ENGG250 MATERIALS ASSIGNMENT 1 20 marks DUE: 20 MARCH 2015 These are the sort of questions you can expect in the Class Test on 23 March. Completing this assignment should therefore be considered part of your preparation for the Class Test. (The Class Test will cover more material than the assignment). When you have completed the questions‚ make an electronic file from your answers (you can put together an electronic file‚ or scan your handwritten copy – as long as it is legible). Create a cover
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. Student Exploration: Graphing Skills Vocabulary: bar graph‚ line graph‚ negative relationship‚ pie chart‚ positive relationship‚ scale‚ scatter plot‚ variable Prior Knowledge Questions (Do these BEFORE using the Gizmo.) 1. Four kinds of graphs are shown in this Gizmo. Circle the kinds you have seen before. [pic] [pic] [pic] [pic] Bar graph Line graph Pie chart Scatter plot 2. Where have you seen graphs used? Graphs are used everywhere.
Free Chart Bar chart Pie chart
The Vector equation of a plane To find the vector equation of a plane a point on the plane and two different direction vectors are required. The equation is defined as: where a is the point on the plane and b and c are the vectors. This equation can then be written as: The Cartesian equation of a plane The cartesian equation of the plane is easier to use. The equation is defined as: One of the advantages to writing the equation in cartesian form is that we can easily find the normal
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Problem 705 Determine the centroid of the shaded area shown in Fig. P-705‚ which is bounded by the x-axis‚ the line x = a and the parabola y2 = kx. Solution 705 HideClick here to show or hide the solution At (a‚ b) Thus‚ → equation of parabola Differential area Area of parabola by integration Location of centroid from the y-axis (x-intercept of centroid) answer Location of centroid from the x-axis (y-intercept
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2-Variable Inequality Here is an example of a problem very similar to the one in the Week Three Assignment: Catskills Hammock Company can obtain at most 2000 yards of striped canvas for making its full size and chair size hammocks. A full size hammock requires 10 yards of canvas and the chair size requires 5 yards of canvas. Write an inequality that limits the number of striped hammocks of each type which can be made. (b) First I must define what variables I will be using in my inequality
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Problem Statement: A spiralateral is a sequence of line segments that form a spiral like shape. To draw one you simply choose a starting point‚ and draw a line the number of units that’s first in your sequence. Always draw the first segment towards the top of your paper. Then make a clockwise 90 degree turn and draw a segment that is as long as the second number in your sequence. Continue to complete your sequence. Some spiralaterals end at their starting point where as others have no end‚ this
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find the distance between two points on a coordinate plane and apply their leaning to find the distance between 2 perpendicular lines on a coordinate plane (Glencoe-Geometry 3.6 Perpendiculars and Distance)‚ transformations in the coordinate plane (Glencoe-Geometry 4.3 Congruent Triangles)‚ SSS on the coordinate plane (Glencoe-Geometry 4.4 Proving Congruence –SSS‚ SAS) and The Distance Formula (Glencoe-Algebra 1 11.5 The Distance Formula). Materials / Equipments: Computers‚ LCD projectors for demonstration
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"Geometry Of Warp Shed " has been carried out by PARTH PARMAR under my guidance in fulfillment of the Degree of Master of Engineering in Textile Engineering (2nd Semester) of Gujarat Technological University‚ Ahmedabad during the academic year 2013-14. Guided By: PROF. A. I . THAKKAR Head of the Department ABSTRACT ﾢ Shed Geometry & Different Possible Shed Geometries. ﾢ Elements Of Shed Geometry. ﾢ Shed Geometry Classification:-
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Report CSD_ ’rlt_n.05t‚ Aug .. ’ 19931 Abstract We report on the development of a two-dimensional geometric COllstraint solver. The solver is a major component of a lIew generation of CAD systems that we are developing based on a high-level geometry representation. The solver uses a graph-reduction directed algebraic approach‚ and achieves interactive speed. We describe the architecture of the solver and its basic capabilities. Theil) we discuss ill detail holV to extend the scope of the solver
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SPM(U) 2006 : http://mathsmozac.blogspot.com Section A [52 marks] Answer all questions in this section. 1 The Venn diagram in the answer space shows sets P‚ Q and R such that the universal set‚ ξ = P ∪ Q ∪ R . On the diagram in the answer space‚ shade (a) the set P ∪ R ‚ (b) the set (P ∩ R ) ∪ Q ’ . [3 marks] Answer: (a) P Q R (b) P R Q 2 Diagram 1 shows a solid cuboid. A cone is removed from this solid. 12 cm 10 cm 15 cm DIAGRAM 1 The diameter of the base of the cone is 7 cm
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