Catalysts In Chemical Reactions‚ Their Importance In Industry‚ Problems and New Developments OXFORD AND CAMBRIDGE SCHOOLS EXAMINATION BOARD. General Certificate Examination - Advanced Level Chemistry (Salters’) - Paper 3 mock. ROBERT TAYLOR U6JW. A Catalyst is a substance that alters the rate of a reaction. The catalyst remains unchanged at the end of the reaction. The process is called catalysis. In this report I aim going to explain the role of catalysts in chemical reactions and their importance
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affecting the rate of a chemical reaction. Introduction: In my coursework I will be mainly concentrating on the reaction between dilute hydrochloric acid with marble chips (calcium carbonate). Calcium carbonate (marble chips) + hydrochloric acid ==> calcium chloride + water + carbon dioxide CaCO3(s) + 2HCl (aq) ==> CaCl2 (aq) + H2O (l) + CO2 (g) Aim: The aim of the experiment is to investigate how the concentration of hydrochloric acid affects the rate of reaction with marble chips‚ i.e.
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Factors Influencing Rate of Reaction Aim To investigate several effects believed to influence rate of reaction‚ concentration of a substance and temperature‚ and observe the effects. Hypothesis Concentration and temperature will both increase the rate of reaction in accordance with collision theory. Introduction The reaction rate or rate of reaction for a reactant or product in any given reaction can be defined as the speed with which a reaction occurs. For example‚ the oxidation of iron
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this reaction at 25(C. A. 1020 kJ/mol B. -1.22 ( 103 kJ/mol C. 2.00 ( 103 kJ/mol D. -1.42 ( 103 kJ/mol E. -198 kJ/mol 2. For the reaction H2(g) + S(s) ( H2S(g)‚ (H( = -20.2 kJ/mol and (S( = +43.1 J/K·mol. Which of these statements is true? A. The reaction is only spontaneous at low temperatures. B. The reaction is spontaneous at all temperatures. C. (G( becomes less favorable as temperature increases. D. The reaction is spontaneous
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Shawn Dubbs Lab 1 The Mole Concept of and the Chemical Formula of a Hydrate Abstract: The objective of this lab was to conduct an experiment to analyze the molar components in alum. This was conducted by heating the alum till the water had evaporated and then determining the number of moles for each component. Then using the these amounts to figure out the empirical formula for alum. Results: In order to determine how much of each separate component a total mass was taken before hand for
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13 – Chemical Kinetics Page 1 of 13 Acknowledgements: Many of the images are adopted from Tro’s textbook‚ the only purpose of which is to enhance student learning. Key terms‚ concepts‚ skills: Refer to pp 599 – 601. Review questions: 3 – 24. Suggested problems: 25‚ 27‚ 33‚ 39‚ 43‚ 53‚ 57‚ 59‚ 69‚ 73‚ 75‚ 81‚ 93‚ 103. 13.1 & 2 Introduction to the Rate of a Chemical Reaction • kinetics is the study of the factors that affect the speed of a reaction and the mechanism by which a reaction proceeds
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CHEMISTRY TOPIC 11 CHEMICAL CALCULATIONS CHEMICAL CALCULATIONS INTRODUCTION The first part of this ‘Chemical Calculations’ topic will help us to work out QUANTITIES involved in a reaction; For example‚ a manufacturer might want to know‚ How much ammonia will I produce from 20 tonnes of nitrogen in the Haber Process? To do these calculations you will need to be familiar with the term Ar (relative atomic mass)‚ Mr‚ Molar mass and Mole. Relative Atomic Mass
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Name Mole Lab Exercises I. Pre Lab Questions Answer the following questions. (Hint: Your textbook will be helpful.) 1. ‘s number is the number of carbon atoms that are present in 12 g of 12C. 2. How many molecules of a compound are in one mole of that compound? 3. Write out the formula for finding percent by mass. 4. Write out the formula for finding Molarity. 5. The Formula Weight of a compound is equal to mole of that compound.
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[ print page ] 04.05 Chemical Reactions: Combustion: Lab Worksheet and Rubric Before You Begin: You may either copy and paste this document into a word processing program of your choice or print this page. Procedure: 1. Iron (IIII) and copper (II) sulfate solution Fill a small test tube halfway with copper (II) sulfate solution. Add a 2.0 gram iron rod to the solution and observe the reaction. 2. Lead (II) nitrate and potassium iodide solutions Pour about 2.0 mL of lead (II) nitrate into
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%abundance (1) +Ir (2) x %abundance (2) +and so on/100 The isotopes are found in the ratio 1.339:1.000 %abundance for isotope=1.000/1.339+1.000 6. Mr= the sum of the number of atoms x Ar: relative formula mass(for molecule and non-molecule substances)/relative molecular mass(only for molecular substances) 7. n=N/NA(6.02x1023)=m/M If the question is calculate the % composition of each element in BaCo3‚ assume we have 1 mole of BaCo3‚ we have M(Baco3)g=137.3+12.0+3x16.0=197.3g/mol so we have 197.3g Baco3
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