8.04 Law’s and Trials of the 1920’s 1. After reading about the subject‚ define the word "Prohibition" as it pertains to the 18th amendment. Prohibition in the United States was a measure designed to reduce drinking by eliminating the businesses that manufactured‚ distributed‚ and sold alcoholic beverages. The Eighteenth Amendment to the U.S. Constitution took away license to do business from the brewers‚ distillers‚ vintners‚ and the wholesale and retail sellers of alcoholic beverages. 2
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Fe(NO3)2(aq)+NaOH(aq) → Fe(OH)3(s)+ NO-3(aq)+Na+(aq) • Cu(NO3)2(aq)+NaOH(aq) → Cu(OH)2(s)+ NO-3(aq)+Na+(aq • Ni(NO3)2(aq)+NaOH(aq) → Ni(OH)2(s)+ NO-3(aq)+Na+(aq) • Al(NO3)2 (aq)+NaOH(aq) →Al(OH)(s)+ NO3-(aq)+Na+(aq) • Al(NO3)2 (aq)+NH4OH(aq) →Al(NH4)6+ (s)+ NO3-(aq)+Na+(aq) • Mn(NO3)2 (aq)+NaOH(aq) →Mn(OH)2(s)+ NO3-(aq) +Na+(aq) • Pb(NO3)2 (aq)+H2S(aq)↔PbS2(s)+ S2-2(g)+NO3-(aq) • Ag(NO3) (aq)+H2S(aq)↔ AgS2(s)+ S2-2(g)+NO3-(aq) • Ba(NO3) (aq)+H2S(aq)↔No reaction existed • Fe(NO3)2(aq)+H2S(aq)↔ Fe2S3(s)+ S2-2(g)+NO3-(aq)
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BU1008 Marketing Fundamentals – SP51 JCUS: In-class Case Presentation (Tutorial - Group) and Written Case Study (Individual) |Session/ Week |Content |Readings |Case Study |Case Study Questions to address in in-class presentation (group) and |Additional In-Class Tutorial Activities | | | | | |written assignment (Individual)
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Player Manual for Beer game Last Modified Jan 7‚ 2011 Game Link: http://davinci.tamu.edu/beergame/ Objective of the Game: Is to satisfy the demand of the customer‚ while keeping the cost low. There is a cost for holding inventory and a cost for not satisfying demand (backorder). The demand for the product remains until it is satisfied i.e. backorder persists until it is fulfilled. Each player would be given an information card as shown below‚ The information card contains details regarding
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06.03 Calorimetry: Lab Report Procedure: Part II: Determining the Specific Heat of an Unknown Metal Data and Observations: Part I: Determining the Specific Heat of a Known Metal Metal: Aluminum Zinc Iron Copper Mass of metal 27.776g 41.664g 34.720g 41.664g Volume of water in the calorimeter 26.0mL 26.0mL 26.0mL 26.0mL Initial temperature of water in calorimeter 25.3 °C 25.3 °C 25.3 °C 25.3 °C Temperature of hot water and metal in hot water bath 100.5 °C 100.5 °C 100
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Determining the Specific Heat of an Unknown Metal Objective: To determine the specific heat of an unknown metal through the use of a calorimeter. Background: The specific heat of any substance represents the quantity of heat energy in joules required to heat one gram of the substances by one °C. The specific heat of a substance is dependent upon the temperature; this means that there is a temperature range for which the specific heat of a substance applies. For metals and metallic substances
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Results : Calculation : Part A Molecular weight of 1M of NaOH = 23g/mol + 16g/mol + 1g/mol = 40g/mol 1M = 40g/mol dissolved in 1L and 20g dissolved in 500ml 20g of NaOH was used to prepare 500ml of 1M NaOH. Part B Molecular weight of 1M of HCl = 35.5g/mol + 1g/mol = 36.5g/mol Specific gravity = 1.19kg/L 37% HC1 × 1.19kg/L = 0.44kg/L Convert w/v to mol/v = = 12mol/L = (12mol/L) = (1M)250ml = 20.83ml ≈ 21ml 21ml of concentrated HC1 is used to prepare 250ml of 1M of HC1. Part C For 0.1N of NaOH
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Figure 1: Titration curve of 0.160 grams of an unknown diprotic acid that was dissociated in distilled water. Shown is the pH versus the volume in milliliters of 0.1 M NaOH‚ a strong base‚ added to the solution. The initial pH reading of the solution was a pH of 2.60. Although the pH of the ½ equivalence point was unknown‚ it could be estimated by halving the volume of NaOH used at the first equivalence point. At the first equivalence point‚ 13.63 milliliters of NaOH had been added to the unknown
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Question # 1: You are titrating 50 ml. of nitrous acid with sodium hydroxide (0.15 M). Equivalence is reached at 22.0 ml of NaOH delivered. Calculate the pH of the solution in the flask: a- before the beginning of the titration - after the delivery of 5 ml. of titrant b- at half-equivalence c-at equivalence d-after delivery of 23 ml. of titrant Part A) Reaction is: HNO2 + OH- NO2- + H2O Ka for Nitrous acid = 7.2E-4 Kw = Ka*Lb Kb = 1.0E-14/7.2E-4 Kb = 1.38E-11 Moles of base:
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Case Analysis: 961 Beer: Launching A Lebanese Brewing Company Introduction 961 Beer has a fascinating history which illustrates to aspiring entrepreneurs that with hard work and determination‚ even crazy business ideas are able to succeed. At a time when building were being destroyed and the city of Beirut‚ Lebanon was in shambles‚ the founders of 961 Beer decided to move forward with founding Lebanon’s first craft brewing company – a surprising fact because this region of the world begin the tradition
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