Angle HAB = 72° B F I 72˚ (a) What is the size of angle CBI? (b) The bar BH bisects the angle ABI. (i) (c) 2. G H A (1 mark) What is the size of angle IBH? (1 mark) What is the size of angle FHG? (1 mark) Name a triangle which is congruent to triangle CBI. (1 mark) The sloping sides of a flower bowl are part of a cone as shown. The radius of the top of the bowl is 10 cm and the radius of the bottom of the bowl is 5 cm. The height of the full cone is 24 cm. Not to scale 10 cm
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3 A tent has a groundsheet as its horizontal base. The shape of the tent is a triangular prism of length 8 metres‚ with two identical half right-circular cones‚ one at each end. The vertical cross-section of the prism is an isosceles triangle of height 2.4 metres and base 3.6 metres. (a) Calculate the area of the groundsheet. Give
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polynomial is : 4. The remainder when a. 1 b. c. d. is divided by is 5. Two sides of a triangle are of lengths 7 cm and 3.5 cm. The length of the 3rd side cannot be a. 4.1 cm b. 3.4 cm c. 3.8 cm d. 3.6 cm Copyright © 2013 Learnhive Education Pvt. Ltd. Learnhive Education Pvt. Ltd. www.learnhive.com 6. If one angle of a triangle is equal to the sum of other two angles‚ then the triangle is a. Obtuse b. Equilateral c. Isosceles d. Right 7. the angle POB equals a. b. c. d. 54 48
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Assignments in Mathematics Class IX (Term 2) 8. QUADRILATERALS IMPORTANT TERMS‚ DEFINITIONS AND RESULTS l l Sum of the angles of a quadrilateral is 360°. A diagonal of a parallelogram divides it into two congruent triangles. In a parallelogram‚ (i) opposite sides are equal (ii) opposite angles are equal (iii) diagonals bisect each other A quadrilateral is a parallelogram‚ if (i) opposite sides are equal or (ii) opposite angles are equal or (iii) diagonals bisect each other or (iv) a pair of
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In mathematics‚ the Pythagorean Theorem — or Pythagoras’ theorem — is a relation in Euclidean geometry among the three sides of a right triangle (right-angled triangle). In terms of areas‚ it states: In any right-angled triangle‚ the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares whose sides are the two legs (the two sides that meet at a right angle). The theorem can be written as an equation relating the lengths
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some new found knowledge regarding triangles and quadrilaterals. Prior to this video‚ I was unfamiliar with the term SSS congruence. This term means that two triangles‚ which have the exact length of sides‚ are congruent. This is a unique characteristic that holds true to only triangles. This feature makes triangles rigid. This term means that a triangle’s sides cannot be compromised. For example‚ if three side lengths compose a triangle‚ there’s only one triangle that can be formed with the lengths
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_______ a) Sector b) Segment c) Semicircle d) Triangle _____ 2. The line that intersects the circle at two distinct points is called _____ a) Tangent b) Segment c) Secant d) Ray _____ 3. The angle whose vertex lies on the circle and whose sides are two chords is said to be ____ a) Central b) Circumscribed c) Dihedral d) Inscribed _____ 4. The region bounded by two concentric circles is ______ a) An annulus b) A sector c) A segment d) A right triangle _____ 5. A dodecagon is a polygon of ____ sides
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mirror to the peak are congruent. Use what you have learned about triangles‚ the mirror‚ Tyler‚ and the peak to find the height of the peak. Defining Your Triangles 1. Which peak did you select? (1 point) Tyler will climb peak __________. 2. In the drawing below‚ label the distances given for the peak you chose. (3 points: 1 point for each correct distance) 3. According to the information given‚ what can you determine about the triangles formed by Tyler‚ the mirror
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points on a coordinate plane and apply their leaning to find the distance between 2 perpendicular lines on a coordinate plane (Glencoe-Geometry 3.6 Perpendiculars and Distance)‚ transformations in the coordinate plane (Glencoe-Geometry 4.3 Congruent Triangles)‚ SSS on the coordinate plane (Glencoe-Geometry 4.4 Proving Congruence –SSS‚ SAS) and The Distance Formula (Glencoe-Algebra 1 11.5 The Distance Formula). Materials / Equipments: Computers‚ LCD projectors for demonstration‚ virtual manipulative
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information to be manipulated too create two isosceles triangles. The first triangle and the one that is given‚ ∆OPA is an isosceles triangle therefore it can be concluded‚ thanks to the Isosceles Triangle Theorem that angle O and A are congruent to each other in this triangle. ∆OPA is not the only triangle that can be created‚ ∆OP’A is the second triangle created with a radius from C2. Therefore ∆OP’A is also an isosceles triangle. Now in both the triangles stated above‚ they share a common angle‚ O. With
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