Key Questions Unit Two Lesson Five 91/92= 99 % 15. a) 2‚3‚5-trimethylhexane b)3-ethyl-2‚4‚6‚7-tetramethyloctane c)2‚2-dimethylpentane 6 16. a)3-ethyl-3-methylhexane CH3 | CH3-CH2-CH-CH2-CH2-CH3 | CH2CH3 b) 1-ethyl-3-propylcyclohexane c) 2‚4-dimethylheptane CH3-CH-CH2-CH-CH2-CH2-CH3
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However‚ these are not the concern for the food technologist. Autoxidation (atmospheric oxidation) under the mild processing and storage conditions of the food industry is of utmost importance due to the resultant malodor- and malflavor-producing aldehydes and ketones. The oxidation of the highly unsaturated fats resulting in polymeric end products and
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SYLLABUS FOR ENTRANCE TEST 2012 UNIVERSITY OF HEALTH SCIENCES LAHORE‚ PAKISTAN STRUCTURE OF ENTRANCE TEST PAPER 2012 Sr.# Subject No. of Questions 1. PHYSICS 44 2. CHEMISTRY 58 3. ENGLISH 30 4. BIOLOGY 88 TOTAL 220 CONTENTS PHYSICS Syllabus TOS Self Test Questions CHEMISTRY Syllabus TOS Self Test Questions ENGLISH Syllabus Self Test Questions BIOLOGY Syllabus TOS Self Test Questions PAGE# 1-5 6 7-9 10-21 22 23-28 29-34 35-36 37-44 45 46-51 PHYSICS
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Galactose etc. * Disaccharides include Sucrose‚ Maltose‚ and Lactose etc. * Polysaccharides include Starch‚ Glycogen‚ Cellulose and Chitin. * Aldehydes (–CHO) and ketones (= CO) are active groups or functional groups in carbohydrates. Carbohydrates contain many hydroxyl groups as well * Monosaccharidecontain the free aldehyde or
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this experiment‚ Drosophila melanogaster‚ Drosophila virilis‚ as well as a marker strain (mutant strain of D. melanogaster) were used to examine the genetic variation. Electrophoresis followed by the staining of the proteins will cause the enzymes‚ aldehyde oxidase‚ alcohol dehydrogenase‚ and malate dehydrogenase‚ to become visible‚ appearing as a set of different banding patterns. The banding patterns will dependent on the molecular form of the enzyme‚ indicating the genetic variation that can exist
Free Protein Gene DNA
combination of carbon dioxide and water molecules. The carbohydrates contain two specific functional groups in which are the hydroxyl groups and carbonyl groups. In the carbohydrates‚ if the sugar contains aldehyde group it called reducing sugar and called non-reducing sugar if didn’t have the aldehyde group. The Benedict’s test shows us which sugars are reducing or non-reducing. Benedict’s reagent‚ which contains Cu2+ ions in alkaline solution with sodium citrate added to keep the cupric ions in solution
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reactivity they are used in different situations. NaBH4 can be used in alcoholic solvent while LiAlH4 can’t be because it will deprotonate and produce H2. Also‚ LiAlH4 can reduce ketones‚ aldehydes‚ carboxylic acids as well as esters. In contrast‚ NaBH4’s lower reactivity causes it only effective at reducing ketones‚ and aldehydes. In this lab NaBH4 will be used‚ an example of such a reaction using NaBH4 as a reducing agent
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enough or some of the precipitate washed away with the solvent. By performing a series of calculations‚ the molecular weight of the unknown was determined. The unknown carboxylic acid was titrated with 0.1 M NaOH. The solid was synthesized from the Grignard reaction. Deionized water and ethanol were both used to dissolve the solid. Then 2-3 drops of phenolphthalein were added to the Erlenmeyer flask as the indicator. Under acidic conditions from the unknown carboxylic acid‚ the indicator did not change
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during the Benedict’s Test. Reducing sugar have contain free aldehyde or ketone group and have the ability to reduce copper(II) ions to copper (I) ions during the Benedict’s Test. All monosaccharides are reducing sugars while only some dissacharides are reducing sugar. Examples of reducing sugar are: Monosaccharides Glucose Fructose Galactose Dissacharides Lactose maltose Non-reducing sugars do not contain have free aldehyde groups and upon testing with Benedict’s solution will not reduce
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replace a less electronegative atom with a more electronegative atom; replace a bond to hydrogen with a bond to oxygen; or replacing a single bond with a double bond by the loss of hydrogen. Oxidations are very convenient when trying to synthesize an aldehyde or ketone for this reason. Since there is less electron density around a reactive carbon center‚ the oxidation n of the carbon will be more positive. Usually a more electronegative atom such as a halogen‚ nitrogen‚ or oxygen replaces hydrogen bonded
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