Mathematics Volume of Solids Formulae for Volume of Solids Cube | Cuboid | Triangular Prism | Cylinder | Cone | Pyramid | Sphere | AnyPrism | s3 | lwh | ½bhl | Πr2h | 1/3πr2h | 1/3Ah | 4/3πr3 | Ah | A = area of the base of the figure s = length of a side of the figure l = length of the figure w = width of the figure h = height of the figure π = 22/7 or 3.14 1. Compute the volume of a cube with side 7cm. Volume of cube: s3 s = 7cm s3 = (7cm x 7cm x 7cm) = 343cm3 2. Compute
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blades‚ potato pieces‚ paper towels‚ iodine Purpose: to identify why cells are so small. Hypothesis: Make a statement as to which potato cubes will diffuse the closer to the center of a cell (small‚ medium‚ large. __________________________________________________________________________________________________________________________________________________________________________ Dimensions For Experiment 3 Cubes with sizes A) 0.5 cm B) 1.0 cm C) 2.0 cm Experimental Evidence:
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In Parts A and C‚ the relationship between surface area and volume was investigated. Plasticine was formed into a cube and a sphere; both shapes were cut in half. It was found that plasticine volume should not vary‚ two halves have a greater surface area than a whole‚ and cubes have a greater surface area than spheres of the same volume. In Part B‚ the relationship between diffusion and surface area to volume ratio was investigated. Three agar-phenolphthalein-sodium hydroxide cubes of different sizes
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AREA (i) The area of a rhombus is equal to the area of a triangle whose base and the corresponding altitude are 24.8 cm and 16.5 cm respectively. If one of the diagonal of the rhombus is 22 cm‚ find the length of the other diagonal. (ii) The floor of a rectangular hall has a perimeter 250m. If the cost of paining the four walls at the rate of Rs 10 per m2 is Rs 1500. Find the height of the hall. (iii) A room is half as long again as it is broad. The cost of carpeting the room at Rs
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Investigating Ratios of Areas and Volumes In this portfolio‚ I will be investigating the ratios of the areas and volumes formed from a curve in the form y = xn between two arbitrary parameters x = a and x = b‚ such that a < b. This will be done by using integration to find the area under the curve or volume of revolution about an axis. The two areas that will be compared will be labeled ‘A’ and ‘B’ (see figure A). In order to prove or disprove my conjectures‚ several different values for n will
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Background Research 3-4 Experiment Hypothesis 5 Variables 5 Equipment 5 Risk Assessment 5 Method 6 Results 6 Analysis/Discussion 7 Conclusion 8 Acknowledgments/Bibliography 8 Table of Contents Background Research As an object becomes bigger its surface area and volume increases but the surface area to volume ratio decreases‚ this is because volume increases quicker than the surface area; as volume is three dimensional. This concept applies to cells and reaction rate because cells need to absorb their
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Surface area Surface area is the measure of how much exposed area a solid object has‚ expressed in square units. Mathematical description of the surface area is considerably more involved than the definition of arc length of a curve. For polyhedra (objects with flat polygonal faces) the surface area is the sum of the areas of its faces. Smooth surfaces‚ such as a sphere‚ are assigned surface area using their representation as parametric surfaces. This definition of the surface area is based on methods
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Biology Lab Report BY: Michael Ryan Pranata 11C | Background: As heat is a form of thermal energy‚ they tend to have the behavior of reaching a thermal equilibrium. This means that when two bodies of different temperatures come in contact with each other‚ the hotter ones will transfer heat particles to the body with a colder temperature‚ with an aim to reach this “thermal equilibrium”‚ whatever the temperature may be. The larger the surface area‚ means there can be more “paths” from the
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Intro: Surface Area and Volume Multiple Choice Identify the choice that best completes the statement or answers the question. Find the surface area of the space figure represented by the net. ____ 1. 12 in. 4 in. 6 in. 4 in. 4 in. 6 in. a. 288 in.2 ____ 2. b. 144 in.2 c. 240 in.2 d. 288 in.2 5 cm 5 cm 7 cm 8 cm 4 cm ____ a. 124 cm2 b. 110 cm2 c. 150 cm2 d. 164 cm2 3. Find the surface area of the cylinder. Use a calculator. Round to the nearest tenth. 4m 3m a
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relationship between surface area : volume ratio and heat loss. INTRODUCTION: The aim of this experiment is to investigate and find the relationship between heat loss (of water) and surface area to volume ratio of animals. To investigate this‚ we are going to use three flasks of different volume (as the equivalent the animals) and thus different surface areas filled with water. BACKGROUND: Surface Area : Volume Ratios We will be using the following formula for calculating SA:Vol ratios: SA : Vol Vol
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