Jubenal Garcia
MAT222: Intermediate Algebra (GSQ1433A)
Instructor Linda Seeger
August 19, 2014
Solving Proportions
This week I learned about solving proportions. Rightfully so, on this assignment I have to prove or show what I’ve learned and retained by solving two problems. In this essay I will attempt to solve two problems from our textbook, the first one is problem 56 located on page 437 and the second one is problem 10 located on page 444 of our Elementary and Intermediate Algebra textbook. During this process I will incorporate the four math vocabulary words required, which are extraneous, proportion, cross multiply, and extreme-means which will be in bold.
Problem number 56 located on page 437 states and asks the following about bear population. “To estimate the size of the bear population on the Keweenaw Peninsula, conservationist captured, tagged, and released 50 bears. One year later, random sample of 100 bears included only 2 tagged bears. What is the conservationist’s estimate of the size of the bear population?” (Dogupolski, 2012). Since this is a ratio equation I will use b for the variable, b equaling the bear population which is what we need to find. …show more content…
Then I cross multiply the extreme-means property as shown below.
2*b=100*50
2b=5000
Because we want to solve for b I had to isolate it by dividing both sides of the proportion by 2. This gave me the answer of 2500. Keep in mind that since the denominator was not zero this equation does not merit to be considers extraneous.
2b=2500
This is the estimated size of the bear population according to