcohol

    • 2109 Words
    • 9 Pages
    Good Essays
  • Satisfactory Essays

    Spectra Analysis Organic Chemistry Lab‚ CHEM 369 The University of Tennessee‚ Knoxville Dr. Smith Spectra 1: tert-butyl cyanoacetate Molecular formula: 141/13 = 10 R 11 => C10H10+11 => C10H21 C10H21NO2 – C3H10 = C7H11NO2 DBE: 2(#C - #H/2 - #X/2 + #N + 2)/2 =2(7 – 11/2 – 0/2 + 1 + 2)/2 = 3=> 1 double bond and 1 triple bond Mass spectrum table: m/z fragment |40

    Premium Oxygen Chemical bond Carbonyl

    • 844 Words
    • 4 Pages
    Satisfactory Essays
Page 1 10 11 12 13 14 15 16 17 50